Explanation
We know $$A=P{ \left[ 1+\dfrac { R }{ 100 } \right] }^{ n }$$
$$ 2226.05= 2000{ \left[ 1+\dfrac { R }{ 100 } \right] }^{ 2 }\\ \dfrac { 2226.05 }{ 2000 } = { \left[ 1+\dfrac { R }{ 100 } \right] }^{ 2 }\\1.113025 ={ \left[ 1+\dfrac { R }{ 100 } \right] }^{ 2 }\\ 1.055= { \left[ 1+\dfrac { R }{ 100 } \right] }\\ 1.055 =\dfrac { 100+R }{ 100 } \\ 105.5= 100+R\\ R= 5.5\%$$
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