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CBSE Questions for Class 11 Commerce Economics Presentation Of Data Quiz 8 - MCQExams.com
CBSE
Class 11 Commerce Economics
Presentation Of Data
Quiz 8
Two houses A and B were constructed at a total cost of Rs 100000 and Rs 250000 respectively The expenditure on materials is shown in the pie charts given bellow
The expenditure on B exceeds expenditure on A by :
Report Question
0%
Rs
12500
0%
Rs
15000
0%
Rs
10000
0%
Rs
22000
Explanation
Answer:-
Shaded area = Materials
Given:- Area of circle A = Total cost of construction of A = Rs
100000
π
r
1
2
=
100000
⇒
r
1
2
=
100000
π
Now expenditure on material for A = Area covered by material in circle A =
π
r
1
2
2
E
A
=
π
×
100000
2
×
π
=
50000
Similarly: Area of B =
Total cost of construction of A = Rs
250000
π
r
2
2
=
250000
r
2
2
=
250000
π
Now expenditure on material for B = Area covered by material in circle B =
π
r
1
2
4
E
B
=
π
×
250000
4
×
π
=
62500
Answer:
expenditure on material for B -
expenditure on material for A =
62500
−
50000
=
12500
The following table gives information regarding land holdings of household of a village
Size of land holding
Number of houehold
More than 1 acre
1727
More than 2 acre
1268
More than 3 acre
378
More than 4 acre
155
More than 5 acre
52
in the village there are 2270 households. The number of households having land up to 1 acre is
Report Question
0%
1727
0%
459
0%
543
0%
378
Explanation
Total no. of households in the village
=
2270
Total no. of households in the village who has land more than one acre
=
1727
Hence,
Total no. of households having land up to one acre
=
2270
−
1727
⇒
543.
Study the above graph and calculate the difference between the number of cars manufactured by company
Y
in
2001
and
2000
?
Report Question
0%
20000
0%
30000
0%
40000
0%
50000
Explanation
Number of cars manufactured by company
Y
in
2001
=
80000
Number of cars manufactured by company
Y
in
2000
=
100000
The difference is
100000
−
80000
=
20000
How many men volunteered for navy and marine?
Report Question
0%
150, 125
0%
125, 375
0%
250, 150
0%
125, 150
Explanation
No of men joining navy force
=
60
360
×
900
=
150
No of men joining marine force
=
80
360
×
900
=
125
The circle graph given here shows the spending of a country on various sport.
What percent of total is spent on tennis?
Report Question
0%
25
2
%
0%
45
2
%
0%
25
%
0%
45
%
Explanation
Required percent is
=
45
360
×
100
=
25
2
%
The circle graph given here shows the spending of a country on the various sports.
On which game money is spent most?
Report Question
0%
Hookey
0%
Criket
0%
Football
0%
Golf
The circle graph given here shows the spending of a country on various sport.
How much percent more is spent on hocky than golf?
Report Question
0%
33
%
0%
347
%
0%
48.2
%
0%
42.8
%
Explanation
Required
%
=
63
−
36
63
×
100
=
42.8
%
How many people read newspaper in Delhi.
Report Question
0%
10
0%
20
0%
30
0%
40
Explanation
Given that bar with lines in the people reading newspaper and the empty bar is the people watching TV.
From the given graph, for the city Delhi, we can observe that the height of the bar with lines is
20
.
Therefore, Delhi has
20
people who read newspaper.
What percentage of men volunteered to join navy force?
Report Question
0%
25%
0%
21.97%
0%
16.67%
0%
49%
Explanation
Percentage of men volunteered to join navy force
=
60
360
×
100
=
16.67
%
The number of students in a hostel, speaking hindi is
40
, bengali is
25
and english
35
. If it is represented in pie chart central angle corresponding to hindi is _____
Report Question
0%
152
∘
0%
72
∘
0%
40
∘
0%
144
∘
Explanation
Central angle
=
40
40
+
25
+
35
×
360
∘
=
40
100
×
360
∘
=
144
∘
The number of votes received in the election of class monitor are
Mona
−
6
votes,
Payal
−
10
votes,
Prashant
−
2
votes,
Sona
−
20
votes,
Rajen
−
15
votes,
Meera
−
4
votes,
Subhash
−
3
votes
In a circle graph the central angle corresponding to the votes of Sona, Mona, Meera and Subhash are
Report Question
0%
120
∘
,
36
∘
,
24
∘
,
18
∘
0%
38
∘
,
115
∘
,
25
∘
,
20
∘
0%
50
∘
,
30
∘
,
130
∘
,
30
∘
0%
72
∘
,
36
∘
,
48
∘
,
150
∘
Explanation
Total no of votes
=
6
+
10
+
2
+
20
+
15
+
4
+
3
=
60
Central angles corresponding to the various votes
Mona
=
6
×
360
o
60
=
36
∘
Payal
=
10
×
360
o
60
=
60
∘
Prashant
=
2
×
360
o
60
=
12
∘
Rajen
=
15
×
360
o
60
=
90
∘
Subhash
=
3
×
360
o
60
=
18
∘
Sona
=
20
×
360
o
60
=
120
∘
Meera
=
4
×
360
o
60
=
24
∘
How many men volunteered for air force?
