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CBSE Questions for Class 11 Commerce Economics Presentation Of Data Quiz 8 - MCQExams.com
CBSE
Class 11 Commerce Economics
Presentation Of Data
Quiz 8
Two houses A and B were constructed at a total cost of Rs 100000 and Rs 250000 respectively The expenditure on materials is shown in the pie charts given bellow
The expenditure on B exceeds expenditure on A by :
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0%
Rs $$12500$$
0%
Rs $$15000$$
0%
Rs $$10000$$
0%
Rs $$22000$$
Explanation
Answer:-
Shaded area = Materials
Given:- Area of circle A = Total cost of construction of A = Rs $$100000$$
$$\pi {r_1}^2 = 100000$$
$$\Rightarrow \;{r_1}^2=\cfrac{100000}{\pi}$$
Now expenditure on material for A = Area covered by material in circle A = $$\cfrac{\pi {r_1}^2}{2}$$
$$E_A = \cfrac{\pi \times 100000}{2\times \pi}=50000$$
Similarly: Area of B =
Total cost of construction of A = Rs $$250000$$
$$\pi {r_2}^2 = 250000$$
$${r_2}^2 = \cfrac{250000}{\pi}$$
Now expenditure on material for B = Area covered by material in circle B = $$\cfrac{\pi {r_1}^2}{4}$$
$$E_B = \cfrac{\pi \times 250000}{4\times \pi}=62500$$
Answer:
expenditure on material for B -
expenditure on material for A = $$62500 - 50000 = 12500$$
The following table gives information regarding land holdings of household of a village
Size of land holding
Number of houehold
More than 1 acre
1727
More than 2 acre
1268
More than 3 acre
378
More than 4 acre
155
More than 5 acre
52
in the village there are 2270 households. The number of households having land up to 1 acre is
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0%
1727
0%
459
0%
543
0%
378
Explanation
Total no. of households in the village $$=2270$$
Total no. of households in the village who has land more than one acre $$=1727$$
Hence,
Total no. of households having land up to one acre $$=2270-1727\Rightarrow 543.$$
Study the above graph and calculate the difference between the number of cars manufactured by company $$Y$$ in $$2001$$ and $$2000$$?
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0%
$$20000$$
0%
$$30000$$
0%
$$40000$$
0%
$$50000$$
Explanation
Number of cars manufactured by company $$Y$$ in $$2001$$ $$=80000$$
Number of cars manufactured by company $$Y$$ in $$2000$$ $$= 100000$$
The difference is $$ 100000-80000 = 20000$$
How many men volunteered for navy and marine?
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0%
150, 125
0%
125, 375
0%
250, 150
0%
125, 150
Explanation
No of men joining navy force $$=\dfrac{60}{360}\times 900=150$$
No of men joining marine force $$=\dfrac{80}{360}\times 900=125$$
The circle graph given here shows the spending of a country on various sport.
What percent of total is spent on tennis?
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0%
$$\dfrac{25}{2}\%$$
0%
$$\dfrac{45}{2}\%$$
0%
$$25\%$$
0%
$$45\%$$
Explanation
Required percent is $$=\dfrac{45}{360} \times 100=\dfrac{25}{2}\%$$
The circle graph given here shows the spending of a country on the various sports.
On which game money is spent most?
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0%
Hookey
0%
Criket
0%
Football
0%
Golf
The circle graph given here shows the spending of a country on various sport.
How much percent more is spent on hocky than golf?
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0%
$$33\%$$
0%
$$347\%$$
0%
$$48.2\%$$
0%
$$42.8\%$$
Explanation
Required $$\% = \dfrac{63-36}{63}\times 100 = 42.8\%$$
How many people read newspaper in Delhi.
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0%
$$10$$
0%
$$20$$
0%
$$30$$
0%
$$40$$
Explanation
Given that bar with lines in the people reading newspaper and the empty bar is the people watching TV.
