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CBSE Questions for Class 12 Medical Physics Moving Charges And Magnetism Quiz 12 - MCQExams.com

An electron is projected into a magnetic field of B=5×103T and rotates in a circle of radius of R=3 mm. Find the work done by the force due to magnetic field.
  • 0 J
  • 15 mJ
  • 14 mJ
  • 20 mJ
A magnetic field B=B0ˆj exists in the region a <x<2a and B=B0ˆj , in the region 2a<x<3a, where B0 is a positive constant. A positive point charge moving with a velocity v=v0ˆi, where v0 is a positive constant, enters the magnetic field at x=a. The trajectory of the charge in this region can be like, 


42471.jpg

A bar magnet of magnetic moment M is divided into 'n' equal parts by cutting parallel to length. Then one part is suspended in a uniform magnetic field of strength 2T and held making an angle 600 with the direction of the field. When the magnet is released, the kinetic energy of the magnet in the equilibrium position is:

  • MnJ
  • Mn J
  • Mn2J
  • Mn2 J
A charged particle q is moving with a velocity v1=2ˆim/s  at a point in a magnetic field B and experiences a force F1=q(ˆk2ˆj)N. If the same charge moves with velocity v2=2ˆjm/s from the same point in that magnetic field and experiences a force F2=q(2ˆi+ˆk)N,  the magnetic induction at that point will be :
  • ˆi+12ˆj12ˆk
  • 12ˆi+12ˆj+ˆk
  • 12ˆi+12ˆj+ˆk
  • 12ˆi+ˆj+12ˆk
The magnitude of force per unit length on a wire carrying current I at O due to two semi infinite wires as shown in figure, (if the distance between the long parallel segments of the wire being equal to L and current in them is I) is:

24049.png
  • \dfrac{+\mu_{0}I^{2}}{\pi L}\hat{j}
  • \dfrac{-\mu_{0}I^{2}}{L}\hat{j}
  • \dfrac{\mu_{0}I^{2}}{2L}\hat{j}
  • \dfrac{\mu_{0}I^{2}}{L}\hat{j}
The magnetic field due to a current carrying square loop of side a at a point located symmetrically at a distance of \mathrm{a}/2 from its centre (as shown in figure):

42292.jpg
  • \displaystyle \dfrac{\sqrt{2}\mu_{0}\mathrm{i}}{\sqrt{3}\pi \mathrm{a}}
  • \displaystyle \dfrac{\mu_{0}\mathrm{i}}{\sqrt{6}\pi \mathrm{a}}
  • \displaystyle \dfrac{2\mu_{0}\mathrm{i}}{\sqrt{3}\pi \mathrm{a}}
  • zero
A planar coil of area 7 \mathrm{m}^{2} carrying an anti-clockwise current 2 A is placed in an extemal magnetic field \vec{B}=(0.2\hat{i}+0.2\hat{j}-0.3\hat{k}), such that the normal to the plane is along the line(3\hat{i}-5\hat{j}+4\hat{k}). Select correct statements from the following .  ( Consider Normal of the coil and Magnetic moment vectors to be in  the same direction ) 
  • The potential energy of the coil in the given orientation is 6.4 J
  • The angle between the normal (positive) to the coil and the external magnetic field is \cos^{-1}\ (0.57)
  • The potential energy of the coil in the given orientatlon is 3.2 J
  • The magnitude of magnetic moment of the coil is about 14 A{m}^{2}
A charged particle having charge q experiences a force \vec{F}=q(-\vec{j}+\vec{k})N in a magnetic field B when it has a velocity v_{1} = 1\hat i \ m/s. The force becomes \vec{F}=q(\vec{i}-\vec{k})N when the velocity is changed to v_{2}=1\hat{j}m/sec. The magnetic induction vector at that point is :
  • (\hat{i}+\hat{j}+\hat{k})\ T
  • (\hat{i}-\hat{j}-\hat{k})\ T
  • (-\hat{i}-\hat{j}+\hat{k})\ T
  • (\hat{i}+\hat{j}-\hat{k})\ T
A charged particle A of charge q = 2 C has velocity v = 100 m/s. When it passes through point A and has  velocity in the direction shown. The strength of magnetic field at point B due to this moving charge is (r = 2 m).the agle between them is 30.

