CBSE Questions for Class 12 Medical Physics Electrostatic Potential And Capacitance Quiz 14 - MCQExams.com

The equivalent capacitance between the points $$A$$ and $$B$$ in the given diagram is:
1119083_567014c820bf49a5ad3c5009f97e92dc.png
  • $$8\mu F$$
  • $$6\mu F$$
  • $$\frac{8}{3}\mu F$$
  • $$\frac{3}{8}\mu F$$
A non conducting semicircular disc (as shown in figure) has a uniform surface charge density $$\sigma $$. The electric potential at the centre of the disc:-
1115270_e1d6a8d29f7640d08f9689dbd8a7cf54.png
  • $$\dfrac{\sigma \ \iota n(b/a)}{2\pi \ \varepsilon _{0}\ (b-a)}$$
  • $$\dfrac{\sigma (b-a)}{2\ \varepsilon _{0}}$$
  • $$\dfrac{\sigma (b-a)}{4\ \varepsilon _{0}}$$
  • $$\dfrac{\sigma (b-a)}{4\pi \ \varepsilon _{0}}$$
A sliding rod AB of resistance R is shown in the figure. Here magnetic field B is constant and is Out of the paper. Parallel wires have no resistance and the rod is moving with Constant velocity v. The current in the sliding rod AB in the function of t, when switch S is closed at time t = 0 is
942497_9c0413e3e8bc45be814b8b7575bc1d11.png
  • $$\left(\dfrac{vBd}{R}\right )e^{-t/C}$$
  • $$\left(\dfrac {vBd}{R} \right)e^{-t/RC}$$
  • $$\left(\dfrac {vBd}{R}\right )e^{RtC}$$
  • $$\left(\dfrac {vBd}{R}\right )e^{t/RC}$$
In a quark model of elemetary particles, a neutron is made of one up quark of charge $$\cfrac{2}{3}e$$ and two down quark of charges $$\left( -\cfrac { 1 }{ 3 } e \right) $$. If they have a triangle configuration with side length of the order of $${ 10 }^{ -15 }m$$. The electrostatic potential energy of neutron in $$MeV$$ is
  • $$7.68$$
  • $$-5.21$$
  • $$-.048$$
  • $$9.34$$
The gravitational field strength $$\vec {E}$$ and gravitational potential $$V$$ are related as $$\vec {E} = -\left (\dfrac {\partial V}{\partial x} \hat {i} + \dfrac {\partial V}{\partial y} \hat {j} + \dfrac {\partial V}{\partial z}\hat {k}\right )$$
In the figure, transversal lines represent equipotential surfaces. A particle of mass $$m$$ is released from rest at the origin. The gravitational unit of potential, $$1\overline {V} = 1\ cm^{2}/ s^{2}$$.
X-component of the velocity of the particle at the point $$(4cm, 4cm)$$ is
1013885_a8cc92d0bfe14fca9dca1252d62ce791.jpg
  • $$4\ cm/s$
  • $$2\ cm/s$$
  • $$2\sqrt {2} \dfrac {cm}{s}$$
  • $$1\ cm/s$$
A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by $${Q}_{0}, {V}_{0}, {E}_{0},$$ and $${U}_{0}$$ respectively. A dielectric slab is now introduced to fill the space between the plates with the battery still in connection. The corresponding quantities now given by $$Q, V, E$$ and $$U$$ are related to the previous one as
  • $$Q>{ Q }_{ 0 }$$
  • $$V>{ V }_{ 0 }$$
  • $$E>{ E }_{ 0 }$$
  • $$U>{ U }_{ 0 }$$
A parallel plate capacitor of plate area $$A$$ and plate separation $$d$$ is charged to potential difference $$V$$ and then the battery is disconnected. A slab of dielectric constant $$K$$ is then inserted between the plate of the capacitor so as to fill the space between the plates. If $$Q, E$$ and $$W$$ denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab inserted), and work done on the system, in question, in the process of inserting the slab, then
  • $$ Q=\dfrac { { \varepsilon }_{ 0 }AV }{ d }$$
  • $$ Q=\dfrac { { \varepsilon }_{ 0 }KAV }{ d }$$
  • $$ E=\dfrac { V }{ Kd }$$
  • $$ W=\dfrac { { \varepsilon }_{ 0 }{ AV }^{ 2 } }{ 2d } \left[ 1-\dfrac { 1 }{ K } \right]$$
Two point charges placed 3m apart, have a combined charge 20 $$\mu $$C. Find the two charges if they repeleach other with a force 0.075 N.
