Explanation
The current in a coil of 0.4 mH coil increases by 250 mA in 0.1 seconds. The induced emf will be:-
Emf is given by
e=−dϕdt
IR=−dϕdt
I=1R−dϕdt
Flux of the magnetic field through the loop
ϕ=B.Acosωt
Emf= −dϕdt=B.Aωsinωt
ωt=0toπ,sinωt=+ve
ωt=πto2π,sinωt=−ve
Hence, the direction of induced e.m.f. changes once in 12 revolution.
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