Explanation
Given, A=3-4i, B=9+ki, Ab-15=0
\therefore AB= (3-4i)(9+ki)
\therefore 27 + 3ki – 36i – 4ki^2-15=60
\therefore -48+3ki-36i+4k=0
Separate the real and imaginery part equal to zero, then we get the value of k,
\therefore -48 + 4k = 0, 3k – 36 = 0
\therefore -48 = -4k, 3k = 36
\therefore k = 12, k = 12
So, the value of k is 12.
Calculate \dfrac{u^3 }{ v^4}
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