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CBSE Questions for Class 11 Commerce Applied Mathematics Numerical Applications Quiz 12 - MCQExams.com
CBSE
Class 11 Commerce Applied Mathematics
Numerical Applications
Quiz 12
If four men working at the same rate can do
2
/
3
of a job in
40
minutes it take one man working at this rate to do
2
/
5
of the job takes how many minutes?
Report Question
0%
80
0%
88
0%
92
0%
96
0%
112
A library has
′
a
′
copies of one book,
′
b
′
copies of each of two books,
′
c
′
copies of each of three books, and single copy each of
′
d
′
. The total number of ways in which these books can be arranged in a row is
Report Question
0%
(
a
+
b
+
c
+
d
)
!
a
!
b
!
c
!
0%
(
a
+
2
b
+
3
c
+
d
)
!
a
!
(
b
!
)
2
(
c
!
)
3
0%
(
a
+
2
b
+
3
c
+
d
)
!
a
!
b
!
c
!
0%
none of these
The number of ways dividing 52 cards amongst four players equally, are
Report Question
0%
52
!
(
13
!
)
4
0%
52
!
(
13
!
)
4
4
!
0%
52
!
(
12
!
)
4
4
!
0%
None of these
Explanation
Hint:-Number of ways in which 3n diiferent things can be divided equally three people
=
(
3
n
)
!
n
!
n
!
n
!
Step:-1 Find the total number of ways
Here 52 cards are distributed among four players equally in an order so each gets 13 cards
Total number of ways dividing 52 cards amongst four players equally,are=
52
C
13
×
39
C
13
×
26
C
13
×
13
C
13
=
52
!
39
!
13
!
×
39
!
26
!
13
!
×
26
!
13
!
13
!
×
13
!
0
!
13
!
=
52
!
13
!
×
13
!
×
13
!
×
13
!
=
52
!
13
!
4
Heence the number of ways the cards can be divided equally amongst number of players=
52
!
13
!
4
If a pipe can fill a cistern in 8 hours and another pipe can empty the cistern in 10 hours, then what part of the cistern will be filled in 1 hour, if both pipes are opened simultancously?
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0%
1
40
0%
1
30
0%
1
35
0%
1
8
A pipe can fill a cistern in
12
min and another pipe can fill it in
15
min, but a third pipe can empty it in
6
min. The first two pipes are kept open for
5
min in the beginning and then the third pipe is also opened. Time taken to empty the cistern is
Report Question
0%
30 min
0%
33 min
0%
37
1
2
min
0%
45 min
A street-light is hung
20
f
t
, above the ground. An object falls freely under the gravity, starting from rest at the same height as the lamp and at a horizontal distance of
5
f
t
. from it. When the object has fallen through
16
f
t
, the speed of the shadow of the object on the ground is
Report Question
0%
12
f
t
.
/
s
e
c
0%
11
f
t
.
/
s
e
c
0%
10
f
t
.
/
s
e
c
0%
12.5
f
t
.
/
s
e
c
Four of the six numbers 1867, 1993, 2019, 2025, 2109 and 2121 have a mean ofWhat is the mean of the other two numbers.
Report Question
0%
1994
0%
2006
0%
2022
0%
2051
Two pipes fill a tank in 20 minutes and 60 minutes. A third pipe empties the same tank in 40 minutes. In how much time will the tank be filled if all three pipes are opened together?
Report Question
0%
6 min
0%
24 min
0%
30 min
0%
40 min
I
f a pipe fills a tank in 20 minutes and a pipe empties the same tank in 60 minutes. Then in how much time the tank will be filled completely if both the pipes are opened together?
Report Question
0%
10 minutes
0%
70 minutes
0%
40 minutes
0%
30 minutes
The mean of series
x
1
,
x
2
,
x
3
,
.
.
.
.
.
.
.
.
x
n
i
s
ˉ
x
,
then mean of the series
x
1
,
+
2
i
,
i
=
1
,
2
,
3
,
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
n
will be
Report Question
0%
ˉ
x
+
n
0%
ˉ
x
+
n
+
1
0%
ˉ
x
+
2
0%
ˉ
x
+
2
n
If
16
men can build a wall of
52
m long in
25
days working for
8
hours a day, in how many days can
64
men build a similar wall of
260
m long working for
10
hours a day?
Report Question
0%
35
0%
65
0%
40
0%
25
Explanation
Solve:- on considering first situation
no. of men
(
m
1
)
=
16
no. of
days
(
D
1
)
=
25
no. of hours work daily
=
8
hours
- length of wall
=
52
m
and in second case by using similar
notation we get,
M
2
=
64
D
2
=
?
no. of hour
=
10
hours
length of wall
=
260
m
We know that, no. of men
α
work
no. of hours
α
work
no. of days
α
work
So,
M
1
×
D
1
×
H
1
l
1
=
M
2
×
D
2
×
H
2
l
2
⇒
16
×
25
×
8
52
=
64
×
D
2
×
10
260
⇒
D
2
=
25
Days
H
1
,
H
2
Denotes hours in first and second
case. Similarly
l
1
and
l
2
represent length
A and
B
can do a job together in
7
days
A
is
1
3
4
times as efficient as
B
The same
job can be done by
A
alone in
Report Question
0%
9
1
3
d
a
y
s
0%
11
d
a
y
s
0%
12
1
4
d
a
y
s
0%
16
1
2
d
a
y
s
Explanation
A
and
B
can do a job together in 7 days
A
is
1
3
4
times as efficient as
B
⇒
A
:
B
=∣
3
4
:
1
=
7
:
4
A
=
7
x
,
B
=
4
x
A
⋅
T
⋅
Q
_
A
+
B
=
1
7
7
x
+
4
x
=
1
7
⇒
x
=
1
77
∴
Hence, (B) is the correct option.
In a conference hall 10 executive are to be seated on 10 chairs placed left to right. Executive
E_1
wants to sit to the right of
E_2
Also,
E_4
wants to sit the left of
E_1
and
E_5
wants to sits to the left of ways
E_4
Number of ways the executives can be seated on the 10 chairs, is
Report Question
0%
\dfrac{10!}{4!}
0%
\dfrac{10!}{3}
0%
10!
0%
3 \times \dfrac{10!}{4!}
Number of positive integers
n ,
less than
17 ,
for which
n ! + ( n + 1 ) ! + ( n + 2 ) !
is an integral multiple of
49
is
Report Question
0%
2
0%
5
0%
7
0%
9
4
men and
3
women finish a job in
6
days. And
5
men and
7
women can do the same job in
4
days. How long will
1
man and
1
woman take to do the work?
Report Question
0%
22\dfrac { 2 }{ 7 } days
0%
25\dfrac { 1 }{ 2 } days
0%
5\dfrac { 1 }{ 7 } days
0%
12 \dfrac { 7 }{ 22 } days
Explanation
(
4
men
+3
women)
\times 6
days
=
(
5
men
+ 7
women)
\times 4
days
24
men
+18
women
=20
men
+28
women
4
men days
=10
women days
1
men days
=2.5
women days
Total work
=24
men days
+18
women days
=20
men days
+28
women days
=78
women days
1
man
+1
women
=2.5
women
+1
women
=3.5
women can do
\dfrac{78}{3.5}=22\left(\dfrac{2}{7}\right)
days
If
m
and
n
are positive integers more than or equal to
2 , m > n ,
then
( m n ) !
is divisible by
Report Question
0%
( m ! ) ^ { n }
0%
( n ! ) ^ { m }
0%
( m + n ) !
0%
( m - n ) !
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