Explanation
Hint:
Energy mass relation for photon is given as,
E=mc2
Where E is the total energy of the photon, m is the moving mass of the photon, and c is the speed of light
Correct Option is A.
Explanation for correct answer:
∙ A photon is moving with frequency v, then its energy is given as,
E=hv
∙ By energy mas relation, we have
⇒mc2=hv
⇒mc=hvc ⇒p=hvc
Where p is the momentum of the photon.
This is the required expression. Momentum of photon is given by, p=hvc
Thus, Option A is correct.
The laser beams are perfectly parallel. So, the laser beams are very narrow and can travel very long distances without spreading.
\lambda is directly proportional to \dfrac{1}{mv}
\dfrac{ \lambda_1}{ \lambda_2} = \dfrac{m_2 v_2}{ m_1 v_1}
\dfrac{ \lambda_1}{ \lambda_2} = \dfrac{1}{2} \times \dfrac{1}{2}
\lambda_2 = 4 \lambda_1
Molecular mass of CaCO3 = (40+12+16*3)=100 g/mole
No. of moles= 10/100 =0.1 mole
No. Of protons in one molecule of CaCO3=(20+6+8*3)=50
No. of protons in 0.1 mole of CaCO3 will be=(0.1*50)*(6.022*10^23)
=3.011*10^24 protons
\lambda \propto {1 \over m}
{{{\lambda _1}} \over {{\lambda _2}}} = {{{m_2}} \over {{m_1}}} = {{3m} \over {2m}}
= 3:2
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