From the given graph, for the city Delhi, we can observe that the height of the bar with lines is $$20$$.
Therefore, Delhi has $$20$$ people who read newspaper.
What percentage of men volunteered to join navy force?
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0%
25%
0%
21.97%
0%
16.67%
0%
49%
Explanation
Percentage of men volunteered to join navy force $$=\frac{60}{360}\times 100 = 16.67\%$$
The number of students in a hostel, speaking hindi is $$40$$, bengali is $$25$$ and english $$35$$. If it is represented in pie chart central angle corresponding to hindi is _____
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0%
$$152^\circ$$
0%
$$72^\circ$$
0%
$$40^\circ$$
0%
$$144^\circ$$
Explanation
Central angle $$=\dfrac{40}{40+25+35}\times 360^\circ=\dfrac{40}{100} \times 360^\circ = 144^\circ$$
The number of votes received in the election of class monitor are
Mona $$-$$ $$6$$ votes,
Payal $$-$$ $$10$$ votes,
Prashant $$-$$ $$2$$ votes,
Sona $$-$$ $$20$$ votes,
Rajen $$-$$ $$15$$ votes,
Meera $$-$$ $$4$$ votes,
Subhash $$-$$ $$3$$ votes
In a circle graph the central angle corresponding to the votes of Sona, Mona, Meera and Subhash are
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0%
$$120^\circ, 36^\circ, 24^\circ, 18^\circ$$
0%
$$38^\circ, 115^\circ, 25^\circ, 20^\circ$$
0%
$$50^\circ, 30^\circ, 130^\circ, 30^\circ$$
0%
$$72^\circ, 36^\circ, 48^\circ, 150^\circ$$
Explanation
Total no of votes $$= 6 + 10 +2 + 20 + 15 + 4 + 3 = 60$$
Central angles corresponding to the various votes
Mona $$=\cfrac{6\times 360^o}{60}=36^\circ$$
Payal $$=\cfrac{10\times 360^o}{60}=60^\circ$$
Prashant $$=\cfrac{2\times 360^o}{60}=12^\circ$$
Rajen $$=\cfrac{15\times 360^o}{60}=90^\circ$$
Subhash $$=\cfrac{3\times 360^o}{60}=18^\circ$$
Sona $$=\cfrac{20\times 360^o}{60}=120^\circ$$
Meera $$=\cfrac{4\times 360^o}{60}=24^\circ$$
How many men volunteered for air force?
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0%
375
0%
250
0%
150
0%
125
Explanation
No of men joining air force $$=\dfrac{100}{360}\times 900 = 250$$
In which year showed the lowest result in Group exams?
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0%
$$2001$$
0%
$$2003$$
0%
$$2000$$
0%
$$2002$$
Explanation
Compare the respective pass percentage for three years : $$2000, 2001, 2002$$ and $$2003$$.
$$\dfrac{54 \times 100}{66} > \dfrac{39\times 100}{49}< \dfrac{57\times 100}{62}> \dfrac{70\times 100}{79}$$
$$2000 = 81.81\%$$
$$2001 = 79.59\%$$
$$2002 = 91.9\%$$
$$2003 = 88.6\%$$
So, in the year $$2001$$ showed the lowest result in Group exams.
What was the percentage of students who succeeded in at least one of three exams in $$2002$$?
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0%
$$65.7\%$$`
0%
$$76.2\%$$
0%
$$87.2\%$$
0%
$$91.9\%$$
Explanation
Total percentage of students who succeeded in at least one of three exams in $$2002 =$$ $$\dfrac{57\times 100}{62}$$
$$= 91.9\%$$
Study the above graph and calculate
the average numbers of cars manufactured by Company $$X$$ over the given period.
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0%
$$200{,}000$$
0%
$$100{,}000$$
0%
$$300{,}000$$
0%
$$400{,}000$$
Explanation
Average number of cars manufactured by Company $$X$$
$$=\cfrac{1}{6}[100000 + 80000 + 60000 + 120000 + 80000 + 160000]$$
$$=\cfrac{1}{6}[600000]$$
$$= 100,000$$
Study the above graph and calculate the average numbers of cars manufactured by Company $$Y$$ over the given period.
