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CBSE Questions for Class 11 Commerce Economics Presentation Of Data Quiz 5 - MCQExams.com
CBSE
Class 11 Commerce Economics
Presentation Of Data
Quiz 5
Choose the correct answer from the alternatives given.
What is the difference in the amount estimated by family on electricity bill and cell bill?
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Rs. $$1920$$
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Rs. $$4160$$
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Rs. $$6080$$
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Rs. $$8000$$
Explanation
Difference between electricity bill and cell bill $$= (19 - 6)\% = 13\%$$
So, required difference $$=13\%\ of\ 32,000 = Rs.\ 4,160$$
Which of the following is advantage of classification of data?
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It arranges and presents data in condensed and meaningful form.
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It facilitates comparison of data.
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It highlights significant features of the data at a glance.
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All of above
Year-wise production of rice, wheat and maize for the last ten years can be displayed by ________.
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simple column chart
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multiple column chart
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broken column chart
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subdivided column chart
Choose the correct answer from the alternatives given.
The family actually paid Rs. $$4672$$ on grocery. What is the difference in the amount budgeted and spent on grocery?
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Rs. $$1738$$
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Rs. $$1672$$
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Rs.$$1728$$
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Rs. $$1038$$
Explanation
Amount budgeted on grocery $$= 20\%\ of\ 32,000 =$$ Rs. $$6,400$$
S
o, required difference $$= 6,400 - 4,672 =$$ Rs. $$1,728$$
_______ is the tendency of data to increase or decrease or stagnate over a long period of tiem.
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Random variations
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Irregular variations
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Secular trend
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Data trend
A survey was made to find the type of music that a certain group of young people linked in a city. Above pie chart shows the findings of this survey.
From this pie chart answer w
hich type of music is liked by the maximum number of people?
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$$\text{Semi Classical}$$
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$$\text{Classical}$$
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$$\text{Light}$$
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$$\text{Folk}$$
Explanation
Light music is liked by $$40\%$$ people which is maximum among all the other three music types.
Hence, option $$C$$ is correct.
The data may be said to be classified 'qualitatively', when data relates to ____________.
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time or period
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character or attributes
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place, area or region
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numerical values or magnitudes
If data are classified for registration of students for Company secretary chip course region wise in Eastern, Northern, Southern, Western. It is knows as _____________________.
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chronological classification
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qualitative classification
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geographical classification
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quantitative classification
The data may be said to be classified 'chronologically', when data relates to __________________.
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time or period
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character or attributes
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place, area or region
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numerical values or magnitudes
The central angle of a sector in a pie chart cannot be more than $$ 180^0 $$
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True
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False
Explanation
The central angle in a pie chart is more than $$ 180^0 $$ , but not more than $$ 360^0 $$
The class marks in a frequency table are given to be $$5,10,15,20,25,30,35,40,45,50$$. The class limits of the first classes are
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$$3-7,7-17,13-17,17-23,23-27$$
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$$2.5-7.5,7.5-12.5,12.5-17.5,17.5-22.5,22.5-27.5$$
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$$1.5-8.5,8.5-11.5,11.5-18.5,18.5-21.5,21.5-28.5$$
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$$2-8,8-12,12-18,18-22,22-28$$
Explanation
$$2.5 - 7.5, 7.5 - 12.5, 12.5 - 17.5, 17.5 - 22.5, 22.5 - 27.5$$
Given,
$$5,10,15,20,25,30,35,40,45,50$$
the class limit is given by,
$$\dfrac{5}{2}=2.5$$
$$\dfrac{5+10}{2}=7.5$$
$$\dfrac{10+15}{2}=12.5$$
$$\dfrac{15+20}{2}=17.5$$
$$\dfrac{20+25}{2}=22.5$$
$$\dfrac{25+30}{2}=27.5$$
Data represented using circle is known as
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Bar Graph
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Histogram
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Pictograph
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Pie chart
Explanation
A pie chart represents the data in circular form.
