Explanation
The Hardy-Weinberg law can be used under some circumstances to calculate genotype frequencies from allele frequencies. Let A1 and A2 be two alleles at the same locus,
According to the Hardy-Weinberg equation, the sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1. Also, the Hardy-Weinberg equation is expressed as: p$$^2$$ + 2pq +q$$^2$$ = 1 where p is the frequency of the "A" allele and q is the frequency of the "a" allele in the population. In the equation, p$$^2$$ represents the frequency of the homozygous genotype AA, q$$^2$$ represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa. Here, q$$^2$$ = 9% = 0.9. From this, q = 0.3. Hence, p = `1- q = 1 - 0.3 = 0.7. Now, population of heterozygous individual will be 2pq as mentioned, that is 2 * 0.7 * 0.3 = 0.42. It means, there is 42% of the heterozygous population. So, from 800 individuals, there will be 800 * 42 /100 = 336 individuals will have heterozygous genotype. Thus, the correct answer is option A.
This time span is isolated into three geologic periods. Following the Paleozoic, the Mesozoic expanded about 186 million years, from 251.902 to 66 million years prior when the Cenozoic Era started.
So, the correct option is 'Palaeozoic → Mesozoic → Cenozoic'.
The main genuine endeavours to figure a geologic time scale that could be connected anyplace on Earth were made in the late eighteenth century. The most powerful of those early endeavours (supported by Werner, among others). The distinguishing proof of strata by the fossils they contained, spearheaded by William Smith, Georges Cuvier, Jean d'Omalius d'Halloy, and Alexandre Brongniart in the mid-nineteenth century, empowered geologists to separate Earth history.
So, the correct option is 'Georges Caviar'.
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