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0%
$$96{,}666.66$$
0%
$$86{,}666.66$$
0%
$$76{,}666.66$$
0%
$$66{,}666.66$$
Explanation
Average number of cars manufactured by Company $$Y$$
$$=\cfrac{1}{6}[80000 + 60000 + 100000 + 80000 + 120000 + 140000]$$
$$= \cfrac{1}{6}[580000]$$
$$= 96{,}666.66$$
Determine the percentage of the students who passed the group examination of the year $$2002$$?
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0%
$$68.6\%$$
0%
$$91.9\%$$
0%
$$75.6\%$$
0%
$$81.81\%$$
Explanation
Required percentage $$=$$ $$\dfrac{57\times 100}{62}$$
$$= 91.9\%$$
What percent of students spending on football?
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0%
$$1.47\%$$
0%
$$2.77\%$$
0%
$$3.45\%$$
0%
$$4.21\%$$
Explanation
Percent of students spending on football $$=$$ $$\dfrac{10}{360}\times 100\% = 2.77\%$$
Which year showed the best result in Group exams (in terms of percentage of students who cleared)?
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0%
$$2000$$
0%
$$2001$$
0%
$$2002$$
0%
$$2003$$
Explanation
Compare the respective pass percentage for three years : $$2000, 2001, 2002$$ and $$2003$$.
$$\dfrac{54 \times 100}{66} > \dfrac{39\times 100}{49}< \dfrac{57\times 100}{62}> \dfrac{70\times 100}{79}$$
$$2000 = 81.81\%$$
$$2001 = 79.59\% $$
$$2002 = 91.9\%$$
$$2003 = 88.6\%$$
So, in the year $$2002$$ showed the best result in Group exams.
Find the percentage of students who cleared Group exam in $$2003$$.
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0%
$$11.39\%$$
0%
$$23.67\%$$
0%
$$31.64\%$$
0%
$$45.9\%$$
Explanation
Total percentage of students who passed group exam in the year $$2003 =$$ $$\dfrac{25\times 100}{79}$$
$$= 31.64\%$$
Study the above graph and calculate
the difference between the number of cars manufactured by Company $$X$$ in $$2001$$ and $$2002$$?
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0%
$$20000$$
0%
$$30000$$
0%
$$40000$$
0%
$$50000$$
Explanation
Number of cars manufacturd by $$X$$ in $$2001 = 120000$$
Number of cars manufactured by $$ X$$ in $$2002=80000$$
The difference is $$120000-80000=40000$$
Which of the countries listed below accounts for the maximum GDP during the year $$2010$$?
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0%
Russia
0%
Germany
0%
Japan
0%
India
Explanation
In the given bar chart, blue colour indicates the GDP during 2009 and red colour indicates the GDP during 2010.
From the graph, the maximum GDP during the year 2010 is observed in Germny with 25 trillion.
Using the line graph, find the average income of sportsman during the period $$2000-2003$$.
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0%
$$187.5 $$ crores
0%
$$287.5$$ crores
0%
$$387.5$$ crores
0%
$$487.5$$ crores
Explanation
Average income os sportsman from the year $$2000-2003 =$$ $$\dfrac{210 + 440 + 300 + 200}{4}$$
$$=$$ $$\dfrac{1150}{4}$$
$$= 287.5$$ crores
The number of washing machines purchased in the past $$35$$ weeks is given in a line graph. Find the total number of washing machines purchased in $$20$$ weeks.
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0%
$$140$$
0%
$$150$$
0%
$$160$$
0%
$$170$$
Explanation
The total number of washing machines purchased in $$20$$ weeks $$= 10 + 20 + 40 + 90 = 160$$
Which one of the following graph is an example of frequency polygon?
