Explanation
lf $$\mathrm{e}$$ is the induced $$\mathrm{e}$$.m.f. in the coil, then $$\displaystyle \mathrm{e}=-\mathrm{L}\frac{\mathrm{d}\mathrm{i}}{\mathrm{d}\mathrm{t}}$$
Therefore, $$\displaystyle \mathrm{L}=-\frac{\mathrm{e}}{\mathrm{d}\mathrm{i}/\mathrm{d}\mathrm{t}}$$
Substituting values, we get $$\displaystyle \mathrm{L}=\frac{-8\times 0.05}{-4}=0.1\mathrm{H}$$
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