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CBSE Questions for Class 11 Commerce Economics Presentation Of Data Quiz 9 - MCQExams.com
CBSE
Class 11 Commerce Economics
Presentation Of Data
Quiz 9
Identify the frequency polygon.
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0%
0%
0%
Explanation
We know, the frequency polygon is formed by joining the mid-points of each upper sides of adjacent rectangles of the histogram by line segments.
Then clearly, the option $$A$$ is an example of frequency polygon.
In which frequency polygon is best suitable for the following table.
Month
Jun.
Jul.
Aug.
Sep.
Oct.
Number of burgers sold
100
400
300
500
200
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0%
0%
0%
0%
Explanation
We know, the frequency polygon is formed by joining the mid-points of each upper sides of adjacent rectangles of the histogram by line segments.
To draw the frequency polygon of the given data:
Step 1: The heights of the bars in the histograms indicate the number of burgers sold.
Step 2: Observe the heights of the bars in the histograms to match with the given values.
Step 3: Compute the midpoints of the bars and draw the lines along these midpoints.
Step 4: Frequency polygon of this data will be as follows.
Therefore, option $$A$$ represents the frequency polygon for the given data.
The figure above shows the cost of joining and buying music from a music subscription service. What does the y-intercept of the line most likely represent?
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The cost per song
0%
The cost to join the service
0%
The cost of buying 20 songs
0%
The cost of 20 subscriptions to the service
Explanation
When no. of songs are 0 then cost is 20$. This means the cost of joining the service is 20$.
Hence, the y-intercept (i.e. 20) of the line represent the cost to join the service.
So, the answer is option (B).
The table shows the number of cups of four different beverages sold by a coffee shop. What is the angle of sector representing tea in a pie chart?
Beverage
Number of cups
Coffee
60
Tea
75
Hot chocolate
25
Milk
40
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0%
$$40^o$$
0%
$$135^o$$
0%
$$108^o$$
0%
$$72^o$$
Explanation
Given table shows the number of cups sold for four different beverages by a coffee shop.
If the given data is represented in a pie chart, the complete angle of the circle is divided into four parts, each representing the number of cups for a particular beverage.
We know that, the complete angle in a circle is $$360^o$$.
Also, total number of cups in the given data $$=60+75+25+40$$
$$=200$$
Also, number of cups for tea $$=75$$.
Hence, the angle of sector represent tea $$=\dfrac{75}{200}\times 360^o$$.
$$=135^o$$
Hence, the angle of the sector representing tea in the pie chart is $$135^o$$.
The pie-charts show the distribution of students of IIT's in seven different companies.
How many of TATA and BIRLA are students from IIT?
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0%
$$4641$$
0%
$$3822$$
0%
$$8420$$
0%
$$8463$$
Explanation
Total % in TATA & BIRLA $$=17+14=31\%$$
Number of people from $$=\cfrac { 31}{ 100 }\times 27300 =8463.$$
If 3,750 2-door sedans were sold in 1999, then how many 4-door sedans were sold in 1999 by XYZ Auto Company?
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0%
3,578
0%
4,950
0%
5,120
0%
5,670
0%
5,845
In which pair of years was the number of candidates qualified, the same?
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0%
1995 and 1997
0%
1995 and 2000
0%
1998 and 1999
0%
Data inadequate
Explanation
The graph gives the data for the percentage of candidates qualified to appeared and unless the absolute values of number of candidates qualified or candidates appeared is know we cannot compare the absolute values for any two years.
Hence, the data is inadequate to solve this question.
The graph in Figure 3 shows the monthly stable expenses for Samantha's horse. If she spends $350 for feed and board, how much does she spend on veterinary bills?
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0%
$200
0%
$250
0%
$275
0%
$325
0%
$375
The central angle corresponding to Market Borrowing is
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0%
$$52^o$$
0%
$$137.8^o$$
0%
$$187.2^o$$
0%
$$192.4^o$$
What was the percentage increase in imports from 1997 to 1998 ?
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0%
72
0%
56
0%
28
0%
Data inadequate
Explanation
The graph gives only the ratio of imports to exports for different years. To find the percentage increase in imports from 1997 to 1998, we require more details such as the value of imports or exports during these years.
Hence, the data is inadequate to answer this question.
A circle graph is used to show the percent of patient types that a hospital sees. How many degrees of the circle should the graph show to represent pediatric if $$\dfrac{1}{3}$$ of the patients are pediatric patients?
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0%
90 degrees
0%
120 degrees
0%
220 degrees
0%
360 degrees
0%
180 degrees
State whether the following statement is true or false
Next to Bicycles, most people prefer to travel by bikes.
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True
0%
False
Explanation
From the given pie chart, we can observe that the most people travel using bicycles i.e., ($$40\%$$)
Next to bicycles, most people prefer to travel on bikes
i.e., ($$30\%$$)
Thus given statement is true.
What is the total number of students in the class?