  • 25$$\mu $$C, -5$$\mu $$C
  • 30 $$\mu $$C, 10$$\mu $$C
  • 30$$\mu $$C, 50$$\mu $$C
  • 15 $$\mu $$C, 5$$\mu $$C
A capacitor of $$2F$$ is charged as shown in the diagram. When the switch $$S$$ is tuned to position $$2$$, the percentage of its stored energy dissipated is :
1026361_65016fc38bb3483c97125749ac59e07d.png
  • $$80$$ %
  • $$0$$ %
  • $$20$$ %
  • $$75$$ %
The gravitational field strength $$\vec {E}$$ and gravitational potential $$V$$ are related as $$\vec {E} = -\left (\dfrac {\partial V}{\partial x} \hat {i} + \dfrac {\partial V}{\partial y} \hat {j} + \dfrac {\partial V}{\partial z}\hat {k}\right )$$
In the figure, transversal lines represent equipotential surfaces. A particle of mass $$m$$ is released from rest at the origin. The gravitational unit of potential, $$1\overline {V} = 1\ cm^{2}/ s^{2}$$.
Speed of the particle $$(v) (y$$ is in cm $$v$$ is in $$cm/s$$) as function of its y-co-ordinate is
1013886_26378f80e0214e4cbc577b8d8ee065ae.png
  • $$v = 2\sqrt {y}$$
  • $$v = \sqrt {2}. y$$
  • $$v = 2y$$
  • $$v = 2y + 4y^{2} + 2y^{2}$$
One plate of a parallel plate capacitor is suspended from a beam of a physical balance as shown in figure. The area of each plate is $$625 \ cm^2$$ and the distance between these plates is $$5 \ mm$$. If an additional mass $$0.04 \ gm$$ is placed in the other pan of the balance, then the potential difference required between the plates to keep it in equilibrium will be:
1065915_07a84453654e4b7bb8321ad96eade01e.png
  • $$150 \ V$$
  • $$188 \ V$$
  • $$225 \ V$$
  • $$310 \ V$$
The diagram shows a small bead of mass $$m$$ carrying charge $$q$$. The bead can freely move on the smooth fixed ring placed on a smooth horizontal plan. In the same plane a charge $$+Q$$ has also been fixed as shown. The potential at the point $$P$$ due to $$+Q$$ is $$V$$. The velocity with which the bead should projected from the point $$P$$ so that it can complete a circle should be greater than
1027137_b0383e9bbf7b4f14ae2838cc20e295c1.png
  • $$\sqrt{\dfrac{6qV}{m}}$$
  • $$\sqrt{\dfrac{qV}{m}}$$
  • $$\sqrt{\dfrac{3qV}{m}}$$
  • $$none$$
A uniformly charged solid sphere of radius $$R$$ has potential $$V_{0}$$ (measured with respect to $$\infty$$) on its surface. For this sphere the equipotential surfaces with potentials $$\dfrac {3V_{0}}{2}, \dfrac {5V_{0}}{4}, \dfrac {3V_{0}}{4}$$ and $$\dfrac {V_{0}}{4}$$ have radius $$R_{1}, R_{2}, R_{3}$$, and $$R_{4}$$ respectively. Then
  • $$R_{1} = 0$$ and $$R_{2} > (R_{4}\ R_{3})$$
  • $$R_{1} \neq 0$$ and $$(R_{2}\ R_{1}) > (R_{4}\ R_{3})$$
  • R$$_{1} = 0$$ and $$R_{2} < (R_{4}\ R_{3})$$
  • $$2R < R_{4}$$
A dipole of $$2 \mu C$$ charges each, consists of the positive charge at the point $$P(1, -1)$$ and the negative charge is placed at the point $$Q(-1, 1)$$. The work done in displacing a charge of $$+1 \mu C$$ from point $$A(-3, -3)$$ to $$B(4, 4)$$ is:
  • $$1.6 \times 10^{-19}J$$
  • $$3.2 \times 10^{-19}J$$
  • zero
  • $$4.8 eV$$
Two equal charges $$q$$ are placed at a distance of $$2a$$ and a third charge $$-2q$$ is placed at the midpoint. The potential energy of the system is
  • $$\dfrac { { q }^{ 2 } }{ 8\pi { \varepsilon }_{ 0 }a } $$
