Explanation
Hint: Write total flux through the loop and then use faraday law.
Solution:
Step-1: Find the induced e.m.f
For a coil of N number of turns and area A, rotating with the speed ωrad/sec in a magnetic field B the induced flux, ϕ=NBAsinωt
∴ Induced e.m.f (ε)=−dϕdt=−NBAωcosωt
Step-2: Find the peak current
Induced e.m.f (ε)=−NBAωcosωt
∴ Peak value of e. m⋅f=NBAω
Therefore peak current through the resistance
= Peak e.m.f Total resistance =NBAω5+10 ( Given, N=500 B=0.14 Wb/m2A=50 cm2=50×10−4 m2ω=150rad/sec)
=500×0.14×(50×10−4)×15015
=3.5 A
Hint: The induced emf in the square frame will be ε=B1av−B2av
Correct Option: (D)
Explanation for Correct Option:
Step 1: Find the magnetic induction.
Step 2: Find the induced emf.
Induced emf, ε=B1av−B2av
Here, v is the velocity of the frame.
⇒ε=(B1−B2)av
⇒ε=(1x−a2−1x+a2)μoIav2π
⇒ε=μoIav2πa(2x−a)(2x+a)
Therefore, the emf induced, εα1(2x−a)(2x+a)
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