Explanation
Given,
Mass of nucleus $$=M$$
Frequency of photon $$=\upsilon $$
Velocity of nucleus $$={{V}_{2}}$$
Momentum of photon $$P=\dfrac{h}{\lambda }=\dfrac{h\nu }{c}$$
From conservation of momentum
Initial momentum = final momentum
$$ 0+0=M{{V}_{2}}+P $$
$$ {{V}_{2}}=\dfrac{P}{M}=\dfrac{h\nu }{Mc} $$
Recoil energy $$E=\dfrac{1}{2}M{{V}^{2}}=\dfrac{1}{2}M{{\left( \dfrac{h\nu }{Mc} \right)}^{2}}=\dfrac{{{h}^{2}}{{\nu }^{2}}}{2M{{c}^{2}}}$$
Binding energy per nucleon versus mass number curve for nuclei is shown in fig.W, X, Y, and Z are four nuclei indicated on the curve. The process that would release energy is
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