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CBSE Questions for Class 12 Medical Physics Electrostatic Potential And Capacitance Quiz 10 - MCQExams.com

Two points charges 4μC and 2μC are separated by a distance of 1 m in air. At what point in between the charges and on the line joining the charges, is the electric potential zero? 
  • In the middle of the two charges
  • 1/3m from 4μC
  • 1/3m from 2μC
  • Nowhere the potential is zero
In a parallel plate capacitor, the region between the plates is filled by a delectric slab. The capacitor is connected to a cell and the slab is taken out.    
  • Some charge is drawn from the cell
  • Some charge is returned to the cell
  • The potential difference across the capacitor is reduced
  • No work is done by an external agent in taking the slab out
The distance between the plates of a parallel plate capacitor is d. A metal plate of thickness d/2 is placed between the plates. The capacitance would be then be
  • Unchanged
  • Initial
  • Zero
  • Doubled
A parallel plate capacitor consists of two circular plates each of radius 2 cm, separatrd by a distance of 0.1 mm If Voltage across the plates is at the rate of 5\times 10^{13} V/s, then the value of displacement current is
  • 5.50A
  • 5.56\times 10^{3}A
  • 2.28\times 10^{4}A
  • 5.56\times 10^{2}
Two identical particles of mass m carry a charge Q each . Initially one is at rest on a smooth horizontal plane and the other is projected along the plane directly towards first particle a large distance with speed v. The closed distance of approach be 
  • \frac{1}{{4\pi {\varepsilon _0}}}\frac{{{Q^2}}}{{mv}}
  • \frac{1}{{4\pi {\varepsilon _0}}}\frac{{4{Q^2}}}{{m{v^2}}}
  • \frac{1}{{4\pi {\varepsilon _0}}}\frac{{2{Q^2}}}{{m{v^2}}}
  • \frac{1}{{4\pi {\varepsilon _0}}}\frac{{3{Q^2}}}{{m{v^2}}}
For high frequency a capacitor offer
  • more reactance
  • less reactance
  • zero reactance
  • inifinite reactance
The plates of a parallel plate condenser are pulled apart with a velocity v. If at any instant their mutual distance of separation is x, the magnitude of the time of rate of change of capacity depends on x as follows : 
  • 1/x
  • 1/x ^{2}
  • x ^{2}
  • x
Equipotential surfaces are shown in fig, then the electric field strength will be 
1224828_1fdfa6cbc47c432ab0320203eec5d923.png
  • 100 Vm-1 along X-axis
  • 100 Vm-1 along Y-axis
  • 200 Vm-1 at an angle { 120 }^{ 0 } wirh X-axis
  • 50 Vm-1 at an angle { 180 }^{ 0 } wirh X-axis
The resultant capacitance between A and B in the following figure is equal to
1241952_b12ce9035b30437fb7f50021f1785e42.png
  • 1 \mu F
  • 3 \mu F
  • 2 \mu F
  • 1.5 \mu F
P, Q and R are three points in a uniform electric field. The electric potential is
1239393_3498dad3654c48978dae57f8b5049f86.PNG
  • minimum at R
  • minimum at Q
  • minimum at P
  • Same at all three points
A charged capacitor of capacitance C and having charge Q is to be connected with another uncharged capasitor of capasitance C' as shown till the steady state is reached , find the value of C' for heat liberated through the wires to be minimum.
1263382_ffcaa4db0fb44cbca33e3948c28e5305.png
  • zero
  • C
  • C /2
  • 2C
75\% of the distance d between the parallel plates of a capacitor is filled with a meterial of dielectric constant K. Find the changed capacitance if original capacitance was C_{0}.....................