42293_a3c6da88eb52467ead7e1a4036060562.png
  • 2.5\muT
  • 5.0\muT
  • 2.0\muT
  • None
An \alpha particle is moving along a circle of radius R with a constant angular velocity \omega. Point A lies in the same plane at a distance 2R from the centre. Point A records magnetic field produced by \alpha particle. If the minimum time interval between two successive times at which A records zero magnetic field is 't', the angular speed \omega , in terms of t is 
  • \displaystyle \frac{2\pi }{t}
  • \displaystyle \frac{2\pi }{3t}
  • \displaystyle \frac{\pi }{3t}
  • \displaystyle \frac{\pi }{t}

An electric motor is a device to convert electrical energy into mechanical energy. The motor shown below has a rectangular coil (15\ cm \times 10\ cm) with 100 turns placed in a uniform magnetic fleld B=2.5\ T. When a current is passed through the coil, lt completes 50 revolutions in one second. the power output of the motor is 1.5\ kW. The current rating of the coil should be



44469.jpg
  • 1 A
  • 2 A
  • 3 A
  • 4 A
A thin rod of mass m and length l has charge Q, distributed uniformly along its length. It is rotated with angular speed \omega in horizontal plane about an axis, passing through the mid-point and perpendicular to its length. If in the presence of an external magnetic field B_{o} oriented along the axis of rotation, the total kinetic energy of the rod is reduced to zero, then the angular speed of the rod must be :
  • \dfrac{QB_{o}}{2m}
  • \dfrac{2QB_{o}}{m}
  • \dfrac{QB_{o}}{m}
  • \dfrac{QB_{o}}{4m}
When a particle of charge q is projected with uniform speed u along x - axis of the Cartesian coordinate system \left ( \hat{i},\hat{j},\hat{k} \right ) in the presence of a magnetic field of induction \vec{B}, the force on q is \vec{F}=\frac{qu\vec{B}}{2}\hat{j} and when the particle is projected along y - axis with same speed, the force \vec{F}=\frac{qu\vec{B}}{2}\left ( -\hat{i}+\sqrt{3}\hat{k} \right ). The magnetic field \vec{B} is
  • \frac{B}{2}(\sqrt{3}\hat{i}+\hat{k})
  • \frac{B}{2}(\sqrt{3}\hat{i}-\hat{k})
  • -\frac{B}{2}(\sqrt{3}\hat{i}+\hat{k})
  • \frac{B}{2}(-\sqrt{3}\hat{i}+\hat{k})
A ring or radius R moves with a velocity v in a unifrom static magnetic field B as shown in diagram. The emf between P and Q is
1092989_3f79b37a22084b789e382c4aca89521c.png
  • zero
  • vBR(1-\cos \theta)
  • 2vBR\sin \dfrac {\theta}{2}
  • vB \sin\theta
A charged particle A of charge q = 2\ C has velocity v = 100 \ m/s. When it passes through point A and has velocity in the direction shown, the strength of magnetic field at point B due to this moving charge is (r = 2\ m)

76343.png
  • 2.5\ \mu T 
  • 5.0\ \mu T
  • 2.0\ \mu T
  • none\ of\ these
A charged particle moves through a magnetic field in a direction perpendicular to it. Then the
  • Speed of the particle remains unchanged
  • Direction of the particle remains unchanged
  • Acceleration remains unchanged
  • Velocity remains unchanged
A positive charge particle with velocity \overrightarrow{v} = x\hat{i} + y\hat{j} moves in a magnetic field \overrightarrow{B} = y\hat{i} + x\hat{j}. The magnitude of magnetic force acting on the particle is F. Which one of the following statements are correct ?
  • no force will act on particle if x = y
  • F \propto (x^2 - y^2) if x > y
  • the force will act along positive Z-axis if x > y
  • the force will act along positive Z-axis if y > x
A Positive charge particle with velocity \vec v=x\hat i+y\hat j moves in a magnetic field \vec B=y\hat i+x\hat j. The magnitude of magnetic force acting on the particles is F. Which one of the following statements are correct :
  • no force will act on particle of x = y
  • F\propto (x^2-y^2) if x > y
  • the force will act along positive Z-axis if x > y
  • the force will act along positive Z-axis if y > x
The field created by the current in the loop at point C will be
74380.png
  • -\dfrac{\mu _{0} }{4\pi }\hat{k}
  • -\dfrac{\mu _{0} }{8\pi }\hat{k}
  • -\dfrac{\mu _{0}\sqrt{2} }{\pi }\hat{k}
  • none
A charged particle is kept at rest in a uniform magnetic field. If the magnetic field increases with time, 
  • the particle starts moving
  • the particle undergoes circular motion
  • the particle starts moving in opposite direction
  • None of the above
The radius of the curved part of the wire is R=100\:mm, the linear parts of the wire are very long. Find the magnetic induction at the point O if the wire carrying a current I=8.0\:A has the shape shown in figure.
144843_c9ba9b4452f549f290ae745fc042154f.png
  • \displaystyle 0.34\:\mu T
  • \displaystyle 0.11\:\mu T
  • \displaystyle 1.1\:\mu T
  • \displaystyle 34\:\mu T
The radius of the curved part of the wire is R=100\:mm, the linear parts of the wire are very long. Find the magnetic induction at the point O if the wire carrying a current I=8.0\ A has the shape shown in figure.
144841_2fd978e7d32944af8e2645d0291e330b.png
  • 0.44\:\mu T
  • 0.34\:\mu T
  • 0.56\:\mu T
  • 0.78\:\mu T
A charge particle of charge q is moving with speed v in a circle of radius R as shown in figure. Then the magnetic field at a point on axis of circle at a distance x from centre is :