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0%
0%
0%
0%
Explanation
We know, the frequency polygon is formed by joining the mid-points of each upper sides of adjacent rectangles of the histogram by line segments.
Then clearly, the option $$B$$ is an example of frequency polygon.
The line graph represent the net sales rate of Apple company from the year $$2003-2013$$. Find the increase in sales rate during $$2005-2007$$.
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0%
$$16,000$$ millions
0%
$$8,000$$ millions
0%
$$26,000$$ millions
0%
$$32,000$$ millions
Explanation
The difference between the two sales rate of the year $$2005-2007$$ is:
$$32,000 - 16,000 = 16,000$$
So, the increase in sales rate from the year $$2005-2007 = 16,000$$ millions
In the graph you can find the takings of a chocolate bar for $$8$$ months.
Answer the following question:
What is the average chocolate bars taken out from the month January to May?
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0%
$$23000$$
0%
$$35000$$
0%
$$50000$$
0%
$$42000$$
Explanation
From the given frequency polygon,
Number of chocolates taken in Jan $$=50000$$
Number of chocolates taken in Feb $$=40000$$
Number of chocolates taken in Mar $$=35000$$
Number of chocolates taken in Apr $$=45000$$
Number of chocolates taken in May $$=40000$$
Number of chocolates taken in June $$=50000$$
Number of chocolates taken in Jul $$=60000$$
Number of chocolates taken in Aug $$=60000$$
.
Then, Average of chocolate bars taken out $$=$$ $$\dfrac{50000 + 40000+35000+45000+40000}{5}$$
$$=$$ $$\dfrac{210000}{5}$$
$$= 42000$$.
Therefore, $$42000$$ chocolate bars are taken out from the month January to May.
Hence, option $$D$$ is correct.
The number of hours each student of a class spends studying is $$4, 6, 5, 8, 9, 5, 7, 4$$, and $$8$$ hours. Identify the frequency polygon for the given data.
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0%
figure $$1$$
0%
figure $$3$$
0%
figure $$4$$
0%
figure $$2$$
In the graph you can find the takings of a chocolate bar for $$8$$ months.
Answer the following question:
Find the percent increase from May to June.
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0%
$$10\%$$
0%
$$25\%$$
0%
$$30\%$$
0%
$$50\%$$
Explanation
From the given frequency polygon,
Number of chocolates taken in Jan $$=50000$$
Number of chocolates taken in Feb $$=40000$$
Number of chocolates taken in Mar $$=35000$$
Number of chocolates taken in Apr $$=45000$$
Number of chocolates taken in May $$=40000$$
Number of chocolates taken in June $$=50000$$
Number of chocolates taken in Jul $$=60000$$
Number of chocolates taken in Aug $$=60000$$
.
$$\therefore$$ Percent increase for month May and June $$=$$ $$\dfrac{50000-40000}{40000}\times 100\%$$
$$= 25\%$$.
Hence, option $$B$$ is correct.
In the graph you can find the takings of a chocolate bar for $$8$$ months. Answer the following question
Identify in which two months $$50000$$ chocolate bars are taken out?
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0%
Jan and Feb
0%
Jun and Jul
0%
Jan and Jun
0%
Feb and Mar
Explanation
From the given frequency polygon,
Number of chocolates taken in Jan $$=50000$$
Number of chocolates taken in Feb $$=40000$$
Number of chocolates taken in Mar $$=35000$$
Number of chocolates taken in Apr $$=45000$$
Number of chocolates taken in May $$=40000$$
Number of chocolates taken in June $$=50000$$
Number of chocolates taken in Jul $$=60000$$
Number of chocolates taken in Aug $$=60000$$
.
Clearly, we can say Jan and June months shows the same number of chocolates, i.e. $$50000$$ chocolates.
So, in the months of
Jan and June
, $$50000$$ chocolate bars are taken out.
Hence, option $$C$$ is correct.
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