Explanation
According to Einstein's quantum theory light propagates in the form of packets i.e. quanta of energy, which is called photon.
$$\textbf{Step2:Rest mass of photon}$$
The rest mass of photons is being zero. It can be shown, according to the relativity theory of light.
According to the relativistic theory equation, the mass of the photon is computed as:
$$m = \dfrac{m_{0}}{\sqrt{1-\dfrac{v^{2}}{c^{2}}}}$$
$$m_0=m {\sqrt{1-\dfrac{v^2}{c^2}}}$$
when $$v=0$$;
So $$m_0=0$$
Where $$m_0$$ is the rest mass of the Photon.
Find the minimum wavelength of X-ray produced if 10 kV potential difference is applied across the anode and cathode of the tube.
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