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CBSE Questions for Class 7 Maths Algebraic Expressions Quiz 2 - MCQExams.com
CBSE
Class 7 Maths
Algebraic Expressions
Quiz 2
State True or False:
On subtracting
x
3
−
4
x
−
1
from
3
x
3
−
x
2
+
6
, the answer is
2
x
3
−
x
2
+
4
x
+
7
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
x
3
−
x
2
+
6
−
(
x
3
−
4
x
−
1
)
⟹
(
3
−
1
)
x
3
+
(
−
1
+
0
)
x
2
+
(
+
4
)
x
+
(
6
+
1
)
=
2
x
3
−
x
2
+
4
x
+
7
State True or False:
Addition of
−
2
a
x
−
6
b
y
+
4
c
z
,
4
b
y
−
14
a
x
,
9
c
z
−
4
a
x
−
6
b
y
is
−
16
a
x
−
8
b
y
+
13
c
z
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
,
−
2
a
x
−
6
b
y
+
4
c
z
+
4
b
y
−
14
a
x
+
9
c
z
−
4
a
x
−
6
b
y
=
−
16
a
x
−
8
b
y
+
13
c
z
State True or False:
On subtracting
a
−
b
−
2
c
from
4
a
+
6
b
−
2
c
, the answer is
3
a
+
7
b
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
a
−
b
−
2
c
−
4
a
−
6
b
+
2
c
=
3
a
+
7
b
State True or False:
On subtracting
3
a
−
5
b
+
c
+
2
d
from
7
a
−
3
b
+
c
−
2
d
, the answer is
4
a
+
2
b
−
4
d
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
7
a
−
3
b
+
c
−
2
d
−
3
a
+
5
b
−
c
−
2
d
=
4
a
+
2
b
−
4
d
State True or False:
Addition of
13
a
b
−
9
c
d
−
x
y
,
15
c
d
−
7
a
b
,
6
x
y
−
3
c
d
is
6
a
b
+
3
c
d
+
5
x
y
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
⟹
(
13
−
7
)
a
b
+
(
−
9
+
15
−
3
)
c
+
(
−
1
+
6
)
=
6
a
b
+
3
c
d
+
5
x
y
State True or False:
On subtracting
4
x
y
2
from
3
x
y
2
, the answer is
−
x
y
2
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
3
x
y
2
−
4
x
y
2
=
(
3
−
4
)
x
y
2
=
−
x
y
2
State True or False:
Addition of
x
3
−
x
2
y
+
5
x
y
2
+
y
3
,
−
x
3
−
9
x
y
2
+
y
3
,
3
x
2
y
+
9
x
y
2
is
2
x
2
y
+
5
x
y
2
+
2
y
3
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
⟹
(
1
−
1
)
x
3
+
(
−
1
+
3
)
x
2
y
+
(
5
−
9
+
9
)
x
y
2
+
(
1
+
1
)
y
3
=
2
x
2
y
+
5
x
y
2
+
2
y
3
State True or False:
On subtracting
−
2
x
2
y
+
3
x
y
2
from
8
x
2
y
, the answer is
10
x
2
y
−
3
x
y
2
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
d
i
r
e
c
t
l
y
8
x
2
y
−
3
x
y
2
+
2
x
2
y
=
(
8
+
2
)
x
2
y
−
3
x
y
2
=
10
x
2
y
−
3
x
y
2
State True or False:
Addition of
a
6
−
4
a
4
+
6
a
,
5
a
6
+
5
a
4
+
6
a
,
12
a
6
−
10
a
is
18
a
6
+
a
4
+
2
a
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
o
f
l
i
k
e
p
o
w
e
r
s
d
i
r
e
c
t
l
y
,
a
6
−
4
a
4
+
6
a
+
5
a
6
+
5
a
4
+
6
a
+
12
a
6
−
10
a
=
(
1
+
5
+
12
)
a
6
+
(
−
4
+
5
)
a
4
+
(
6
+
6
−
10
)
a
=
18
a
6
+
a
4
+
2
a
State True or False:
On subtracting
the sum of
5
y
2
+
y
−
3
and
y
2
−
3
y
+
7
from
6
y
2
+
y
−
2
, the answer is
3
y
−
6
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
a
n
d
s
u
b
t
r
a
c
t
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
6
y
2
+
y
−
2
−
(
5
y
2
+
y
−
3
+
y
2
−
3
y
+
7
)
⟹
(
6
−
5
−
1
)
y
2
+
(
1
−
1
+
3
)
y
+
(
−
2
+
3
−
7
)
=
3
y
−
6
How much more than
2
x
2
+
4
x
y
+
2
y
2
is
5
x
2
+
10
x
y
−
y
2
?
