Explanation
Tank filled by tab A in 1 minute$$=\dfrac{1}{12}$$
Tank filled by tab B in 1 minute$$=\dfrac{1}{15}$$
Tank filled by tab A and B ib 1 minute$$=\dfrac{1}{12}+\dfrac{1}{15}=\dfrac{9}{60}$$
Pipe A and B is opened for 3 minute
Then part filled by A and B in 3 minute$$=\dfrac{9}{50}\times 3=\dfrac{9}{20}$$
Remaining part$$=1-\dfrac{9}{20}=\dfrac{11}{20}$$
Time taken by B to fill this remaining part$$=\dfrac{\cfrac{11}{20}}{\cfrac{1}{15}}$$
$$=\dfrac{11\times 15}{20}=\dfrac{33}{4}=8\cfrac{1}{4}$$
$$=8 \ min \ 15 \ s$$
A's one day's work $$= \cfrac{1}{45}$$
B's one day's work $$= \cfrac{1}{40}$$
$$\therefore (A+B)$$'s 1 day's work $$= \cfrac{1}{45} + \cfrac{1}{40} = \cfrac{8+9}{360} = \cfrac{17}{360}$$
Work done by B in 23 days $$ = \cfrac{1}{40} \times 23 = \cfrac{23}{30}$$ Remaining work $$ = 1 - \cfrac{23}{40} = \cfrac{40-23}{40} = \cfrac{17}{40}$$ $$(A+B)$$'s 1 day work $$ = \cfrac{17}{360}$$ $$ \dfrac{17}{40}$$ work done by $$(A+B)$$ in $$ 1 \times \dfrac{360}{17} \times \dfrac{17}{40} = 9 \ Days$$
Ronald work at a rate of 32 pages per 6 hrs$$=\dfrac{32}{6}=\dfrac{16}{3} pages/hr$$
Elan work at a rate of 40 pages per 5 hr$$=\dfrac{40}{4}=8 Pages/hr$$
If they work together then they work at the rate of$$=\dfrac{16}{3}+8=\dfrac{40}{3} pages/hr$$
Let t time is required them to type 110 pages then
$$\dfrac{40}{3}t=110$$
$$40t=330$$
$$t=\dfrac{330}{40}=\dfrac{33}{4}=8\dfrac{1}{4}=8 hr 15 min.$$
Ravi and Kumar are working on an assignment. Ravi takes $$6$$ hours to type $$32$$ pages on a computer, while Kumar takes $$5$$ hours to type $$40$$ pages. How much time will they take, working together on two different computers to type an assignment of $$110$$ pages?
$$A$$ works twice as fast as $$B.$$ If $$B$$ can complete a work in $$12$$ days independently, the number of days in which $$A$$ and $$B$$ can together finish the work in
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