  • $$\dfrac { 6{ q }^{ 2 } }{ 8\pi { \varepsilon }_{ 0 }a } $$
  • $$-\dfrac { 7{ q }^{ 2 } }{ 8\pi { \varepsilon }_{ 0 }a } $$
  • $$\dfrac { 9{ q }^{ 2 } }{ 8\pi { \varepsilon }_{ 0 }a } $$
The variation of potential with distance $$R$$ from a fixed point is as shown below. A charge $$q$$ is put at $$R=3\ m$$ and released. The charge will 
1033045_81fb2872e3bd46e899e2f83cce9b9400.png
  • Move away from origin
  • Move towards the origin
  • Not move
  • Trace a circular path
The electric potential at a point in free space due to a charge $$Q$$ coulomb is $$Q\times {10}^{11}V$$. The electric field at that point is 
  • $$4\pi { \varepsilon }_{ 0 }Q\times { 10 }^{ 22 }V/m$$
  • $$127\pi { \varepsilon }_{ 0 }Q\times { 10 }^{ 20 }V/m$$
  • $$4\pi { \varepsilon }_{ 0 }Q\times { 10 }^{ 20 }V/m$$
  • $$12\pi { \varepsilon }_{ 0 }Q\times { 10 }^{ 22 }V/m$$
The distance between electric charges $$1\mu C$$ and $$3\mu C$$ is $$8m$$. What is the electric potential at a point on the line joining them where the electric field is zero? ($$k=9\times {10}^{9}$$ SI)
  • $$9\times {10}^{2}$$
  • $$9\times {10}^{3}$$
  • $$9\times {10}^{4}$$
  • $$9\times {10}^{5}$$
A dielectric slab of thickness $$d$$ inserted in a parallel plate capacitor whose negative plate is at $$x=0$$ and   positive plate is at $$x=3d$$.  The slab is equidistant from the plates. The capacitor is given some charge .As $$x$$ goes from $$0$$ to $$3d$$:
  • $$The\ magnitude\ of\ the\ elecrtric\ field\ remains\ the\ same.$$
  • $$The\ direction\ of\ the\ electric\ field\ remains\ the\ same.$$
  • $$The\ electric\ potential\ increases\ continuously.$$
  • $$The\ electric\ potential\ increase\ at\ first\, then\ decreases\ and\ again\ increases.$$
The capacity of a parallel plate capacitor formed by the plates of same are A is 0.02$$\mu F$$ with air as dielectric. Now one plate is replaced by a plate of area 2A and dielectric (K = 2) is introduced between the plates, the capacity is :
  • 0.04 $$
    \mu F
    $$
  • 0.08$$
    \mu F
    $$
  • 9.91 $$
    \mu F
    $$
  • 2 $$
    \mu F
    $$
$$4\ \mu F$$ and $$6\ \mu F$$ capacitors are joined in series and $$500\ v$$ are applied between the outer plates of the system. What is the charge on each plate ?
  • $$1\cdot 2\times 10^{3}\ C$$
  • $$6\cdot 0\times 10^{3}\ C$$
  • $$5\cdot 0\times 10^{-3}\ C$$
  • $$2\cdot 0\times 10^{-3}\ C$$
Select the correct statements:
  • The electric lines of force are always closed curves.
  • Electric line of forced is parallel to equipotential surface
  • Electric line of force is perpendicular to equipotential surface.
  • Electric line of force is always the path of a positively charged particle.
Three long concentric cylindrical shells have radii R, 2R and $$2\sqrt{2}R$$. Inner and outer shells are connected to each other. The capacitance across middle and inner shells per unit length is:
  • $$\dfrac{\dfrac{1}{3}\epsilon_0}{ln 2}$$
  • $$\dfrac{6\pi \epsilon_0}{ln 2}$$
  • $$\dfrac{\pi \epsilon_0}{2 ln 2}$$
  • None
The capacitance of a capacitor is $$10F$$. The potential difference on it is $$50V$$. If the distance between its plate is halved, What will be the potential difference now?
