Explanation
Electric is designed to draw power p at the given voltage V , then the power developed is given by
$$P \alpha V^{2} \Rightarrow \dfrac{P}{P_{0}} = \left ( \dfrac{V}{V_{0}} \right )^{2} \Rightarrow P = \left ( \dfrac{V}{V_{0}} \right )^{2} P_{0}$$
Thus $$P = \left ( \dfrac{V}{V_{0}} \right )^{2} P_{0}$$ is the final answer.
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