Explanation
Given, $$A=3-4i, B=9+ki, Ab-15=0$$
$$\therefore AB= (3-4i)(9+ki)$$
$$\therefore 27 + 3ki – 36i – 4ki^2-15=60$$
$$\therefore -48+3ki-36i+4k=0$$
Separate the real and imaginery part equal to zero, then we get the value of $$k$$,
$$\therefore -48 + 4k = 0, 3k – 36 = 0$$
$$\therefore -48 = -4k, 3k = 36$$
$$\therefore k = 12, k = 12$$
So, the value of $$ k$$ is $$12$$.
Calculate $$\dfrac{u^3 }{ v^4}$$
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