  • $$100V$$
  • $$50V$$
  • $$25V$$
  • $$75V$$
Four condenser each of capacity $$4\mu F$$ are connected as shown in figure $${V_p} - {V_q} = 15$$ volts. The energy stored in the system is 
1044004_204a0377a24f4669b820253058f5b808.png
  • $$2400$$ ergs
  • $$1800$$ ergs
  • $$3600$$ ergs
  • $$5400$$ ergs
Two condensers of capacity $$0.3 \mu F$$ and $$0.6 \mu F$$ respectively are connected in series. The combination is connected across a potential of $$6$$ volts. The ratio of energies stored by the condensers will be:
  • $$\dfrac {1}{2} $$
  • $$2$$
  • $$\dfrac {1}{4}$$
  • $$4$$
Two materials of dielectric constants $$k_1\, and \, k_2$$ are introduced to fill the space between the two parallel plates of a capacitor as shown in the figure. The capacitance of the capacitor is : 
1110672_dc750a7667cc48519e3fe7fc1c8bfb4d.png
  • $$\dfrac{{A{ \in _0}\left( {{k_1} + {k_2}} \right)}}{{2d}}$$
  • $$\dfrac{{2A{ \in _0}}}{d}\left( {\dfrac{{{k_1}{k_2}}}{{{k_1} + {k_2}}}} \right)$$
  • $$\dfrac{{A{ \in _0}}}{d}\left( {\dfrac{{{k_1}{k_2}}}{{{k_1} + {k_2}}}} \right)$$
  • $$\dfrac{{A{ \in _0}\left( {{k_1} + {k_2}} \right)}}{{2d{k_1}{k_2}}}$$
A parallel plate capacitor is made of two dielectric blocks in series. One of the blocks has thickness $$d_{1}$$ and dielectric constant $$k_{1}$$ and the other has thickness $$d_{2}$$ and dielectric constant $$k_{2}$$ as shown in fig. This arrangement can be thought as a dielectric slab of thickness $$d=d_{1}+d_{2}$$ and effective dielectric constant $$k$$. The $$k$$ is then :
1077587_5d2711f63bad4e33bd66eacedf160a2e.png
  • $$\dfrac{k_{1}d_{1}+k_{2}d_{2}}{d_{1}+d_{2}}$$
  • $$\dfrac{k_{1}d_{1}+k_{2}d_{2}}{k_{1}+k_{2}}$$
  • $$\dfrac{k_{1}k_{2}(d_{1}+d_{2})}{k_{1}d_{2}+k_{2}d_{1}}$$
  • $$\dfrac{2k_{1}k_{2}}{k_{1}+k_{2}}$$
Electrical potential in an electric field is given by V=K/r (K being constant). If the position vector $$\underset{r}{\rightarrow}=2\widehat{i}+3\widehat{j}+6\widehat{k}$$ , then the electric field will be 
  • $$\dfrac{2\widehat{i}+3\widehat{j}+6\widehat{k}}{243}K$$
  • $$\dfrac{2\widehat{i}+3\widehat{j}+6\widehat{k}}{343}K$$
  • $$\dfrac{3\widehat{i}+2\widehat{j}+6\widehat{k}}{243}K$$
  • $$\dfrac{3\widehat{i}+2\widehat{j}+6\widehat{k}}{343}K$$
Capacitance $$C_1 = 2 C_2 = 2C_3$$ and potential difference across $$C_1, C_2$$ and $$C_3$$ are $$V_1, V_2$$ and $$V_3$$ respectively then:
1103108_4c4e28ef1a1c427d9862cca4c20b32bc.png
  • $$V_1 = V_2 = V_3$$
  • $$V_1 = 2V_2 = 2V_3$$
  • $$2V_1 = V_2 = V_3$$
  • $$2V_1 = 2V_2 = V_3$$
A parallel-plate capacitor of plate area $$A$$ and plate separation $$d$$ is charged to a potential difference and then the battery is disconnected. A slab of dielectric constant $$K$$ is then inserted between the plates of the capacitor so as to fill the whole space between the plates. Find the work done on the system the process of inserting the slab.
