Two magnetic poles one of which is three times as strong as the other exert on each other, a force equal to $$3×10^{−3}$$ when separated by a distance of $$10\ cm$$. The strength of the each pole is
Explanation
When a diamagnetic liquid is poured into a U-tube and one arm of the U-tube is placed between the two poles of strong magnet with the meniscus along the lines of the field, then the level of the liquid in the arm where magnetic field is applied will
A sensitive magnetic instrument can be shielded very effectively from outside magnetic fields by placing it inside a box of:
Two magnetic poles have their strengths in the ratio 3 :They are kept at a distance of 0.6 m in air and the force of repulsion is found to be 0.06 dynes. The pole strengths are (in amp. m)
The pole strength of a bar magnet is 2 Am. If the field at poles are 0.2 T and 0.22 T, then the force acting on the bar magnet is
( consider field direction to be same)
A bar Magnet of Magnetic Moment 3.0 amp.m$$^{2}$$ is placed in a uniform Magnetic induction field 2 x 10$$^{-5}$$ T. If each pole of the magnet experience a force of 6 x 10$$^{-4}$$ N, the length of the magnet is
Two magnetic poles of strengths 10 Am and 20 Am are separated by a distance of 10 cm. The ratio of force on them is
Two poles of same strength attract each other with a force of magnitude $$F$$ when placed at the corners of an equilateral triangle. If a north pole of the same strength is placed at the third vertex, it experiences a force of magnitude
Correct answer: Option B
Hint: Two poles of same strength attract each other with force F so here two poles must be of opposite nature
Step 1:Finding magnitude of Force
If the north pole is placed within the triangle's third corner, one of the corners will exert an attraction force on that, whereas the opposite can exert a repulsion force. As a result, two forces of equal magnitude F will act on the third corner, which is at a 120-degree angle to each other.
So the resultant of two forces is given as
$${F_{net}} = \sqrt {{F^2} + {F^2} + 2(F)(F)\cos 120} $$
$${F_{net}} = \sqrt {{F^2} + {F^2} - {F^2}} $$
$${F_{net}} = F$$
So the force of magnitude is equal to F
Relative permittivity and permeability of a material are $$\varepsilon _{r}$$ and $$\mu _{r}$$ respectively. The values of these quantities allowed for a diamagnetic material are
Substances in which the magnetic moment of a
single atom is not-zero
Please disable the adBlock and continue. Thank you.