Explanation
Emf , $$\varepsilon =\dfrac{AdB}{dt}$$.
$$\varepsilon \,\,\alpha \,\,\dfrac{dB}{dt}\,$$ (Slope of graph of magnetic field $$B$$ verses time $$t$$)
From the diagram given in question.
In the given graph slope of $$A B >$$ slope of CD, slope in the $$^ { \prime } a ^ { \prime }$$ region slope in the $$c ^ { \prime } c ^ { \prime }$$ region $$= 0 ,$$ slope in the $$' d ^ { \prime }$$ region $$=$$ slope in the $$^ { \prime } e ^ { \prime }$$ region $$\neq 0 .$$
Hence, why $$b > ( d = \varepsilon ) > ( a = c )$$
A current is flowing through a thin cylindrical shell of radius R. If the energy density in the medium, due to the magnetic field, at a distance r from the axis of the shell is equal to U then which of the following graphs is correct?
It is given that,
Length, $$l=1\,m$$
Current, $$I=1\,A$$
Magnetic field, $$B=1\,oersted={{10}^{-4}}\,Kg/A{{s}^{2}}$$
Magnetic force,
$$ F=I\left( L\times B \right) $$
$$ F=1\left( 1\times {{10}^{-4}}\sin 45 \right) $$
$$ F=\dfrac{{{10}^{-4}}}{\sqrt{2}} $$
Two infinitely long parallel wires carry equal current in same direction. The magnetic field at a mid point in between the two wires is
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