  • \left(\dfrac{3K}{K+3}\right) C_{0}
  • \left(\dfrac{4K}{K+4}\right) C_{0}
  • \left(\dfrac{4K}{K+3}\right) C_{0}
  • \left(\dfrac{3K}{K+4}\right) C_{0}
Maximum charge on capacitor after switch is closed is
1244168_2e13f898e4b44df7acc285b5b66301e0.png
  • 2 CE
  • 4 CE
  • 6 CE
  • 7 CE
Two capacitors of 4\ \mu Fand 2\ \mu F are connected in series with the battery. If total potential difference across the two capacitors is 200 volts then the ratio  of potential difference across one capacitor to another is
  • 1:2
  • 2:1
  • 1:4
  • 4:1
The capacitor is charged by closing the switch S. The witch is then opened and the capacitor is allowed to discharge. Take { R }_{ 1 }={ R }_{ 2 }={ R }_{ 3 }=R (Battery is ideal and connecting wire has negligible resistance). The fraction of the total heat generated, lost in { R }_{ 1 } during discharging is :
  • \dfrac { 1 }{ 6 }
  • \dfrac { 1 }{ 3 }
  • \dfrac { 1 }{ 2 }
  • \dfrac { 2 }{ 3 }
The ratio of charge densities on the surface of two conducting spheres is 3 :lithe radii of t: the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere 2 is
  • 3 : 4
  • 3 : 1
  • 1 : 3
  • 4 : 9
The energy per unit volume of a dielectric medium is proportional to square of 
  • relative permittivity
  • charge
  • energy
  • electric intensity
The electric potential decreases uniformly from 120 V to 80 V as one moves on the X-axis from x = -1 cm to x = +1 cm. The electric field at the origin.
  • must be equal to 20 V/cm
  • must be equal to 2.0 V/cm
  • must be greater than 20 V/cm
  • must be less than 20 V/cm
The distance between the plates of a parallel plate capacitor is 3 mm and the potential 1 difference applied is 3\times10^5 V. If an electron travels from one plate to another, the change in its potential energy is
  • 3\times10^5 eV
  • 900 eV
  • 10^8 eV
  • Negligible
If electric intensity \overrightarrow { E } is along the X-axis, then the equipotential surfaces are parallel to
  • XOY plane
  • XOZ plane
  • YOZ plane
  • None of these
Let  V_0 be the potential at the origin in an electric field \overset{\rightarrow}{E}=E_x\hat{i}+E_y\hat{j}. The potential at the point (x,y) is:
  • V_0-{_{x}{E}_x}-{_{y}{E}_y}
  • V_0+{_{x}{E}_x}+{_{y}{E}_y}
  • {_{x}{E}_x}+{_{y}{E}_y}-V_0
  • \left(\sqrt{x^2+y^2}\right)\sqrt{{E}_{x}^{2}+{E}_{y}^{2}}-V_0
The electric potential at a distance of 3 \,m on the axis of a short dipole of dipole moment 4\times 10^{-12} coulomb-metre is 
  • 1.33 \times 10^{-3} V
  • 4 \,mV
  • 12 \,mV
  • 27 \,mV
The electric potential due to point charge at a point
  • May be approximately zero
  • May be positive
  • May be negative
  • Any of these
In order to increase the capacity of parallel plate condenser one should introduce between the plates, a sheet of
  • mica
  • tin
  • copper
  • stainless steel
A parallel plate capacitor of area 60 cm^2 and separation 3 mm is charged initially to 90 \mu C. If medium between the plates gets slightly conducting and the p!ate loses the charge initially at rate of 2.5\times10^{-8}  C/s, then what is the magnetic field between the plates?    