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0%
$$74$$
0%
$$84$$
0%
$$94$$
0%
None of these
Explanation
Total Number of students in class
$$=$$ Sum of all frequencies of intervals
$$= 4+8+20+40+22$$$$=94$$
Plot the frequency curve for the histogram and find the same marks in which maximum student have scored?
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0%
$$80-100$$
0%
$$40-60$$
0%
$$60-80$$
0%
None of these
Explanation
$$Class\,Interval\,(Marks)$$
$$No\,of\,students$$
$$0-20$$
$$4$$
$$20-40$$
$$6$$
$$40-60$$
$$20$$
$$60-80$$
$$40$$
$$80-100$$
$$22$$
$$\Rightarrow$$ From above frequency table we can see, number of students score marks between $$60-80$$ are $$40$$ which is maximum.
$$\therefore$$ The same mark in which maximum students score marks are $$60-80$$.
How a frequency curve is sketched?
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Frequency curve is sketched with the help of histogram by joining the end points of rectangles.
0%
Frequency curve is sketched with the help of histogram by joining the mid point of
rectangle
.
0%
Frequency curve is sketched with the help of histogram by joining the starting points of
rectangles.
0%
None of these
Explanation
Curve formed by joining the midpoint of rectangular of histogram is called as frequency curve.
In the above histogram, how many students have scored marks upto 40?
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0%
$$22$$
0%
$$12$$
0%
$$10$$
0%
$$16$$
Explanation
Number of students scored marks upto $$40$$
$$=$$ Number of students score between $$0$$ to $$20$$ + Number os students score between $$20$$ to $$40$$
$$=4+8$$
$$=12$$
Plot the frequency curve for the histogram and find the mode of the histogram?
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0%
$$30$$
0%
$$22$$
0%
$$40$$
0%
None of these
Explanation
Mode of histogram $$=$$ Frequency tallest bar
$$=$$ Highest frequency of a class
$$=40$$ (Class interval $$(60-80))$$
The above pie graph shows the time spend on leisure activities by $$A$$ in a week.
If total time spent by $$A$$ on leisure activities is $$30$$ hours in a week. How much time he spends for reading books?
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0%
$$36$$ mins
0%
$$42$$ mins
0%
$$30$$ mins
0%
$$48$$ mins
Explanation
$$A$$ spends $$2\%$$ of his time for reading books.
If total time spent by $$A$$ on leisure activities is $$30$$ hrs, then
time spent on reading books $$=\dfrac{2}{100}\times 30=0.6$$ hrs $$=36$$ mins
In a factory, there are $$1000$$ workers out of which $$400$$ are men and $$100$$ are married. Out of $$600$$ women, $$300$$ are married. Tabulate this data and calculate the total number of unmarried workers.
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0%
$$400$$
0%
$$600$$
0%
$$700$$
0%
$$800$$
Explanation
Married Workers
Unmarried Workers
Men
$$100$$
$$x$$
Women
$$300$$
$$y$$
Total number of men $$= 400$$
$$\therefore 100 + x = 400$$
$$x = 300$$
Total number of women $$= 600$$
$$\therefore 300 + y = 600$$
$$y = 300$$
Total number of unmarried workers $$= x + y = 600$$
There are $$500$$ students in a class in which there are $$100$$ boys. 50 boys like Mathematics and 100 girls dislike Mathematics. Tabulate the given data and calculate the number of girls who like the subject Mathematics.
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0%
$$50$$
0%
$$100$$
0%
$$150$$
0%
$$300$$
Explanation
Like Mathematics
Dislike Mathematics
No. of Boys
$$50$$
$$y$$
No. of Girls
$$x$$
$$100$$
Total number of students $$= 500$$
Number of boys $$= 100$$
Number of girls $$= 400$$
$$50 + y = 100$$ $$\Rightarrow y= 50$$
$$x + 100 = 400$$ $$\Rightarrow x= 300$$
$$\therefore$$ Number of girls who like Mathematics $$= 300$$
The population of Maharashtra is $$100$$ lacs, Madhya Pradesh is $$125$$ lacs and that of Haryana is $$75$$ lacs. Tabulate this data and find the total population of all the three states.
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$$200$$ lacs
0%
$$225$$ lacs
0%
$$300$$ lacs
0%
$$420$$ lacs
Explanation
State
Maharashtra
Madhya Pradesh
Haryana
Population
$$100$$ lacs
$$125$$ lacs
$$75$$ lacs
Total population of all the three states $$= 100 + 125 + 75 = 300$$ lacs
Which year showed the best result in MBA entrance exams (in terms of percentage of students who cleared?)
