Explanation
A resistance of $$ 10\Omega $$, acapacitance of $$ 0.1\mu F$$ and an inductance of $$2mH$$ are connected inseries across a source of alternatingemf of variab frequency. At what frequency does maximum current flow?
Given that,
$$ C=200pF $$
$$ C=200\times {{10}^{-12}}F $$
$$ L=100\mu H $$
$$ L=100\times {{10}^{-6}}H $$
We know that,
Frequency of wave = $$ \nu =\dfrac{1}{2\pi \sqrt{LC}} $$
$$ \nu =\dfrac{1}{2\times 3.14\sqrt{200\times {{10}^{-12}}\times 100\times {{10}^{-6}}}} $$
$$ \nu =\dfrac{1}{2\times 3.14\times 1.4142\times {{10}^{-7}}} $$
Now, the wavelength is
$$ \lambda =\dfrac{3\times {{10}^{8}}}{\nu } $$
$$ \lambda =\dfrac{3\times {{10}^{8}}}{\dfrac{1}{2\times 3.14\times 1.4142\times {{10}^{-7}}}} $$
$$ \lambda =3\times {{10}^{8}}\times 2\times 3.14\times 1.4142\times {{10}^{-7}} $$
$$ \lambda =26.643\times 10 $$
$$ \lambda =266.43\,m $$
Hence, the wavelength of radiated electromagnetic wave is $$266$$ m.
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