  • 2.5\times10^{-8} T
  • 2.0\times10^{-7} T
  • 1.63\times10^{-11} T
  • ZERO
If electric field in  a region is zero, then electric potential in the region
  • Must be zero
  • Must not be zero
  • May be zero
  • None of these
Three capacitors 4, 6 and 12 \mu F  are connected in series to a 10 V source. The charge on the middle capacitor is
  • 10 \mu C
  • 20 \mu C
  • 60 \mu C
  • 5 \mu C
In figure two points A and B are located in a region of electric field. The potential difference V_B-V_A is  
1293302_642afed671aa4f8cadaf6d16eaf32c86.png
  • Positive
  • Negative
  • Zero
  • None of these
Two charges -5\mu C and +10\mu C are placed 20 cm apart. The net electric field at the mid-point between the two charge is 
  • 4.5\times { 10 }^{ 5 }N/C directed towards +10\mu C
  • 13.5\times { 10 }^{ 5 }N/C directed towards -5\mu C
  • 13.5\times { 10 }^{ 5 }N/C directed towards +10\mu C
  • 4.5\times { 10 }^{ 5 }N/C directed towards -5\mu C
The change on capacitor { c }_{ 1 }
1303865_a4fbefe049b94e25b2adb1f97c57efdf.png
  • 0_{ \mu }c
  • 5_{ \mu }c
  • 10_{ \mu }c
  • none of these
In the following circuit the resultant capacitance between A and B is 1\mu F. Find the value of C :


1327539_108de9eab9da458d940873fd36570190.png
  • \dfrac { 23 }{ 32 } \mu F
  • \dfrac { 32 }{ 23 } \mu F
  • \dfrac { 13 }{ 23 } \mu F
  • \dfrac { 23 }{ 13 }
In the electric network shown, when no current flows through the 4\, \Omega resistor in the arm EB, the potential difference between the points A and D will be : 

1302685_670c3d90227c447d9320b0dd2095635c.PNG
  • 3 V
  • 4 V
  • 5 V
  • 6 V
The radius of the gold nucleus is 6.6 \times {10^{ - 15}}m  and the atomic number is 79. The electric potential at the surface of the gold nucleus is :
  • 1.7 \times {10^7}V
  • 7.1 \times {10^7}V
  • 1.7 \times {10^9}V
  • 7.1 \times {10^9}V
Some charge Q is to be distributed on 3 concentric shell such that surface charge density on each shell is same as shown. Find the electric potential at r(<a) from point O.
1347673_cded0cd5840646d29d116c1616e5e854.png
  • \dfrac { Q(a+b-c) }{ 4\pi { \varepsilon }_{ 0 }({ a }^{ 2 }+{ b }^{ 2 }+{ c }^{ 2 }) }
  • \dfrac { Q(a+b+c) }{ 4\pi { \varepsilon }_{ 0 }({ a }^{ 2 }+{ b }^{ 2 }+{ c }^{ 2 }) }
  • \dfrac { Q(a+b+c) }{ 4\pi { \varepsilon }_{ 0 }({ a }^{ 2 }-{ b }^{ 2 }+{ c }^{ 2 }) }
  • \dfrac { Q(a+b-c) }{ 4\pi { \varepsilon }_{ 0 }({ a }^{ 2 }+{ b }^{ 2 }-{ c }^{ 2 }) }
The charges Q + q and +q are placed at the vertices of a right-angle isosceles triangle as shown below. The net electrostatic energy of the configuration is zero, it the value of Q is: 
1331792_b9eb64ca72a54afd84f61aa007cbd8c5.PNG
  • \dfrac{-\sqrt{2}q}{\sqrt{2}+1}
  • -2q
  • \dfrac{-q}{1+\sqrt{2}}
  • +q
Two condenser of 2 \mu F and 4 \mu F are connected in series. The p.d of 1200 volt. The p.d across 2 \mu F is -
  • 400\ V
  • 600\ V
  • 800\ V
  • 900\ V
Potential difference between two points is equal to 
  • electric charge /time
  • work done/time
  • work done/charge
  • work done \times charge
Two capacitors 'A' of 3 \mu F  and 'B' of 2\mu F are connected in series. 'A' can withstand a potential difference of 3 KV while 'B' can withstand 5 KV. What maximum potential difference can be applied across the combination?
  • 8 KV
  • 6 KV
  • 7.5 KV
  • 8.3 KV
The charge on a capacitor plate in a circuit, as a function of time, is shown in the figure:
What is the value of current at t = 4s?
