Explanation
$${\text{Force on }}l{\text{ length of the wire }}2{\text{ is }}$$
$${F_2} = Q{E_1} = \left( {{\lambda _2}l} \right)\dfrac{{2k{\lambda _1}}}{R}$$
$$ \Rightarrow \dfrac{{{F_2}}}{l} = \dfrac{{2k{\lambda _1}{\lambda _2}}}{R}$$
$${\text{ Also }}\dfrac{{{F_1}}}{l} = \dfrac{{{F_2}}}{l} = \dfrac{F}{l} = \dfrac{{2k{\lambda _1}{\lambda _2}}}{R}$$
Therefore, option b is correct.
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