Explanation
by the principle of mutual inductance we know that flux induced in coil 2 will depends on the current flowing in coil 1
$$\phi _{ 2 }=Mi_{ 1 }$$
M = mutual inductance
$$i1$$ = current in first coil
now by Faraday's law induced EMF in 2nd coil will be
$$\dfrac { d\phi }{ dt } =EMF$$
$$EMF=M\dfrac { di_{ 1 } }{ dt } $$
now plug in value of current and mutual inductance
$$EMF=5\times 10^{ -3 }\dfrac { d }{ dt } (50sin500t$$
$$EMF=5\times 10^{ -3 }50\times 500\times cos500t$$
$$EMF=125cos500t$$
so above is the equation of induced EMF
so maximum value of induced EMF will be
$$EMF_{ max }=125volts$$
A ring of radius R is charged uniformly with a charge +Q. The electric field at a point on its axis at a distance r from any point on the ring will be:-
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