77198.jpg
  • \dfrac{\mu _{0}}{4\pi }\dfrac{qV}{R^{2}}
  • \dfrac{\mu _{0}}{4\pi }\dfrac{qV}{(R^{2}+x^{2})}
  • \dfrac{\mu _{0}}{4\pi }\dfrac{qV}{x^{2}}
  • \dfrac{\mu _{0}}{4\pi }\dfrac{qVR}{(R^{2}+x^{2})^{3/2}}
The potential energy for a force field \vec {F} is given by U(x,y)=\sin(x+y). The force acting on the particle of mass m at \left(0,\dfrac {\pi}{4}\right) is
  • 1
  • \sqrt {2}
  • \dfrac {1}{\sqrt {2}}
  • 0
A non conductive insulating ring of mass m and radius R, having charge Q uniformly distributed over it's circumference is hanging by a insulated thread with the help of a small smooth ring (not rigidly fixed with bigger ring). A time varying magnetic field B=B_0 \sin \omega t is switched at t=0 and ring is released at the same time. The average magnetic moment of Ring in time interval 0 is:

77083.jpg
  • \dfrac {B_0q^2R^2}{2\pi m}
  • \dfrac {B_0q^2R^2}{4\pi m}
  • \dfrac {B_0q^2R^2}{\pi m}
  • zero
The magnetic field B at the centre of a circular coil of radius r is \pi times that due to a long straight wire at a distance r from it, for equal currents. The following diagram shows three cases. In all cases the circular part has radius r and straight ones are infinitely long. For the same current the field B at centre P in cases 1, 2, 3 has the ratio :

143606_ce1fcb87563e476bb841190c96ae32e8.png
  • \left (-\dfrac {\pi}{2}\right ):\left (\dfrac {\pi}{2}\right ):\left (\dfrac {3\pi}{4}-\dfrac {1}{2}\right )
  • \left (-\dfrac {\pi}{2}+1\right ):\left (\dfrac {\pi}{2}+1\right ):\left (\dfrac {3\pi}{4}+\dfrac {1}{2}\right )
  • \left (-\dfrac {\pi}{2}\right ):\left (\dfrac {\pi}{2}\right ):\left (\dfrac {3\pi}{4}\right )
  • \left (-\dfrac {\pi}{2}-1\right ):\left (\dfrac {\pi}{2}-\dfrac {1}{4}\right ):\left (\dfrac {3\pi}{4}+\frac {1}{2}\right )
L is a circular ring made of a uniform wire. Current enters and leaves the rind through straight conductors which, if produced, would have passed through the centre C of the ring. The magnetic field at C :

