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CBSE Questions for Class 7 Maths Algebraic Expressions Quiz 2 - MCQExams.com
CBSE
Class 7 Maths
Algebraic Expressions
Quiz 2
State True or False:
On subtracting
x
3
−
4
x
−
1
from
3
x
3
−
x
2
+
6
, the answer is
2
x
3
−
x
2
+
4
x
+
7
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
x
3
−
x
2
+
6
−
(
x
3
−
4
x
−
1
)
⟹
(
3
−
1
)
x
3
+
(
−
1
+
0
)
x
2
+
(
+
4
)
x
+
(
6
+
1
)
=
2
x
3
−
x
2
+
4
x
+
7
State True or False:
Addition of
−
2
a
x
−
6
b
y
+
4
c
z
,
4
b
y
−
14
a
x
,
9
c
z
−
4
a
x
−
6
b
y
is
−
16
a
x
−
8
b
y
+
13
c
z
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
,
−
2
a
x
−
6
b
y
+
4
c
z
+
4
b
y
−
14
a
x
+
9
c
z
−
4
a
x
−
6
b
y
=
−
16
a
x
−
8
b
y
+
13
c
z
State True or False:
On subtracting
a
−
b
−
2
c
from
4
a
+
6
b
−
2
c
, the answer is
3
a
+
7
b
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
a
−
b
−
2
c
−
4
a
−
6
b
+
2
c
=
3
a
+
7
b
State True or False:
On subtracting
3
a
−
5
b
+
c
+
2
d
from
7
a
−
3
b
+
c
−
2
d
, the answer is
4
a
+
2
b
−
4
d
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
7
a
−
3
b
+
c
−
2
d
−
3
a
+
5
b
−
c
−
2
d
=
4
a
+
2
b
−
4
d
State True or False:
Addition of
13
a
b
−
9
c
d
−
x
y
,
15
c
d
−
7
a
b
,
6
x
y
−
3
c
d
is
6
a
b
+
3
c
d
+
5
x
y
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
⟹
(
13
−
7
)
a
b
+
(
−
9
+
15
−
3
)
c
+
(
−
1
+
6
)
=
6
a
b
+
3
c
d
+
5
x
y
State True or False:
On subtracting
4
x
y
2
from
3
x
y
2
, the answer is
−
x
y
2
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
3
x
y
2
−
4
x
y
2
=
(
3
−
4
)
x
y
2
=
−
x
y
2
State True or False:
Addition of
x
3
−
x
2
y
+
5
x
y
2
+
y
3
,
−
x
3
−
9
x
y
2
+
y
3
,
3
x
2
y
+
9
x
y
2
is
2
x
2
y
+
5
x
y
2
+
2
y
3
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
⟹
(
1
−
1
)
x
3
+
(
−
1
+
3
)
x
2
y
+
(
5
−
9
+
9
)
x
y
2
+
(
1
+
1
)
y
3
=
2
x
2
y
+
5
x
y
2
+
2
y
3
State True or False:
On subtracting
−
2
x
2
y
+
3
x
y
2
from
8
x
2
y
, the answer is
10
x
2
y
−
3
x
y
2
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
8
x
2
y
−
3
x
y
2
+
2
x
2
y
=
(
8
+
2
)
x
2
y
−
3
x
y
2
=
10
x
2
y
−
3
x
y
2
State True or False:
Addition of
a
6
−
4
a
4
+
6
a
,
5
a
6
+
5
a
4
+
6
a
,
12
a
6
−
10
a
is
18
a
6
+
a
4
+
2
a
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
p
o
w
e
r
s
d
i
r
e
c
t
l
y
,
a
6
−
4
a
4
+
6
a
+
5
a
6
+
5
a
4
+
6
a
+
12
a
6
−
10
a
=
(
1
+
5
+
12
)
a
6
+
(
−
4
+
5
)
a
4
+
(
6
+
6
−
10
)
a
=
18
a
6
+
a
4
+
2
a
State True or False:
On subtracting
the sum of
5
y
2
+
y
−
3
and
y
2
−
3
y
+
7
from
6
y
2
+
y
−
2
, the answer is
3
y
−
6
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
a
n
d
s
u
b
t
r
a
c
t
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
6
y
2
+
y
−
2
−
(
5
y
2
+
y
−
3
+
y
2
−
3
y
+
7
)
⟹
(
6
−
5
−
1
)
y
2
+
(
1
−
1
+
3
)
y
+
(
−
2
+
3
−
7
)
=
3
y
−
6
How much more than
2
x
2
+
4
x
y
+
2
y
2
is
5
x
2
+
10
x
y
−
y
2
?
State True or False: T
he answer is
3
x
2
+
6
x
y
−
3
y
2
.
Report Question
0%
True
0%
False
Explanation
W
e
w
i
l
l
s
u
b
t
r
a
c
t
t
h
e
2
t
o
f
i
n
d
t
h
e
d
i
f
f
e
r
e
n
c
e
,
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
5
x
2
+
10
x
y
−
y
2
−
(
2
x
2
+
4
x
y
+
2
y
2
)
=
3
x
2
+
6
x
y
−
3
y
2
How much less than
3
a
2
−
6
is
2
a
2
+
1
?
