Explanation
The relation to find number of spectral lines is $$\frac{({{n}_{2}}-{{n}_{1}})({{n}_{2}}-{{n}_{1}}+1)}{2}$$
Here transition is from n = 4 to n = 1
So, number of spectral lines = $$\frac{3\times 4}{2}=6$$
Hence, there are 6 spectral lines.
Molar mass of $$Ca=M`= 40$$
Molar mass of$$Mg=M=24$$
Given mass of $$Ca= m`=40g$$
Given mass of $$Mg=m=?$$
Formula: $$m= m`× M/ M`$$
$$m= 40\times \dfrac{24}{40}$$
$$m= 24g$$
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