143090_8c9cabc4cab2406db41eb988d3ac0649.png
  • due to the straight conductors is zero
  • due to the loop is zero
  • due to the loop is proportional to \theta
  • due to the loop is proportional to (\pi -\theta)
Find the circulation of the vector \vec{B} around the square path T with side l located as shown in the figure above.
145600_4b1ec8fc55ac4c5bb1af5841762e1767.png
  • \displaystyle\oint{\vec{B}dr}=2(1-\mu)Bl\sin{\theta}
  • \displaystyle\oint{\vec{B}dr}=(1+\mu)Bl\sin{\theta}
  • \displaystyle\oint{\vec{B}dr}=2(1-+\mu)Bl\sin{\theta}
  • \displaystyle\oint{\vec{B}dr}=(1-\mu)Bl\sin{\theta}
The radius of the curved part of the wire is R=100\:mm, the linear parts of the wire are very long. Find the magnetic induction at the point O if the wire carrying a current I=8.0\ A has the shape shown in the figure.
144839_a71ac60f4c2347d583788039a1fef47d.png
  • \displaystyle 0.30\:\mu T
  • \displaystyle 0.60\:\mu T
  • \displaystyle 0\:\mu T
  • \displaystyle 0.70\:\mu T
Velocity and acceleration vector of a charged particle moving in a magnetic field at some instant are \overrightarrow{v}=3\hat i+4\hat j and \overrightarrow{a}=2\hat i+x\hat j. Select the correct options.
  • x=-1.5
  • x=3
  • Magnetic field has a component along the z-direction
  • Kinetic energy of the particle is constant
A particle of charge per unit mass \alpha is released from origin with velocity \vec v=v_0\hat i in a magnetic field \vec B=-B_0\hat k for x\leq \dfrac {\sqrt 3}{2}\dfrac {v_0}{B_0\alpha} and \vec B=0 for x > \dfrac {\sqrt 3}{2}\dfrac {v_0}{B_0\alpha}. The x-coordinate of the particle at time t\left ( > \dfrac {\pi}{3B_0\alpha}\right ) would be
  • \displaystyle \frac {\sqrt 3}{2}\frac {v_0}{B_0\alpha}+\frac {\sqrt 3}{2}-v_0\left (t-\frac {\pi}{B_0\alpha}\right )
  • \displaystyle \frac {\sqrt 3}{2}\frac {v_0}{B_0\alpha}+v_0\left (t-\frac {\pi}{3B_0\alpha}\right )
  • \displaystyle \frac {\sqrt 3}{2}\frac {v_0}{B_0\alpha}+\frac {v_0}{2}\left (t-\frac {\pi}{3B_0\alpha}\right )
  • \displaystyle \frac {\sqrt 3}{2}\frac {v_0}{B_0\alpha}+\frac {v_0t}{2}
A particle having a mass of 0.5 g carries a charge of 2.5\times 10^{-8}C. The particle is given an initial horizontal velocity of 6\times 10^4 ms^{-1}. To keep the particle moving in a horizontal direction
  • the magnetic field may be perpendicular to the direction of the velocity
  • the magnetic field should be along the direction of the velocity
  • magnetic field should have a minimum value of 3.27 T
  • no magnetic field is required
An insulating rod of length l carries a charge q distributed uniformly on it. The rod is pivoted at its mid-point and is rotated at a frequency f about a fixed axis perpendicular to the rod and passing through the pivot. The magnetic moment of the rod system is
  • \dfrac {1}{12}\pi q f l^2
  • \pi qfl^2
  • \dfrac {1}{6}\pi q f l^2
  • \dfrac {1}{3}\pi q f l^2
A charged particle P leaves the origin with speed v=v_0 at some inclination with the x-axis. There is a uniform magnetic field B along the x-axis. P strikes a fixed target T on the x-axis for a minimum value of B=B_0. P will also strike T if
  • B=2B_0, v=2v_0
  • B=2B_0, v=v_0
  • B=B_0, v=2v_0
  • B=\dfrac {B_0}{2}, v=2v_0
A charged particle of specific charge (charge/mass) \alpha is released from origin at time t=0 with velocity \vec v=v_0(\hat i+\hat j) in a uniform magnetic field \vec B=B_0\hat i. Coordinates of the particle at time t=\dfrac{\pi}{B_0\alpha} are
  • \displaystyle\left (\frac {v_0}{2B_0\alpha}, \frac {\sqrt 2v_0}{\alpha B_0}, \frac {-v_0}{B_0\alpha}\right )
  • \displaystyle\left (\frac {-v_0}{2B_0\alpha}, 0, 0\right )
  • \displaystyle\left (0, \frac {2v_0}{B_0\alpha}, \frac {v_0\pi}{2B_0\alpha}\right )
  • \displaystyle\left (\frac {v_0\pi}{B_0\alpha}, 0, \frac {-2v_0}{B_0\alpha}\right )
A long circular tube of length 10\ m and radius 0.3\ m carries a current I along its curved surface as shown. A wire-loop of resistance 0.005\ ohm and of radius 0.1\ m is placed inside the tube with its axis coinciding with the axis of the tube. The current varies as I = I_0\cos (300  t) where I_0 is constant, If the magnetic moment of the loop is N \mu_0 I_0\sin (300  t) then 'N' is
166670.png
  • 6
  • 8
  • 7
  • 4
An electron is moving along the positive x-axis. You want to apply a magnetic field for a short time so that the electron may reverse its direction and move parallel to the negative x-axis. This can be done by applying the magnetic field along :
  • y-axis
  • z-axis
  • y-axis only
  • z-axis only
A charged particle with velocity \overrightarrow{v}=x\hat i+y\hat j moves in a magnetic field \overrightarrow{B}=y\hat i+x\hat j. The force acting on the particle has magnitude F. Which one of the following statements is/are correct?
  • No force will act on charged particle if x=y
  • If x > y, F\propto(x^2-y^2)
  • If x > y, the force will act along z-axis
  • If y > x, the force will act along y-axis
Two very long straight parallel wires carry steady currents i and 2i in opposite directions. The distance between the wires is d. at a certain instant of time, a point charge q is at a point equidistant from the two wires in the plane of the wires. Its instantaneous velocity \vec { v } is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is:
  • \cfrac { { \mu }_{ 0 }iqv }{ 2\pi d }
  • \cfrac { { \mu }_{ 0 }iqv }{ \pi d }
  • \cfrac { { 3\mu }_{ 0 }iqv }{ 2\pi d }
  • zero
Find the magnetic field \vec B.
  • (10^{-3}T)(\hat i+\hat j)
  • (2\times 10^{-3}T)\hat i
  • (10^{-3}T)\hat i
  • (2\times 10^{-3}T)(\hat i_\hat j)
Find the magnitude of the force F_2
  • 10^{-2}\ N
  • 10^{-3}\ N
  • 10^{-4}\ N
  • 10^{-5}\ N