Report Question
0%
375
0%
250
0%
150
0%
125
Explanation
No of men joining air force
=
100
360
×
900
=
250
In which year showed the lowest result in Group exams?
Report Question
0%
2001
0%
2003
0%
2000
0%
2002
Explanation
Compare the respective pass percentage for three years :
2000
,
2001
,
2002
and
2003
.
54
×
100
66
>
39
×
100
49
<
57
×
100
62
>
70
×
100
79
2000
=
81.81
%
2001
=
79.59
%
2002
=
91.9
%
2003
=
88.6
%
So, in the year
2001
showed the lowest result in Group exams.
What was the percentage of students who succeeded in at least one of three exams in
2002
?
Report Question
0%
65.7
%
`
0%
76.2
%
0%
87.2
%
0%
91.9
%
Explanation
Total percentage of students who succeeded in at least one of three exams in
2002
=
57
×
100
62
=
91.9
%
Study the above graph and calculate
the average numbers of cars manufactured by Company
X
over the given period.
Report Question
0%
200,000
0%
100,000
0%
300,000
0%
400,000
Explanation
Average number of cars manufactured by Company
X
=
1
6
[
100000
+
80000
+
60000
+
120000
+
80000
+
160000
]
=
1
6
[
600000
]
=
100
,
000
Study the above graph and calculate the average numbers of cars manufactured by Company
Y
over the given period.
Report Question
0%
96,666.66
0%
86,666.66
0%
76,666.66
0%
66,666.66
Explanation
Average number of cars manufactured by Company
Y
=
1
6
[
80000
+
60000
+
100000
+
80000
+
120000
+
140000
]
=
1
6
[
580000
]
=
96,666.66
Determine the percentage of the students who passed the group examination of the year
2002
?
Report Question
0%
68.6
%
0%
91.9
%
0%
75.6
%
0%
81.81
%
Explanation
Required percentage
=
57
×
100
62
=
91.9
%
What percent of students spending on football?
Report Question
0%
1.47
%
0%
2.77
%
0%
3.45
%
0%
4.21
%
Explanation
Percent of students spending on football
=
10
360
×
100
%
=
2.77
%
Which year showed the best result in Group exams (in terms of percentage of students who cleared)?
Report Question
0%
2000
0%
2001
0%
2002
0%
2003
Explanation
Compare the respective pass percentage for three years :
2000
,
2001
,
2002
and
2003
.
54
×
100
66
>
39
×
100
49
<
57
×
100
62
>
70
×
100
79
2000
=
81.81
%
2001
=
79.59
%
2002
=
91.9
%
2003
=
88.6
%
So, in the year
2002
showed the best result in Group exams.
Find the percentage of students who cleared Group exam in
2003
.
Report Question
0%
11.39
%
0%
23.67
%
0%
31.64
%
0%
45.9
%
Explanation
Total percentage of students who passed group exam in the year
2003
=
25
×
100
79
=
31.64
%
Study the above graph and calculate
the difference between the number of cars manufactured by Company
X
in
2001
and
2002
?
Report Question
0%
20000
0%
30000
0%
40000
0%
50000
Explanation
Number of cars manufacturd by
X
in
2001
=
120000
Number of cars manufactured by
X
in
2002
=
80000
The difference is
120000
−
80000
=
40000
Which of the countries listed below accounts for the maximum GDP during the year
2010
?
Report Question
0%
Russia
0%
Germany
0%
Japan
0%
India
Explanation
In the given bar chart, blue colour indicates the GDP during 2009 and red colour indicates the GDP during 2010.
