Explanation
Equivalent weight equal to molecular weight divided by n- factor.$$n- factor$$ in case of $$H_3PO_2 = 1$$ Then Equivalent weight equal to molecular weight in case of $$H_3 PO_2$$.
$$H^+$$ in $$HCl$$ is the reactant reduced, and $$HCl$$ is the oxidizing agent. $$Zn$$ is the reactant oxidized and the reducing agent. $$Cu^{2+}$$ in $$CuCl_2$$ is the reactant reduced, and $$CuCl_2$$ is the oxidizing agent.$$Cl_2$$ is the reactant reduced and the oxidizing agent.
Nitrogen atoms can form up to four covalent bonds.In the ammonium ion($$NH_4^+$$), the nitrogen atom forms four covalent bonds, again filling the outermost orbital with eight electrons: Phosphorus can form up to five covalent bonds, as in phosphoric acid $$(H_3PO_4)$$.
Eka-boron wassubsequently named as
Due to the inert pair effect.
In the elements which are at a lower position in the group, there are d and f orbitals which have poor shielding effect. So outermost s electrons feel more attractions towards the nucleus and become more difficult to lose. So as 2 electrons are not getting lost from ns, the oxidation state decreases from +3 to +1.
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