State True or False: T
he answer is
3
x
2
+
6
x
y
−
3
y
2
.
Report Question
0%
True
0%
False
Explanation
W
e
w
i
l
l
s
u
b
t
r
a
c
t
t
h
e
2
t
o
f
i
n
d
t
h
e
d
i
f
f
e
r
e
n
c
e
,
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
5
x
2
+
10
x
y
−
y
2
−
(
2
x
2
+
4
x
y
+
2
y
2
)
=
3
x
2
+
6
x
y
−
3
y
2
How much less than
3
a
2
−
6
is
2
a
2
+
1
?
State True or False: T
he answer is
a
2
−
7
.
Report Question
0%
True
0%
False
Explanation
W
e
w
i
l
l
s
u
b
t
r
a
c
t
t
h
e
2
t
o
f
i
n
d
t
h
e
d
i
f
f
e
r
e
n
c
e
,
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
a
2
−
6
−
(
2
a
2
+
1
)
=
a
2
−
7
State True or False:
If
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
and
z
=
c
−
b
+
3
a
; then
x
+
y
+
z
is
6
a
+
9
b
+
4
c
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
;
z
=
c
−
b
+
3
a
x
+
y
+
z
=
6
a
+
9
b
+
4
c
State True or False:
On subtracting
a
2
+
a
b
+
b
2
from
4
a
2
−
3
a
b
+
2
b
2
, the answer is
3
a
2
−
4
a
b
+
b
2
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
4
a
2
−
3
a
b
+
2
b
2
−
(
a
2
+
a
b
+
b
2
)
⟹
(
4
−
1
)
a
2
+
(
−
3
−
1
)
a
b
+
(
2
−
1
)
b
2
=
3
a
2
−
4
a
b
+
b
2
State True or False:
On subtracting
−
3
x
3
+
4
x
2
−
5
x
+
6
from
3
x
3
−
4
x
2
+
5
x
−
6
, the answer is
6
x
3
−
8
x
2
+
10
x
−
12
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
x
3
−
4
x
2
+
5
x
−
6
−
(
−
3
x
3
+
4
x
−
5
x
+
6
)
⟹
(
3
+
3
)
x
3
+
(
−
4
−
4
)
x
2
+
(
5
+
5
)
x
+
(
−
6
−
6
)
=
6
x
3
−
8
x
2
+
10
x
−
12
State True or False:
On subtracting
c
a
b
−
4
c
a
d
−
c
b
d
from
3
a
b
c
+
5
b
c
d
−
c
d
a
, the answer is
2
a
b
c
+
3
c
a
d
+
6
b
c
d
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
3
a
b
c
+
5
b
c
d
−
c
d
a
−
(
c
a
b
−
4
c
a
d
−
c
b
d
)
⟹
(
3
−
1
)
a
b
c
+
(
−
1
+
4
)
c
a
d
+
(
1
+
5
)
b
c
d
=
2
a
b
c
+
3
c
a
d
+
6
b
c
d
State True or False:
On subtracting
−
m
2
+
m
+
4
from
2
m
2
+
m
+
1
, the answer is
3
m
2
−
m
−
1
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
2
m
2
+
m
+
1
−
(
m
2
+
m
+
4
)
⟹
(
2
−
1
)
m
2
+
(
1
−
1
)
m
+
(
1
−
4
)
=
m
2
−
3
State True or False:
On subtracting
6
a
+
3
from
a
3
−
3
a
2
+
4
a
+
1
, the answer is
a
3
−
3
a
2
−
2
a
−
2
.
