Explanation
An electron beam is moving near to a conducting loop then the induced current in the loop:-
As shown in the figure, a magnet is moved with a fast speed towards a coil at rest. due to this induced e.m.f, induced current and induced charge in the coil is $$e$$, $$i$$ and $$q$$ respectively .if the speed of the magnet is doubled , the incorrect statement is:
Given that,
Average emf $$V=20V$$
Current $$i=2.5\,A$$
We know that,
$$ V=L\dfrac{dI}{dt} $$
$$ 20=L\times \dfrac{5}{0.1} $$
$$ L=\dfrac{20}{50} $$
$$ L=0.4\,Henry $$
Hence, the self-inductance is $$0.4\ henry$$
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