1332120_0c4669cddf464e62bcc1f83f816831bb.PNG
  • 3\ \mu A
  • 2\ \mu A
  • Zero
  • 1.5\ \mu A
The energy stored in a parallel plate capacitor can be treated as the energy filled. The energy per unit volume, due to the electric field is :
  • E^2
  • \dfrac{1}{2}{\epsilon_0}{E^2}
  • \dfrac{1}{{2{\epsilon_0}}}{E^2}
  • \frac{1}{2}{E^2}
The potential energy of a 1\mathrm { kg } particle free to move alongthe x -axis is given byV ( x ) = \left( \frac { x ^ { 4 } } { 4 } - \frac { x ^ { 2 } } { 2 } \right) J

The total mechanical energy of the particle is 21 . Then, the maximum speed (in ms ^ { 1 } ) is
  • \dfrac { 3 } { \sqrt { 2 } }
  • \sqrt { 2 }
  • \dfrac { 1 } { \sqrt { 2 } }
  • 2
 An infinite number of charges 'q' each are placed along the x - axis at x =1, x=4 ,x=8 and so on. If the distance are in meters calculate the electric potential at x=0
  • \frac{{3q}}{{8\pi {E_0}}}
  • \frac { q } { 2 \pi \epsilon _ { 0 } }
  • \frac { 2 q } { \pi \epsilon _ { 0 } }
  • \frac { 4 q } { \pi \epsilon _ { 0 } }
In the situation shown in figure, what should be the relation between Q and q so that electric potential at centre of the square is zero:
1330482_0485bbc720b24e49a55fae919d02f4a6.PNG
  • Q=q
  • Q=3q
  • Q=2q
  • Q=-3q
The figure shows an experiment plot for discharging of a capacitor in an R-C circuit. The time constant t of this circuit lies between 
1377845_fa536e3748c44f979e859708c64e3bc5.png
  • 0\ and\ 50\ sec
  • 50\ and\ 100\ sec
  • 100\ and\ 150\ sec
  • 150\ and\ 200\ sec
Two spheres of capacitance 3\mu F and 5\ mu F are charged to 300\ V and 500\ V respectibely and are connected together. The common potential in steady state will be :
  • 400\ V
  • 425\ V
  • 350\ V
  • 375\ V
In the capacitor shown in the circuit is charged to 5V and left in the circuit,in 12s the charge on the capacitor will become.
1396513_1ebe96fe877543b9a9a89171a51a8766.png
  • \frac {10}{e} C
  • \frac {e}{10} C
  • \frac {10}{e^2} C
  • \frac {e^2}{10} C
The electric potential at a point (x,0,0) is given byV=\left[\dfrac{1000}{\chi }+\dfrac{1500}{\chi }+\dfrac{500}{\chi }^3\right]
then the electric field at x =1\, m is (in volt/m)
  • -5500 \, \hat{i}
  • 5500 \, \hat{i}
  • \sqrt{5500 \, \hat{i}}
  • Zero
Potential difference between the points B and C of the circuit is 
1393663_508c6295259146acb9e9a0b8225e55d0.PNG
  • \dfrac { ( C_2-C_1 ) }{V}
  • \dfrac { ( C_4-C_3 ) }{V}
  • \dfrac { ( C_2C_3 - C_1C_4 ) }{ (C_1+C_2+C_3+C_4) } V
  • \dfrac {C_1C_4 - C_2C_3 }{ ( C_1+C_2) \times ( C_3+C_4) } V
An arc of radius r carries change. The linear density of charge is \lambda and the arc subtends a angle \frac{\pi }{3} at the center. What is electric potential at the center
  • \dfrac{\lambda }{4\varepsilon _{0}}
  • \dfrac{\lambda }{8\varepsilon _{0}}
  • \dfrac{\lambda }{12\varepsilon _{0}}
  • \dfrac{\lambda }{16\varepsilon _{0}}
The potential at a point, due to a positive charge of  10\mu { C }  at a distance of  9 m  is
  • 10^{ { 5 } }V
  • 10^{ { 3 } }V
  • 10^{ { 6 } }V
  • 10^{ { 4 } }V
0:0:2


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