From the graph, the maximum GDP during the year 2010 is observed in Germny with 25 trillion.
Using the line graph, find the average income of sportsman during the period
2000
−
2003
.
Report Question
0%
187.5
crores
0%
287.5
crores
0%
387.5
crores
0%
487.5
crores
Explanation
Average income os sportsman from the year
2000
−
2003
=
210
+
440
+
300
+
200
4
=
1150
4
=
287.5
crores
The number of washing machines purchased in the past
35
weeks is given in a line graph. Find the total number of washing machines purchased in
20
weeks.
Report Question
0%
140
0%
150
0%
160
0%
170
Explanation
The total number of washing machines purchased in
20
weeks
=
10
+
20
+
40
+
90
=
160
Which one of the following graph is an example of frequency polygon?
Report Question
0%
0%
0%
0%
Explanation
We know, the frequency polygon is formed by joining the mid-points of each upper sides of adjacent rectangles of the histogram by line segments.
Then clearly, the option
B
is an example of frequency polygon.
The line graph represent the net sales rate of Apple company from the year
2003
−
2013
. Find the increase in sales rate during
2005
−
2007
.
Report Question
0%
16
,
000
millions
0%
8
,
000
millions
0%
26
,
000
millions
0%
32
,
000
millions
Explanation
The difference between the two sales rate of the year
2005
−
2007
is:
32
,
000
−
16
,
000
=
16
,
000
So, the increase in sales rate from the year
2005
−
2007
=
16
,
000
millions
In the graph you can find the takings of a chocolate bar for
8
months.
Answer the following question:
What is the average chocolate bars taken out from the month January to May?
Report Question
0%
23000
0%
35000
0%
50000
0%
42000
Explanation
From the given frequency polygon,
Number of chocolates taken in Jan
=
50000
Number of chocolates taken in Feb
=
40000
Number of chocolates taken in Mar
=
35000
Number of chocolates taken in Apr
=
45000
Number of chocolates taken in May
=
40000
Number of chocolates taken in June
=
50000
Number of chocolates taken in Jul
=
60000
Number of chocolates taken in Aug
=
60000
.
Then, Average of chocolate bars taken out
=
50000
+
40000
+
35000
+
45000
+
40000
5
=
210000
5
=
42000
.
Therefore,
42000
chocolate bars are taken out from the month January to May.
Hence, option
D
is correct.
The number of hours each student of a class spends studying is
4
,
6
,
5
,
8
,
9
,
5
,
7
,
4
, and
8
hours. Identify the frequency polygon for the given data.
Report Question
0%
figure
1
0%
figure
3
0%
figure
4
0%
figure
2
In the graph you can find the takings of a chocolate bar for
8
months.
Answer the following question:
Find the percent increase from May to June.
Report Question
0%
10
%
0%
25
%
0%
30
%
0%
50
%
Explanation
From the given frequency polygon,
Number of chocolates taken in Jan
=
50000
Number of chocolates taken in Feb
=
40000
Number of chocolates taken in Mar
=
35000
Number of chocolates taken in Apr
=
45000
Number of chocolates taken in May
=
40000
Number of chocolates taken in June
=
50000
Number of chocolates taken in Jul
=
60000
Number of chocolates taken in Aug
=
60000
.
∴
Percent increase for month May and June
=
50000
−
40000
40000
×
100
%
=
25
%
.
Hence, option
B
is correct.
In the graph you can find the takings of a chocolate bar for
8
months. Answer the following question
Identify in which two months
50000
chocolate bars are taken out?
Report Question
0%
Jan and Feb
0%
Jun and Jul
0%
Jan and Jun
0%
Feb and Mar
Explanation
From the given frequency polygon,
Number of chocolates taken in Jan
=
50000
Number of chocolates taken in Feb
=
40000
Number of chocolates taken in Mar
=
35000
Number of chocolates taken in Apr
=
45000
Number of chocolates taken in May
=
40000
Number of chocolates taken in June
=
50000
Number of chocolates taken in Jul
=
60000
Number of chocolates taken in Aug
=
60000
.
Clearly, we can say Jan and June months shows the same number of chocolates, i.e.
50000
chocolates.
So, in the months of
Jan and June
,
50000
chocolate bars are taken out.
Hence, option
C
is correct.
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