State True or False: T
he answer is
a
2
−
7
.
Report Question
0%
True
0%
False
Explanation
W
e
w
i
l
l
s
u
b
t
r
a
c
t
t
h
e
2
t
o
f
i
n
d
t
h
e
d
i
f
f
e
r
e
n
c
e
,
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
a
2
−
6
−
(
2
a
2
+
1
)
=
a
2
−
7
State True or False:
If
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
and
z
=
c
−
b
+
3
a
; then
x
+
y
+
z
is
6
a
+
9
b
+
4
c
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
;
z
=
c
−
b
+
3
a
x
+
y
+
z
=
6
a
+
9
b
+
4
c
State True or False:
On subtracting
a
2
+
a
b
+
b
2
from
4
a
2
−
3
a
b
+
2
b
2
, the answer is
3
a
2
−
4
a
b
+
b
2
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
4
a
2
−
3
a
b
+
2
b
2
−
(
a
2
+
a
b
+
b
2
)
⟹
(
4
−
1
)
a
2
+
(
−
3
−
1
)
a
b
+
(
2
−
1
)
b
2
=
3
a
2
−
4
a
b
+
b
2
State True or False:
On subtracting
−
3
x
3
+
4
x
2
−
5
x
+
6
from
3
x
3
−
4
x
2
+
5
x
−
6
, the answer is
6
x
3
−
8
x
2
+
10
x
−
12
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
x
3
−
4
x
2
+
5
x
−
6
−
(
−
3
x
3
+
4
x
−
5
x
+
6
)
⟹
(
3
+
3
)
x
3
+
(
−
4
−
4
)
x
2
+
(
5
+
5
)
x
+
(
−
6
−
6
)
=
6
x
3
−
8
x
2
+
10
x
−
12
State True or False:
On subtracting
c
a
b
−
4
c
a
d
−
c
b
d
from
3
a
b
c
+
5
b
c
d
−
c
d
a
, the answer is
2
a
b
c
+
3
c
a
d
+
6
b
c
d
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
a
b
c
+
5
b
c
d
−
c
d
a
−
(
c
a
b
−
4
c
a
d
−
c
b
d
)
⟹
(
3
−
1
)
a
b
c
+
(
−
1
+
4
)
c
a
d
+
(
1
+
5
)
b
c
d
=
2
a
b
c
+
3
c
a
d
+
6
b
c
d
State True or False:
On subtracting
−
m
2
+
m
+
4
from
2
m
2
+
m
+
1
, the answer is
3
m
2
−
m
−
1
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
2
m
2
+
m
+
1
−
(
m
2
+
m
+
4
)
⟹
(
2
−
1
)
m
2
+
(
1
−
1
)
m
+
(
1
−
4
)
=
m
2
−
3
State True or False:
On subtracting
6
a
+
3
from
a
3
−
3
a
2
+
4
a
+
1
, the answer is
a
3
−
3
a
2
−
2
a
−
2
.
Report Question
0%
True
0%
False
Explanation
\\
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
a
3
−
3
a
2
+
4
a
+
1
−
(
6
a
+
3
)
⟹
(
1
)
a
3
+
(
−
3
)
a
2
+
(
4
−
6
)
a
+
(
1
−
3
)
=
a
3
−
3
a
2
−
2
a
−
2
Add:
2
x
+
y
+
z
;
−
x
+
2
y
+
2
z
and
x
−
y
−
z
Report Question
0%
2
x
+
2
y
+
2
z
0%
3
x
+
5
y
+
z
0%
3
x
−
3
y
−
z
0%
None of these
Explanation
Sum of
(
2
x
+
y
+
z
)
,
(
−
x
+
2
y
+
2
z
)
and
(
x
−
y
−
z
)
is:
=
(
2
x
+
y
+
z
)
+
(
−
x
+
2
y
+
2
z
)
+
(
x
−
y
−
z
)
=
(
2
x
−
x
+
x
)
+
(
y
+
2
y
−
y
)
+
(
z
+
2
z
−
z
)
=
2
x
+
2
y
+
2
z
=
2
(
x
+
y
+
z
)
The sum of
3
a
b
,
−
8
a
b
and
5
a
b
is equal to
Report Question
0%
10
a
b
0%
16
a
b
0%
a
b
0%
0
Explanation
We have to find sum of
3
a
b
,
−
8
a
b
,
5
a
b
∴
required sum is
=\displaystyle 3ab+\left( -8ab \right) +5ab
\displaystyle =8ab-8ab=0
Add the given expressions
5m+0.3n-1.2t; \, \, 0.23m - 2.8t + 4n
Report Question
0%
5.3m + 4.13n-4t
0%
5.23m + 4.3n-4t
0%
52.33m + 0.43n-4t
0%
5.23m + 43n-4t
Explanation
5m+0.3n-1.2t+ 0.23m-2.8t+4n
=5m+0.3n-1.2t+0.23m+4n-2.8t
=5.23m + 4.3n-4t
State True or False:
If
x=6a+8b+9c
;
y=2b-3a-6c
and
z=c-b+3a
; then
2x-y-3z
is
6a+17b+21c
.
