Explanation
$$\dfrac{dy}{dx}=\dfrac{3(y+1)}{x-2}$$
$$\Rightarrow \int \dfrac{dy}{3(1+y)}=\int \dfrac{dx}{x-2}+c$$
$$\Rightarrow \dfrac{1}{3}\log(1+y)=\log(x-2)+log\ c$$
$$\Rightarrow \dfrac{1}{3}\log(1+y)=\log\ c(x-2)$$
$$\log(1+y)=\log(c(x-2))^{3}$$
$$\Rightarrow (1+y)=(x-2)^{3}c$$
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