Explanation
1 eV = (1.6 x 10^-19 coulomb) x (1 volt)
= 1.6 x 10^-19 joule
15 keV = 18 x 10^-16 J …..(a)
Given that photon energy = hf = 15 keV
hf = hc/lambda …… (b)
Now hc = (6.63 x 10^-34 J-sec) x (3 x 10^8 m/sec)
= 19.89 x 10^-28 J-m …..(c)
From (b), lambda = hc/15 keV and from (a) & (c)
Lambda = (19.89 x 10^-28 J-m)/(18 x 10^-16 J)
= 1.105 x 10^-12 m
= 0.01105 Angstrom, which is in the x-ray range
Displacement current is given by
I=ε0dϕedt
=ε0AdEdt(∵ϕ=A.E)
=Addt(qA′)
=AA′i(∵dqdt=i)
=π(R2)2πR2
=14i
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