Hence, option $$D$$ is correct.
A graph that displays data that changes continuously over periods of time is
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Bar graph
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pie chart
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Histogram
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Line graph
Explanation
The correct answer is option (d). Line graph is a way to compare and represent the data. It displays the relation among two varying quantities.
Look at the histogram and answer the following .
How many workers earn more than Rs. 850?
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7
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8
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9
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10
Explanation
From the graph, we get the following table.
$$\text{Wages (Rs.)}$$
$$\text{Number of workers}$$
800-810
3
810-820
2
820-830
1
830-840
9
840-850
5
850-860
1
860-870
3
870-880
1
880-890
1
890-900
4
The workers who earn more than $$850$$ are $$n(850-860)+n(860-870)+n(870-880)+n(880-890)+n(890-900)=1+3+1+1+4=10$$
For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are the:
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upper limits of the classes
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lower limits of the classes
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class marks of the classes
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upper limits of perceeding classes
Explanation
For drawing a frequency polygon of a continuous frequency distribution,
we draw the class marks of the classes on the abscissae and the frequency of the classes on the ordinates.
We know, class marks are the mean of lower and upper limit of the class intervals.
Hence, option $$C$$ is correct.
Class mark of a particular class is 10.5 and class size is 7, then class interval is :
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10.5 -17.5
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3.5 -10.5
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7 -17.5
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7 -14
Explanation
Class mark is the mid point of the class interval.
Class size is the upper limit minus lower limit.
Given that class mark of a class is $$10.5$$ and
class size is $$7$$
By option verification,
Opition A class mark is $$\dfrac{10.5+17.5}{2}=\dfrac{28}{2}=14$$ False
Option B
class mark is $$\dfrac{10.5+3.5}{2}=\dfrac{14}{2}=7$$ False
Option C
class mark is $$\dfrac{17.5+7}{2}=\dfrac{24.5}{2}=12.25$$ False
Option D class size is $$14-7=7$$ and
Class mark is $$\dfrac{14+7}{2}=\dfrac{21}{2}=10.5$$ True
Therefore the class interval is $$7-14$$
Class mark of class interval 60 - 70 is
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60
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70
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65
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75
Explanation
Class mark is the mid point of the class interval.
Therefore, the class mark for the interval $$60-70$$ is $$\dfrac{60+70}{2}=\dfrac{130}{2}=65$$
Find the central angle of pie chart for winter.
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$$90$$
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$$120$$
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$$150$$
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None of these
Explanation
Central Angle for Summer $$= \dfrac { 90 }{ 360 } \times 360 = 90$$ degree
Central Angle for Rainy $$= \dfrac { 120 }{ 360 } \times 360 = 120$$ degree
Central Angle for Winter $$= \dfrac { 150 }{ 360 } \times 360 = 150$$ degree
If the class marks in a frequency distribution are 19.5, 26.5, 33.5, 40.5, then the class corresponding to the class mark 33.5 is :
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16 - 23
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23-30
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30-37
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37-41
Explanation
Class mark is the mid point of the class interval.
Class size is the upper limit minus lower limit.
Given that class mark of a class is $$6.5$$ and
the class size is $$26.5-19.5=33.5-26.5=40.5-33.5=7$$
By option verification,
Opition A class mark is $$\dfrac{16+23}{2}=\dfrac{39}{2}=19.5$$ False
Option B
class mark is $$\dfrac{30+23}{2}=\dfrac{53}{2}=26.5$$ False
Option C
class mark is $$\dfrac{30+37}{2}=\dfrac{67}{2}=33.5$$ and
class size is $$37-30=7$$ True
Option D
class mark is $$\dfrac{37+41}{2}=\dfrac{78}{2}=39$$ False
Therefore the class interval is $$30-37$$
The class mark of the class 29.5 $$-$$ 30.5 is :
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30
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30.5
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31.5
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31
Explanation
Class mark is the mid point of the class interval.