The field B at the centre of a circular coil of radius r is \pi times that due to a long straight wire at a distance r from it for equal currents. The figure shows three cases. In all cases the circular part has radius r and straight ones are infinitely long. For same current, the field B at the centre P in cases 1, 2, 3 has the ratio:
166932.JPG
  • \displaystyle \left ( - \frac{\pi}{2} \right ) : \frac{\pi}{2} : \left ( \frac{3 \pi}{4} - \frac{1}{2} \right )
  • \displaystyle \left ( - \frac{\pi}{2} + 1\right ) : \left ( \frac{\pi}{2}+ 1 \right ) : \left ( \frac{3 \pi}{4} - \frac{1}{2} \right )
  • \displaystyle -\frac{\pi}{2} : \frac{\pi }{2} : \frac{3 \pi}{4}
  • \displaystyle \left ( - \frac{\pi}{2} - 1\right ) : \left ( \frac{\pi}{4}+ \frac{1}{4} \right ) : \left ( \frac{3 \pi}{4} + \frac{1}{2} \right )
A wire is bent in the form of a circular arc with a straight portion AB. Magnetic induction at O when current I is flowing in the wire, is

166713.PNG
  • \cfrac { { { \mu }_{ 0 } } }{ 2r } \left( \pi -\theta +\tan { \theta } \right)
  • \cfrac { { { \mu }_{ 0 } I} }{ 2\pi r } \left( \pi +\theta -\tan { \theta } \right)
  • \cfrac { { { \mu }_{ 0 }I } }{ 2\pi r } \left( \pi -\theta +\tan { \theta } \right)
  • \cfrac { { { \mu }_{ 0 } I} }{ 2\pi r } \left( -\tan { \theta } +\pi -\theta \right)
A long wire bent as shown in figure carries current I. If the radius of the semicircular portion is a, the magnetic field at center C is:

167104.PNG
  • \cfrac { { \mu }_{ 0 }I }{ 4a }
  • \cfrac { { \mu }_{ 0 }I }{ 4\pi a } \sqrt { { \pi }^{ 2 }+4 }
  • \cfrac { { \mu }_{ 0 }I }{ 4a }+\cfrac { { \mu }_{ 0 }I }{ 4\pi a }
  • \cfrac { { \mu }_{ 0 }I }{ 4\pi a } \sqrt { { \pi }^{ 2 }-4 }
Select the correct statement