Report Question
0%
True
0%
False
Explanation
\\
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
a
3
−
3
a
2
+
4
a
+
1
−
(
6
a
+
3
)
⟹
(
1
)
a
3
+
(
−
3
)
a
2
+
(
4
−
6
)
a
+
(
1
−
3
)
=
a
3
−
3
a
2
−
2
a
−
2
Add:
2
x
+
y
+
z
;
−
x
+
2
y
+
2
z
and
x
−
y
−
z
Report Question
0%
2
x
+
2
y
+
2
z
0%
3
x
+
5
y
+
z
0%
3
x
−
3
y
−
z
0%
None of these
Explanation
Sum of
(
2
x
+
y
+
z
)
,
(
−
x
+
2
y
+
2
z
)
and
(
x
−
y
−
z
)
is:
=
(
2
x
+
y
+
z
)
+
(
−
x
+
2
y
+
2
z
)
+
(
x
−
y
−
z
)
=
(
2
x
−
x
+
x
)
+
(
y
+
2
y
−
y
)
+
(
z
+
2
z
−
z
)
=
2
x
+
2
y
+
2
z
=
2
(
x
+
y
+
z
)
The sum of
3
a
b
,
−
8
a
b
and
5
a
b
is equal to
Report Question
0%
10
a
b
0%
16
a
b
0%
a
b
0%
0
Explanation
We have to find sum of
3
a
b
,
−
8
a
b
,
5
a
b
∴
required sum is
=
3
a
b
+
(
−
8
a
b
)
+
5
a
b
=
8
a
b
−
8
a
b
=
0
Add the given expressions
5
m
+
0.3
n
−
1.2
t
;
0.23
m
−
2.8
t
+
4
n
Report Question
0%
5.3
m
+
4.13
n
−
4
t
0%
5.23
m
+
4.3
n
−
4
t
0%
52.33
m
+
0.43
n
−
4
t
0%
5.23
m
+
43
n
−
4
t
Explanation
5
m
+
0.3
n
−
1.2
t
+
0.23
m
−
2.8
t
+
4
n
=
5
m
+
0.3
n
−
1.2
t
+
0.23
m
+
4
n
−
2.8
t
=
5.23
m
+
4.3
n
−
4
t
State True or False:
If
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
and
z
=
c
−
b
+
3
a
; then
2
x
−
y
−
3
z
is
6
a
+
17
b
+
21
c
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
3
a
6
c
;
z
=
c
b
+
3
a
2
x
−
y
−
3
z
=
2
(
6
a
+
8
b
+
9
c
)
−
(
2
b
−
3
a
−
6
c
)
−
3
(
c
−
b
+
3
a
)
=
6
a
+
17
b
+
21
c
State True or False:
If
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
and
z
=
c
−
b
+
3
a
; then
x
−
y
+
z
is
12
a
+
5
b
+
16
c
.
Report Question
0%
True
0%
False
Explanation
W
e
c
a
n
d
i
r
e
c
t
l
y
a
d
d
t
h
e
c
o
e
f
f
i
c
i
e
n
t
s
o
f
l
i
k
e
v
a
r
i
a
b
l
e
s
,
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
;
z
=
c
−
b
+
3
a
x
−
y
+
z
=
12
a
+
5
b
+
16
c
State True or False:
If
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
and
z
=
c
−
b
+
3
a
; then
3
y
−
2
z
−
5
x
is
−
45
a
−
32
b
−
65
c
.
