Explanation
We have,
$$ \log \left( -2x \right)=2\log \left( x+1 \right) $$
$$ \Rightarrow \log \left( -2x \right)=\log {{\left( x+1 \right)}^{2}} $$
Comparing both side and we get,
$$ -2x={{\left( x+1 \right)}^{2}} $$
$$ \Rightarrow -2x={{x}^{2}}+1+2x $$
$$ \Rightarrow {{x}^{2}}+4x+1=0 $$
Using quadratic formula and we get,
$$ x=\dfrac{-4\pm \sqrt{16-4\times 1\times 1}}{2\times 1} $$
$$ x=\dfrac{-4\pm \sqrt{12}}{2} $$
$$ x=\dfrac{-4\pm \sqrt{2\times 2\times 3}}{2} $$
$$ x=\dfrac{-4\pm 2\sqrt{3}}{2} $$
$$ x=-2\pm \sqrt{3} $$
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