Explanation
A resistance of 10\Omega , acapacitance of 0.1\mu F and an inductance of 2mH are connected inseries across a source of alternatingemf of variab frequency. At what frequency does maximum current flow?
Given that,
C=200pF
C=200\times {{10}^{-12}}F
L=100\mu H
L=100\times {{10}^{-6}}H
We know that,
Frequency of wave = \nu =\dfrac{1}{2\pi \sqrt{LC}}
\nu =\dfrac{1}{2\times 3.14\sqrt{200\times {{10}^{-12}}\times 100\times {{10}^{-6}}}}
\nu =\dfrac{1}{2\times 3.14\times 1.4142\times {{10}^{-7}}}
Now, the wavelength is
\lambda =\dfrac{3\times {{10}^{8}}}{\nu }
\lambda =\dfrac{3\times {{10}^{8}}}{\dfrac{1}{2\times 3.14\times 1.4142\times {{10}^{-7}}}}
\lambda =3\times {{10}^{8}}\times 2\times 3.14\times 1.4142\times {{10}^{-7}}
\lambda =26.643\times 10
\lambda =266.43\,m
Hence, the wavelength of radiated electromagnetic wave is 266 m.
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