Explanation
$$dx=e^{t}(\cos t+\sin t).dt$$ $$dy=e^{t}[\cos t-\sin t).dt$$ Hence $$\dfrac{dy}{dx}_{t=\tfrac{\pi}{4}}$$ $$=\dfrac{\cos t-\sin t}{\cos t+\sin t}_{t=\tfrac{\pi}{4}}$$ $$=0$$
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