Explanation
The kinetic energy is given as
$${\rm{K = e}}{{\rm{V}}_{\rm{0}}}$$
$$K = 1.6 \times {10^{ - 19}} \times \left( { - 3.2} \right)$$
$$K = 5.12 \times {10^{ - 19}}$$
By substituting the above value in
$$5.12 \times {10^{ - 19}} = 6.6 \times {10^{34}} \times f + 3.2$$
The frequency is $$0.29 \times {1^{15}}$$
The initial momentum is given as,
$$\dfrac{{d\lambda }}{\lambda } = - \dfrac{{dP}}{{{P_i}}}$$
$$\dfrac{{0.05}}{{100}} = - \dfrac{{\Delta P}}{{{P_i}}}$$
$${P_i} = - 2000\Delta P$$
The initial momentum of electron is $$ - 2000\Delta P$$.
The electron diffraction pattern from a single slit will be as shown below.
dsinθ = λ/2π The line of maximum intensity for the zeroth order will exceed d very much.
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