  • $$\dfrac{\varepsilon_0AV^2}{2d}\left({{1}-{\dfrac{1}{K}}}\right)$$
  • $$\dfrac{\varepsilon_0AV^2}{d}\left(\dfrac{1}{K}-1\right)$$
  • $$\dfrac{\varepsilon_0AV^2}{2d}\left(\dfrac{1}{K}+1\right)$$
  • $$\dfrac{\varepsilon_0AV^2}{d}\left(\dfrac{1}{K}+1\right)$$
In the figure show the potential difference between hollow spheres $$A$$ and $$B$$ is:-
1091638_c04bd368dc964abb87290fa68a005a84.JPG
  • zero
  • $$- \dfrac{q}{16 \pi \varepsilon_0 R}$$
  • $$\dfrac{q}{16 \pi \varepsilon_0 R}$$
  • $$\dfrac{- q}{24 \pi \varepsilon_0 R}$$
Consider a capacitor-charging circuit. Let $$Q_1$$ be the charge given to the capacitor in a time interval of $$10ms$$ and $$Q_2$$ be the charge given in the next time interval of $$10ms$$. Let $$10 \mu C$$ charge be deposited in a time interval $$t_1$$ and the next $$10 \mu C$$ charge is deposited in the next time interval $$t_2$$.
  • $$Q_1 > Q_2, \, t_1 > t_2$$
  • $$Q_1 > Q_2, \, t_1 < t_2$$
  • $$Q_1 < Q_2, \, t_1 > t_2$$
  • $$Q_1 < Q_2, \, t_1 < t_2$$
The potential difference between points $$A$$ and $$D$$ in the given circuit is:-
1121036_925ce5f59c2542a7af8bf486e821266f.PNG
  • $$\dfrac{2}{3}V$$
  • $$\dfrac{8}{9}V$$
  • $$\dfrac{4}{3}V$$
  • $$2V$$
Two long straight wires equal cross- sectional radii $$a$$ are located parallel to each other in air. The distance between their axes equal $$b$$. Find the mutual capacitance of the wire per unit length under the condition $$b>>a$$.
  • $$C=\dfrac{\pi\varepsilon _0}{ln(b/a)}$$
  • $$C=\dfrac{\pi \varepsilon _0}{ln(a/b)}$$
  • $$C=\pi/\varepsilon _0In(b/a)$$
  • $$C=\pi\varepsilon_0ln(ba)$$
what is the series combination of condenses and $$\dfrac { 1 }{ c } =\dfrac { 1 }{ { c }_{ 1 } } +\dfrac { 1 }{ { c }_{ 2 } } +\dfrac { 1 }{ { c }_{ 3 } } $$ farad
  • True
  • False
A point charge +Q is located at out side point, at a distance of r from the centre of an uncharged conducting sphere of radius R. Find the electric field and electric potential at the centre of the sphere due to induced charges on the sphere ?
  • $$\frac { 1 }{ 4\pi { \epsilon }_{ 0 } } \quad \frac { Q }{ { R }^{ 2 } } $$ and Zero
  • Zero and $$\frac { 1 }{ 4\pi { \epsilon }_{ 0 } } \quad \frac { Q }{ { R } } $$
  • $$\frac { 1 }{ 4\pi { \epsilon }_{ 0 } } \quad \frac { Q }{ { R }^{ 2 } } $$ and $$\frac { 1 }{ 4\pi { \epsilon }_{ 0 } } \quad \frac { Q }{ { R } } $$
  • Zero and Zero
The potential at a point x (measured in $$\mu m$$ ) due to some charges situated on the x -axis is given by $$V(x) =\dfrac{20}{(x^{2} -4)}$$ volt. The electric field $$E$$ at $$x = 4\mu m$$ is given by
  • $$\left(\dfrac{10}{9}\right) V\mu m^{-1}$$ and in the +ve x direction
  • $$\left(\dfrac{5}{3}\right) V\mu m^{-1}$$ and in the -ve x direction
  • $$\left(\dfrac{5}{3}\right) V\mu m^{-1}$$ and in the +ve x direction
  • $$\left(\dfrac{10}{9}\right) V\mu m^{-1}$$ and in the -ve x direction
A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The slab is equidistant from the plates. The capacitor is given some charge. As x goes  from 0 to 3 d:  
  • The magnitude of the electric field remains the same
  • The direction of the electric field remains the same
  • the electric potential increase continuously.