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0%
True
0%
False
Explanation
We\quad can\quad directly\quad add\quad the\quad coefficients\quad of\quad like\quad variables,\\ x=6a+8b+9c;\quad y=2b3a6c;\quad z=cb+3a\\ 2x-y-3z\quad =2(6a+8b+9c)\quad -\quad (2b-3a-6c)\quad -3(c-b+3a)\\ =6a+17b+21c
State True or False:
If
x=6a+8b+9c
;
y=2b-3a-6c
and
z=c-b+3a
; then
x-y+z
is
12a+5b+16c
.
Report Question
0%
True
0%
False
Explanation
We\quad can\quad directly\quad add\quad the\quad coefficients\quad of\quad like\quad variables,\\ x=6a+8b+9c;\quad y=2b-3a-6c;\quad z=c-b+3a\\ x-y+z\quad =12a+5b+16c
State True or False:
If
x=6a+8b+9c
;
y=2b-3a-6c
and
z=c-b+3a
; then
3y-2z-5x
is
-45a-32b-65c
.
Report Question
0%
True
0%
False
Explanation
x=6a+8b+9c;
y=2b-3a-6c
\&
z=c-b+3a
The value of
3y-2z-5x
will be,
substitute
x
\&
y
\&
z
in the expression,
=3\left( { 2b-3a-6c } \right) -2\left( { c-b+3a } \right) -5\left( { 6a+8b+9c} \right)
=6b-9a-18c-2c+2b-6a-30a-40b-45c
=45a-32b-65c
Hence, the answer is true.
If we take away
\displaystyle -8abc
from
\displaystyle -7abc
, then the result is equal to
Report Question
0%
\displaystyle abc
0%
\displaystyle 15abc
0%
\displaystyle -abc
0%
\displaystyle -15abc
Explanation
We have to just subtract
-8abc
from
-7abc
=\displaystyle \left( -7abc \right) -\left( -8abc \right)
\displaystyle =-7abc+8abc
= abc
What is the sum of
\displaystyle \left( 4a+5b \right) ,\left( -6a+2b \right) ,\left( 7a-6b \right)
?
Report Question
0%
\displaystyle -5a+b
0%
\displaystyle 5a+b
0%
\displaystyle 5a-b
0%
\displaystyle -5a-b
Explanation
We have to find sum of
(4a+5b), (-6a+2b), (7a-6b)
\therefore
required sum
=\displaystyle \left( 4a+5b \right) +\left( -6a+2b \right) +\left( 7a-6b \right)
\displaystyle =\left( 4a-6a+7a \right) +\left( 5b+2b-6b \right)
=\displaystyle 5a+b
What should be added to
6x^2-3xy+4y^2
to get
2y^2+xy-4x^2
?
Report Question
0%
-x^2-y^2+4y
0%
-10x^2-y^2+4xy
0%
x^2-2y^2+4x
0%
-10x^2-2y^2+4xy
Explanation
Let the required expression be
P
P=(2y^{ 2 }+xy-4x^{ 2 })-(6x^{ 2 }-3xy+4y^{ 2 })
=-4x^{ 2 }+2y^{ 2 }+xy-6x^{ 2 }+3xy-4y^{ 2 }
=-10x^2-2y^2+4xy
Subtract
6x+8y+4
from the sum of
4x-2y+3
and
2y-x+3
?
Report Question
0%
-x-8y-2
0%
-3x-8y+2
0%
-3x-y+1
0%
-x-8y+2
Explanation
Consider,
(4x-2y+3)+(2y-x+3)
=4x-2y+3+2y-x+3
=3x+6
Subtracting
6x+8y+4
from
3x+6
we get,
(3x+6)-(6x+8y+4)
=3x+6-6x-8y+4
=-3x-8y+2
By how much is
\displaystyle a^{4}+4a^{2}b^{2}+b^{4}
more than
\displaystyle a^{4}-8a^{2}b^{2}+b^{4}
?
Report Question
0%
\displaystyle 12a^{2}b^{2}
0%
\displaystyle -12a^{2}b^{2}
0%
\displaystyle 2a^{4}+2b^{4}
0%
None
Explanation
\displaystyle a^{4}+4a^{2}b^{2}+b^{4}
\displaystyle a^{4}-8a^{2}b^{2}+b^{4}
-
+
-
\displaystyle \overline{\underline{12a^{2}b^{2}}}
\displaystyle \left( p+q \right) -\left( p-q \right)
is equal to
Report Question
0%
\displaystyle 2p+2q
0%
\displaystyle 2p
0%
\displaystyle 2q
0%
0
Explanation
Given,
\displaystyle \left( p+q \right) -\left( p-q \right) =p+q-p+q
=2q
Hence simplified form of the given expression is
2q
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Practice Class 7 Maths Quiz Questions and Answers
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