Explanation
Let magnetic field strength be $$B$$
Charge $$q$$
Mass $$m$$ and
Radius of the circular path be $$r$$
$$\vec { B=B\hat { k } } $$
$$\vec { v } =v\cos \theta \hat { i } +v\sin \theta \hat { j } \\ \vec { F } =\left( v\cos \theta \hat { i } +v\sin \theta \hat { j } \right) \times Bq\hat { k } \\ \Rightarrow \vec { F } =Bqv\left( \cos \theta \hat { i } +\sin \theta \hat { j } \right) \\ \theta =\omega t\\ { a }_{ x }=\dfrac { Bqv }{ m } \sin \omega t\\ \dfrac { { d }^{ 2 }x }{ d{ t }^{ 2 } } =\dfrac { Bqv }{ m } \sin \omega t$$
Integrating
$$\Rightarrow x=\dfrac { Bqv }{ m{ \omega }^{ 2 } } \sin \left( \omega t+\theta \right) $$
So magnitude of maximum horizontal displacement suffered by the particle in the field will be
$${ x }_{ max }=\dfrac { Bqv }{ m{ \omega }^{ 2 } } $$
Again,
$${ x }_{ max }=\dfrac { Bqv }{ m{ \omega }^{ 2 } } \\ Bqv=m{ \omega }^{ 2 }r\\ \omega =\dfrac { Bq }{ m } \\ { x }_{ max }=\dfrac { v }{ \omega } $$
$$v=r\omega \\ \Rightarrow { x }_{ max }=r$$
This means for a particle to reach maximum displacement the field must have a minimum length of $$r$$
since length of field is $$1.5r$$ the particle cannot come out of field horizontally so to come out of it must reverse its direction and thus displacement.
Thus the particle will deflect by $$180°$$
Hint: Apply Biot - Savart's law.
Explanation: Step 1: Concept used:
Now let us consider an ampere loop around the cable.
The magnetic field in an ampere loop is calculated as,
$$\oint B.dl$$
Its value is calculated as the product of the magnetic permeability and the current enclosed in the ampere loop. So the magnetic field around the loop will be,
$$\oint Bdl=\mu_oi$$
Step 2: Conclusion:Now, in the cable, current flows in two opposite directions, so,
$$\oint Bdl=\mu_o(i-i)$$
$$0$$
Thus, in a coaxial cable, the magnetic field is zero outside the cable.
The correct answer is (A).
The force between two long parallel conductors separated by distance r, is $$F =\dfrac{\mu_0 (i_1)(i_2)}{2 \pi r}$$
If the current is flowing in the same direction through both conductors, they will attract each other due to magnetic force between the two.
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