  • The electric potential increase at first, then decreases and again increase
The electric potential in a certain region is expressed by $$V = 6x-8xy^2-8y + 6yz - 4z^2$$ volts. The magnitude of the force acting on a charge of $$2C$$ sityuated at the origin wil be:-
  • $$2N$$
  • $$6N$$
  • $$8N$$
  • $$20N$$
Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is $$2\times\ 10^5\ V/m$$. When the space is filled with dielectric, the electric field becomes $$1\times\ 10^5\ V/m$$. The dielectric constant of a dielectric material is:
  • $$1/2$$
  • $$1$$
  • $$2$$
  • $$3$$
A capacitor 1 mF withstands a maximum voltage of 6KV while another capacitor 2 mF withstands a maximum voltage of 4 KV. If the capacitors are connected in series, the system will withstand a maximum voltage of (MNR)
  • 2 KV
  • 4 KV
  • 6 KV
  • 9 KV
Three point charges of $$1C, 2C$$ and $$3C$$ are placed at the corners of an equilateral triangle of side $$100\ cm$$. The work done to move these charges to the corners of a similar equilateral triangle of side $$50\ cm$$, will be
  • $$9.9\times 10^{10}J$$
  • $$9.9\times 10^{9}J$$
  • $$5.2\times 10^{10}J$$
  • $$5.9\times 10^{9}J$$
In the figure a potential of +1200 V is given to point A and point B is earthed,what is the potential at the point P
1212347_a4f4e177c47b4a6c82f531568a60660f.png
  • 100 V
  • 200 V
  • 400 V
  • 600 V
A straight conductor of length $$l$$ carrying a current t, is bent in the form of a semi-circle, The magnetic field in tesla at the center of the semi-circle is.
  • $$\frac{{{\pi ^2}i}}{l} \times {10^{ - 7}}$$
  • $$\frac{{i\pi }}{l} \times {10^{ - 7}}$$
  • $$\frac{{i\pi }}{{{l^2}}} \times {10^{ - 7}}$$
  • $$\frac{{{\pi ^2}}}{l} \times {10^{ - 7}}$$
  • None of the above.
A parallel plate capacitor has plate area $$A$$ and separation  $$ d$$. It is charged to a potential difference $$V_0$$. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is:
  • $$\dfrac{3\epsilon_0 AV_0^2}{d}$$
  • $$\dfrac{\epsilon_0 AV_0^2}{2d}$$
  • $$\dfrac{\epsilon_0 AV_0^2}{3d}$$
  • $$\dfrac{\epsilon_0 AV_0^2}{d}$$
A thin metal plate P is inserted half way between the plates of a parallel plate capacitor of capacitance C in such a way that it is parallel to the two plates. The capacitance now becomes 
  • C
  • C/2
  • 4C
  • None of these
In given circuit when switch $$S$$ has been closed then charge on capacitor $$A$$ & $$B$$ respectively

1202068_1becc4ff245849a1affaa348aa596399.png
  • $$3\ q, 6\ q$$
  • $$6\ q,3\ q$$
  • $$4.5\ q, 4.5\ q$$
  • $$5,4\ q,4\ q$$
Two condemners of capacity $$0.3\mu\ F$$ and $$0.6\mu\ F$$ respectively are connected in series. The combination is connected across a potential  of $$6\ volts$$. The ratio  of energies stared by the condensers will be
  • $$\dfrac{1}{2}$$
  • $$2$$
  • $$\dfrac{1}{4}$$
  • $$4$$
A parallel plate capacitor consist of two circular plates each of radius 2 cm, separated by a distance of 0.1 mm. If voltage across the plates is varying at the rate of $$5 \times {10^{13}}V{s^{ - 1}}$$ , then the value of displacement current is:
  • $$5.50A$$ 
  • $$ 5.56 \times 10^2 A $$
  • $$ 5.56 \times 10^3 A $$
  • $$ 2.28 \times 10^4 A $$
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Practice Class 12 Medical Physics Quiz Questions and Answers