Explanation
The kinetic energy is given as
{\rm{K = e}}{{\rm{V}}_{\rm{0}}}
K = 1.6 \times {10^{ - 19}} \times \left( { - 3.2} \right)
K = 5.12 \times {10^{ - 19}}
By substituting the above value in
5.12 \times {10^{ - 19}} = 6.6 \times {10^{34}} \times f + 3.2
The frequency is 0.29 \times {1^{15}}
The initial momentum is given as,
\dfrac{{d\lambda }}{\lambda } = - \dfrac{{dP}}{{{P_i}}}
\dfrac{{0.05}}{{100}} = - \dfrac{{\Delta P}}{{{P_i}}}
{P_i} = - 2000\Delta P
The initial momentum of electron is - 2000\Delta P.
The electron diffraction pattern from a single slit will be as shown below.
dsinθ = λ/2π The line of maximum intensity for the zeroth order will exceed d very much.
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