167139_4fd145fa686f4ca5ba67285fb0e3b681.png
  • At t=\dfrac {T_0}{2}, coordinate of charge are \left (\dfrac {P_0}{2}, 0, -2R_0\right )
  • At t=\dfrac {3T_0}{2}, coordinate of charge are \left (\dfrac {3P_0}{2}, 0, 2R_0\right )
  • At t=\dfrac {T_0}{2}, coordinate of charge are \left (P_0, 0, -2R_0\right )
  • At t=\dfrac {3T_0}{2}, coordinate of charge are \left (3P_0, 0, 2R_0\right )
Figure shows three cases: in all cases the circular part has radius r and straight ones are infinitely long. For the same current the ratio of field B at center P in the three cases {B}_{1}:{B}_{2}:{B}_{3} is :

166815_2e854f77095442acb80315f91da2e25b.png
  • \left( -\cfrac { \pi }{ 2 } \right) :\left( \cfrac { \pi }{ 2 } \right) :\left( \cfrac { 3\pi }{ 4 } -\cfrac { 1 }{ 2 } \right)
  • \left( -\cfrac { \pi }{ 2 } +1 \right) :\left( \cfrac { \pi }{ 2 } +1 \right) :\left( \cfrac { 3\pi }{ 4 } +\cfrac { 1 }{ 2 } \right)
  • \left( -\cfrac { \pi }{ 2 } \right) :\left( \cfrac { \pi }{ 2 } \right) :\left( \cfrac { 3\pi }{ 4 } \right)
  • \left( -\cfrac { \pi }{ 2 } -1 \right) :\left( \cfrac { \pi }{ 2 } -\cfrac { 1 }{ 4 } \right) :\left( \cfrac { 3\pi }{ 4 } +\cfrac { 1 }{ 2 } \right)
An otherwise infinite, straight wire has two concentric loops of radii a and b carrying equal currents in opposite directions as shown in figure. The magnetic field at the common center is zero for:

166818.PNG
  • \cfrac { a }{ b } =\cfrac { \pi -1 }{ \pi }
  • \cfrac { a }{ b } =\cfrac { \pi } { \pi +1 }
  • \cfrac { a }{ b }=\cfrac { \pi -1 }{ \pi +1 }
  • \cfrac { a }{ b }=\cfrac { \pi +1 }{ \pi -1 }
The magnetic field at the center of the  circular loop as shown in figure, when a single wire is bent to form a circular loop and also extends to form straight sections, is :

166813_df485782256b42b2b4a4dbb1144596fd.png
  • \cfrac { { { \mu }_{ 0 } I} }{ 2R } \bigodot
  • \cfrac { { { \mu }_{ 0 } I} }{ 2R }\left( 1+\cfrac { 1 }{ \pi \sqrt { 2 } } \right) \bigodot
  • \cfrac { { { \mu }_{ 0 } I} }{ 2R }\left( 1-\cfrac { 1 }{ \pi \sqrt { 2 } } \right) \bigotimes
  • \cfrac { { { \mu }_{ 0 } I} }{ R }\left( 1-\cfrac { 1 }{ \pi \sqrt { 2 } } \right) \bigotimes
Positive point chages q=+8.00\mu C and q'=+3.00\mu C are moving relative to an observer at point P, as shown in the figure. the distance d is 0.120 m. When the two charges are at the locations as shown in the figure, what are the magnitude and direction of the net magnetic field they produce at point P?
(Take v=4.50\times { 10 }^{ 6 }{ m{ s }^{ -1 }} and v'=9.00\times { 10 }^{ 6 }{ m{ s }^{ -1 }}).

167232.png
  • 4.38\times { 10 }^{ -4 } T, into the page
  • 4.38\times { 10 }^{ -4 } T, out of the page
  • 2.16\times { 10 }^{ -4 } T, into the page
  • 2.9\times { 10 }^{ -9 } T, out of the page
Figure shows an Amperian path ABCDA. Part ABC is in verical plane PSTU while part CDA is in horizontal plane PQRS. Direction of circulation along the path is shown by an arrow near point B and D.
\oint { \vec { B } .d\vec { l }  } for this path according to Ampere's law will be :


167202_0acd2e30dfc54ad59a896586006da0a7.png
  • \left( { I }_{ 1 }-{ I }_{ 2 }+{ I }_{ 3 } \right) { \mu }_{ 0 }
  • \left( -{ I }_{ 1 }+{ I }_{ 2 } \right) { \mu }_{ 0 }
  • { I }_{ 3 }{ \mu }_{ 0 }
  • \left( { I }_{ 1 }+{ I }_{ 2 } \right) { \mu }_{ 0 }
0:0:1


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Practice Class 12 Medical Physics Quiz Questions and Answers