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0%
2000
0%
2001
0%
2002
0%
cannot be determined
Explanation
Number of students appeared in $$2000$$ $$=170$$
Students cleared any of the MBA exams $$=140$$
Percentage of students who cleared the exam $$=\dfrac{140}{170}\times 100=82.35$$
Number of students appeared in $$2001$$ $$=180$$
Students cleared any of the MBA exams $$=150$$
Percentage of students who cleared the exam $$=\dfrac{150}{180}\times 100=83.33$$
Number of students appeared in $$2002$$ $$=200$$
Students cleared any of the MBA exams $$=160$$
Percentage of students who cleared the exam $$=\dfrac{160}{200}\times 100=80$$
So the percentage is maximum in $$2001$$
Option $$B$$ is correct.
The pie chart given shows the expenditure of a family on various items and its savings during a year.
Study the pie chart and answer the following questions
If the total annual income of the family is Rs. $$75,000$$, what is the expenditure on children education?
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0%
Rs. $$9000$$
0%
Rs. $$9500$$
0%
Rs. $$8500$$
0%
Rs. $$5600$$
Explanation
Total annual income of the family is Rs. $$75,000$$.
Children education is $$12\%$$
So, expenditure on children education is $$ 75000 \times \dfrac {12 }{100} $$
Thus expenditure is Rs. $$ 9000$$.
The sub-divided bar graph shows the production of wheat, oats and barley in three consecutive years by a farmer. What is the percentage of oats and Barley in the year $$1991$$
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0%
$$40$$
0%
$$50$$
0%
$$60$$
0%
$$70$$
Explanation
Given sub-divided bar graph shows the production of wheat, oats and barley in 3 consecutive years.
In the year 1991, the production of oats is $$20$$ kg. and
the production of barley is $$40$$ kg.
The total production in the year 1991 is $$100$$ kg.
Therefore, the percentage of oats and barley in the year 1991 is $$\dfrac{20+40}{100}\times100=60\%$$
The pie charts shows the cases of fatal road accidents in various age groups. Which two age groups suffers the most in road accidents
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$$16-19$$ and $$25-34$$
0%
$$45-54$$ and $$75+$$
0%
$$16-19$$ and $$75+$$
0%
$$20-24$$ and $$65-75$$
Explanation
The pie chart shows the fatal road accidents in various age groups. The $$16-19$$ age group has $$32.13\%$$ road accidents and $$75+$$ age group has $$23.80\%$$ road accidents.
Therefore,
$$16-19$$
and
$$75+$$ age gropus suffer the most in road accidents.
The above graph shows the monthly budget of $$A$$.
If the total budget is Rs. $$2000$$. How much percent does he spends on healthcare,utility bills and dining out?
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$$14\%$$
0%
$$25\%$$
0%
$$21\%$$
0%
$$26\%$$
Explanation
$$A$$ spends $$12\%$$ of his budget on utility bills and $$8\%$$ and $$6\%$$ respectively on dining out and health care.
Total percentage of the budget he spends on utility bills, health care and dining out $$=12\%+8\%+6\%=26\%$$
The above graph shows the time spend by student on various activities.
Out of total time what fraction of students spend their time on sleeping?
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0%
$$\dfrac{1}{3}$$
0%
$$\dfrac{2}{25}$$
0%
$$\dfrac{1}{4}$$
0%
$$\dfrac{3}{4}$$
Explanation
Percentage of time spent on sleeping by student$$=33\%$$.
The fraction of the time out of the total time of students spent on their sleeping$$=\dfrac{33}{100}\approx \dfrac{1}{3}$$
The above graph shows the monthly budget of $$A$$.
If the total budget is Rs. $$2000$$. On which thing does he spends Rs. $$440$$?
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0%
Automobile
0%
Utility bills
0%
Grocery
0%
Dining out
Explanation
Total budget of $$A$$ is Rs. $$2000$$.
Thus $$\dfrac{440}{2000}\times 100=22\%$$
Rs. $$440$$ is $$22\% $$ of the total budget which $$A$$ spends on automobiles.
The above graph shows the monthly budget of $$A$$.
If the total budget is RS. $$2000$$. How much he spends on utility bill ?
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0%
Rs. $$440$$
0%
Rs. $$220$$
0%
Rs. $$240$$
0%
Rs. $$420$$
Explanation
$$A$$ spends $$12\%$$ of the total budget on utility bills.
Total budget $$=$$ Rs. $$2000 $$
Therefore, money spend on utility bill$$=\dfrac{12}{100}\times2000=$$ Rs. $$240 $$.
The above graph shows the monthly budget of $$A$$.
If the total budget is $$2000\ Rs$$. How much he spends on Automobile and Grocery?
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0%
$$900$$ Rs
0%
$$830$$ Rs
0%
$$880$$ Rs
0%
$$860$$ Rs
Explanation
$$A$$ spends $$21\%$$ on grocery and $$22\%$$ on automobile of his total budget.
Total percentage of budget he spends on grocery and automobile $$=21\%+22\%=43\%$$
And total budget is Rs. $$2000$$
the budget he spends on grocery and automobile $$=\dfrac{43}{100}\times 2000=$$ Rs. $$860$$.
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