Explanation
Given parameters are,
Wavelength $$\lambda = 5000\ A^{\circ}$$
= $$5000 \times 10^{-10}$$
Diameter of telescope, $$D = 10 cm = 0.1 m$$
Now, Angular resolution (d\theta) formula for telescope is,
$$d\theta =\dfrac{1.22 \lambda}{D}\\$$
Substituting the values, we get
$$\Rightarrow d\theta = \dfrac{1.22 \times 5000 \times 10^{-10}}{0.1}= 6.1 \times 10^{-6}\\$$
Clearly it is having significance order of $$10^{-6}$$.
Thus option B is correct.
Please disable the adBlock and continue. Thank you.