Explanation
$$\dfrac{x+1}{\sqrt{x^{2}-5 x+6}}$$
$$x^{2}-5 x+6>0$$
$$x^{2}-3 x-2 x+6>0$$
$$x(x-3)-2(x-3)>0$$
$$(x-3)(x-2)>0$$
$$x \in[-\infty, 2) \cup(3, \infty)$$
Domain of
$$x+1 \in R$$
$$\therefore$$ Domain of $$\dfrac{x+1}{\sqrt{x^{2}-5 x+6}}$$ is $$R-(2,3)$$
Option $$A=R-(2,3)$$
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