Explanation
The inertness of s subshell electrons towards the bond formation is called inert pair effect or it can be said as the inactiveness of electrons present in outermost shell (i.e. ns^2) to get unpaired and involve in bond formation is called inert pair effect.
for example:
1) In 13th group, thallium can exhibit +1 and +3 oxidation states but it is stable in +1 oxidation state only due to inert pair effect
2) In 14th group , lead shows both +2 and +4 oxidation states but it is stable in +2 oxidation state due to inert pair effect.
3)In group 15 elements, the stability of +3 oxidation state increases down the group and that of +5 oxidation state decreases down the group, due to inert pair effect."
The inertness of s subshell electrons towards the bond formation is called inert pair effect or it can be said as the inactiveness of electrons present in the outermost shell (i.e. ns^2) to get unpaired and involve in bond formation is called inert pair effect.
2) In 14th group, lead shows both +2 and +4 oxidation states but it is stable in +2 oxidation state due to inert pair effect.
3)In group 15 elements, (Bi) the stability of +3 oxidation state increases down the group and that of +5 oxidation state decreases down the group, due to inert pair effect.
Hence, the correct options are A, B and C
Hence, the correct option is A.
Explanation:
In NC{l_5}, there is absence of d-orbitals. PC{l_5} has d-orbitals, so it exists.
Due to inert pair effect P{b^{2 + }} is more stable than P{b^{4 + }}. So it doesn’t form tetravalent compounds.
In carbonate ion the bonds are equal due to the resonance.
The configuration of O_2^ + (8 + 8 - 1 = 15) = \sigma 1{s^2},{\sigma ^*}1{s^2},\sigma 2{s^2},{\sigma ^*}2{s^2} \sigma 2p_z^2,\pi 2p_x^2 \approx 2p_y^2, {{\pi 2p}^*_{x}}^1 \approx \pi {{2p}^*_{y}}^0
The configuration of NO (7 + 8 = 15) = \sigma 1{s^2},{\sigma ^*}1{s^2},\sigma 2{s^2},{\sigma ^*}2{s^2} \sigma 2p_z^2,\pi 2p_x^2 \approx 2p_y^2, {{\pi 2p}^*_{x}}^1 \approx \pi {{2p}^*_{y}}^0
Both have one unpaired electron so they are paramagnetic.
Final answer: The statements B and C are incorrect. So the correct answer is options B and C.
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