Therefore, the class mark for the interval $$29.5-30.5$$ is $$\dfrac{29.5+30.5}{2}=\dfrac{60}{2}=30$$
The class mark of the class 100 $$-$$ 150:
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$$100$$
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$$125$$
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$$130$$
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$$150$$
Explanation
Class mark is the mid point of the class interval.
Therefore the class mark of the class $$100-150$$ is $$\dfrac{100+150}{2} = \dfrac{250}{2}=125$$
How much distance did the car cover during the period 7.30 a.m. to 8 a.m?
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$$20$$ km
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$$40$$ km
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$$80$$ km
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$$100$$ km
Explanation
Using the information provided in the table, we can plot the graph shown above, taking the time on the $$x-axis$$ and the distance (in km) on the $$y-axis$$.
From the above graph, we can observe that at $$7:30\ am$$, the distance traveled is $$100\space km$$ and
at $$8:00\ am$$, the distance traveled is $$120 \space km$$.
Therefore, the distance covered during
the period
$$7:30$$ and $$8:00$$ is $$120-100=20\space km$$
Hence, option A is correct.
Draw a graph for the given information with suitable scales on the axes and answer the following question.
The time when the car had covered a distance of $$100$$ km since its start is:
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$$7:00$$ am
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$$7:30$$ am
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$$ 8:00$$ am
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$$8:30$$ am
To get an interest of Rs $$280$$ per year, how much money should be deposited?
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$$2500$$
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$$3000$$
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$$3500$$
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$$400$$
Explanation
From the above graph, we can notice that, to get an interest of $$280$$ rupees per year, the money to be deposited is $$3500$$ rupees (approximately).
Use the graph to find the interest on Rs $$2500$$ for a year.
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$$Rs. 100$$
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$$Rs.200$$
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$$Rs.300$$
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$$Rs.400$$
Explanation
From the above graph, we can observe that simple interest on $$Rs. 2500$$ rupees is $$Rs. 200$$ rupees which is marked as black point in the graph.
3 weeks
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$$7cm$$
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$$8cm$$
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$$9cm$$
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$$10cm$$
Explanation
In the given graph, The dotted line represents the growth of the Plant $$A$$.
From the graph, we can observe that after $$3$$ weeks Plant $$A$$ has grown $$9\space cm$$
2 weeks
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$$7cm$$
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$$8cm$$
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$$9cm$$
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$$10cm$$
Explanation
In the given graph, The dotted line represents the growth of the Plant $$A$$.
From the graph, we can observe that after $$2$$ weeks Plant $$A$$ has grown $$7\space cm$$
During which periods did the patient's temperature showed an upward trend?
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9 a.m. to 10 a.m., 10 a.m. to 11 a.m., 2 p.m. to 3 p.m.
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9 a.m. to 10 a.m., 10.30 a.m. to 11.30 a.m., 2 p.m. to 3 p.m.
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9 a.m. to 10 a.m., 10 a.m. to 11.30 a.m., 1 p.m. to 2 p.m.
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9 a.m. to 10 a.m., 10 a.m. to 11 a.m., 1 p.m. to 2 p.m.
Explanation
Whenever there is an increase in the value of $$y - axis$$ as the time(on $$x - axis$$) passes by, there is an upward trend.
Thus, the patient shows an upward trend between $$9 am - 10 am$$, $$10 am - 11 am$$ and $$2 pm - 3 pm$$
Hence, option A is correct.
2 weeks
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$$7cm$$
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$$8cm$$
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$$9cm$$
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$$10cm$$
Explanation
In the given graph, The straight line represents the growth of the Plant $$B$$.
From the graph, we can observe that after $$2$$ weeks Plant $$B$$ has grown $$7\space cm$$
When was the patients temperature $$38.5$$ C?
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$$9$$
0%
$$10$$
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$$11$$
0%
$$12$$
Explanation
From the given graph, we can observe that the patient temperature $$38.5^0C$$ was at $$12$$ noon
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