Explanation
The current in a coil of 0.4 mH coil increases by 250 mA in 0.1 seconds. The induced emf will be:-
Emf is given by
$$ e=\dfrac{-d\phi }{dt} $$
$$ IR=\dfrac{-d\phi }{dt} $$
$$ I=\dfrac{1}{R}\dfrac{-d\phi }{dt} $$
Flux of the magnetic field through the loop
$$\phi =B.A\cos \omega t$$
Emf= $$-\dfrac{d\phi }{dt}=B.A\omega \sin \omega t$$
$$ \omega t=0\,to\,\pi \,\,,\,\,\,\,\,\sin \omega t=+ve $$
$$ \omega t=\pi \,to\,2\pi ,\,\,\,\,\,\,\,\sin \omega t=-ve $$
Hence, the direction of induced e.m.f. changes once in $$\dfrac{1}{2}$$ revolution.
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