Report Question
0%
True
0%
False
Explanation
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
&
z
=
c
−
b
+
3
a
The value of
3
y
−
2
z
−
5
x
will be,
substitute
x
&
y
&
z
in the expression,
=
3
(
2
b
−
3
a
−
6
c
)
−
2
(
c
−
b
+
3
a
)
−
5
(
6
a
+
8
b
+
9
c
)
=
6
b
−
9
a
−
18
c
−
2
c
+
2
b
−
6
a
−
30
a
−
40
b
−
45
c
=
45
a
−
32
b
−
65
c
Hence, the answer is true.
If we take away
−
8
a
b
c
from
−
7
a
b
c
, then the result is equal to
Report Question
0%
a
b
c
0%
15
a
b
c
0%
−
a
b
c
0%
−
15
a
b
c
Explanation
We have to just subtract
−
8
a
b
c
from
−
7
a
b
c
=
(
−
7
a
b
c
)
−
(
−
8
a
b
c
)
=
−
7
a
b
c
+
8
a
b
c
=
a
b
c
What is the sum of
(
4
a
+
5
b
)
,
(
−
6
a
+
2
b
)
,
(
7
a
−
6
b
)
?
Report Question
0%
−
5
a
+
b
0%
5
a
+
b
0%
5
a
−
b
0%
−
5
a
−
b
Explanation
We have to find sum of
(
4
a
+
5
b
)
,
(
−
6
a
+
2
b
)
,
(
7
a
−
6
b
)
∴
required sum
=
(
4
a
+
5
b
)
+
(
−
6
a
+
2
b
)
+
(
7
a
−
6
b
)
=
(
4
a
−
6
a
+
7
a
)
+
(
5
b
+
2
b
−
6
b
)
=
5
a
+
b
What should be added to
6
x
2
−
3
x
y
+
4
y
2
to get
2
y
2
+
x
y
−
4
x
2
?
Report Question
0%
−
x
2
−
y
2
+
4
y
0%
−
10
x
2
−
y
2
+
4
x
y
0%
x
2
−
2
y
2
+
4
x
0%
−
10
x
2
−
2
y
2
+
4
x
y
Explanation
Let the required expression be
P
P
=
(
2
y
2
+
x
y
−
4
x
2
)
−
(
6
x
2
−
3
x
y
+
4
y
2
)
=
−
4
x
2
+
2
y
2
+
x
y
−
6
x
2
+
3
x
y
−
4
y
2
=
−
10
x
2
−
2
y
2
+
4
x
y
Subtract
6
x
+
8
y
+
4
from the sum of
4
x
−
2
y
+
3
and
2
y
−
x
+
3
?
Report Question
0%
−
x
−
8
y
−
2
0%
−
3
x
−
8
y
+
2
0%
−
3
x
−
y
+
1
0%
−
x
−
8
y
+
2
Explanation
Consider,
(
4
x
−
2
y
+
3
)
+
(
2
y
−
x
+
3
)
=
4
x
−
2
y
+
3
+
2
y
−
x
+
3
=
3
x
+
6
Subtracting
6
x
+
8
y
+
4
from
3
x
+
6
we get,
(
3
x
+
6
)
−
(
6
x
+
8
y
+
4
)
=
3
x
+
6
−
6
x
−
8
y
+
4
=
−
3
x
−
8
y
+
2
By how much is
a
4
+
4
a
2
b
2
+
b
4
more than
a
4
−
8
a
2
b
2
+
b
4
?
Report Question
0%
12
a
2
b
2
0%
−
12
a
2
b
2
0%
2
a
4
+
2
b
4
0%
None
Explanation
a
4
+
4
a
2
b
2
+
b
4
a
4
−
8
a
2
b
2
+
b
4
−
+
−
¯
12
a
2
b
2
_
(
p
+
q
)
−
(
p
−
q
)
is equal to
Report Question
0%
2
p
+
2
q
0%
2
p
0%
2
q
0%
0
Explanation
Given,
(
p
+
q
)
−
(
p
−
q
)
=
p
+
q
−
p
+
q
=
2
q
Hence simplified form of the given expression is
2
q
0:0:1
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0
Answered
1
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Incorrect : 0
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Practice Class 7 Maths Quiz Questions and Answers
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