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CBSE Questions for Class 8 Maths Comparing Quantities Quiz 2 - MCQExams.com
CBSE
Class 8 Maths
Comparing Quantities
Quiz 2
A car was sold at
R
s
80
,
000
through a broker. The broker charged
2.5
%
brokerage from both the seller and the buyer. What is the total amount of brokerage received by the broker?
Report Question
0%
R
s
1000
0%
R
s
4000
0%
R
s
2500
0%
None of these
Explanation
From the buyer side, broker get charge
=
2.5
%
o
f
80000
=
R
s
.
2000
From the seller side, broker get charge
=
2.5
%
o
f
80000
=
R
s
.
2000
Hence total brokerage charge he get
=
2000
+
2000
=
R
s
.
4000
By paying
2
%
brokerage for buying an old scooter for
R
s
15
,
000
through a broker. At what amount is the scooter bought?
Report Question
0%
R
s
25
,
300
0%
R
s
15
,
300
0%
R
s
12
,
200
0%
None of these
Explanation
Amount the scooter bought = 15000+(2/100)15000
= 15000 + 300
= Rs 15300
Deepali has bought a sofa set for Rs 14,There is an additional expense of Rs 500 on it. Since she did not like the sofa set, she sold it bearing a loss of 8.5%. For how much did she sell the sofa set?
Report Question
0%
R
s
10
,
725
0%
R
s
11
,
725
0%
R
s
13
,
725
0%
None of these
Explanation
Original price =100
then
14500+500 = 15000
total cost = 15000
loss = 8.5%
then,
Total SP=[(100-Loss%)/100]*(Cost price)
=
(
91.5
/
100
)
∗
15000
=
91.5
∗
150
=
13725
Vinodbhai sold his shop through a broker for
R
s
7
,
50
,
000
. The broker charged
1
%
brokerage for this work. What amount did Vinodbhai get on selling the shop?
Report Question
0%
R
s
8
,
42
,
500
0%
R
s
7
,
42
,
500
0%
R
s
3
,
42
,
500
0%
None of these
Explanation
Brokerage charge
=
1
%
o
f
7
,
50
,
000
=
R
s
.
7
,
500
Hence amount received by Vinodhbhai
=
7
,
50
,
000
−
7
,
500
=
R
s
.
7
,
42
,
500
Do the following sums:
C.P. = Rs 300 S.P. = Rs 350, then how much rupees profit or loss occur?
Report Question
0%
Profit
R
s
50
0%
Profit
R
s
100
0%
Profit
R
s
40
0%
None of these
Explanation
Given:
C.P. = Rs 300 and S.P. = Rs350
Since,
S
.
P
.
>
C
.
P
.
Therefore,
P
r
o
f
i
t
=
S
.
P
.
−
C
.
P
.
=
350
−
300
=
R
s
50
Jimmy's balance in a bank on 1st November was Rs.
58709
. He withdrew RS.
13090
and Rs.
16518
from his account and deposits Rs.
1680
in his account in that month. What was the balance at the end of the month?
Report Question
0%
Rs.
30001
0%
Rs.
29101
0%
Rs.
29001
0%
Rs.
30781
Explanation
Amount of money in the account on 1st November
=
R
s
.58709
Total amount of money withdrawn
=
R
s
.
(
13090
+
16518
)
=
R
s
.29608
Amount of money deposited
=
R
s
.1680
Balance left at the end of the month
=
R
s
.
(
58709
−
29608
+
1680
)
=
R
s
.
(
60389
−
29608
)
=
R
s
.30781
Vivekbhai bought a TV for Rs 16,Rs 200 was spent on transportation and labour. For earning 12 % profit, what price should it be sold?
Report Question
0%
R
s
30
,
144
0%
R
s
18
,
144
0%
R
s
20
,
144
0%
None of these
Explanation
Vivkebhai bought a TV = 16,000 Rs.
transportation and labor price = 200 Rs.
∴ now C.P = 16,000 + 200 = 16,200 Rs.
for earning 12% profit, Let selling price = X Rs.
X = C.P + 12% of C.P
= 16,200 + (12 × 16,200)/100
= 16,200 + 12 × 162
= 16,200 + 1,944
= 18,144 Rs.
hence, selling price of TV will be 18,144 Rs.
The compound interest on
R
s
.
64
,
000
for
3
years, compounded annually at
7.5
% per annum is
Report Question
0%
R
s
.
14
,
400
0%
R
s
.
15
,
705
0%
R
s
.
15
,
507
0%
R
s
.
15
,
075
Explanation
P
r
i
n
c
i
p
a
l
=
64000
R
a
t
e
=
7.5
%
p
.
a
T
i
m
e
=
3
y
e
a
r
s
Where r is the rate and t is the time.
C
I
=
64000
(
1
+
7.5
/
100
)
3
−
64000
=
64000
(
1
+
75
/
1000
)
3
−
64000
=
64000
(
1
+
3
/
40
)
3
−
64000
=
64000
×
(
43
/
40
)
3
−
64000
=
64000
×
(
43
/
40
×
43
/
40
×
43
/
40
)
−
64000
=
(
43
×
43
×
43
)
−
64000
=
79507
−
64000
=
15507
Hence CI will be 15507 rupees
30% of 1860 + 40% of 820 = ?% of 3544
Report Question
0%
30
0%
25
0%
35
0%
40
Explanation
solution:
30
100
x 1860 +
40
100
x 820 =
x
x 3544
558
+
328
=
x
x 3544
886
3544
=
x
x
=
.25
hence the correct option : B
40% of 2400+ ?% of 600=50% of 3840
Report Question
0%
50
0%
40
0%
80
0%
None of these
Explanation
solution:
40
100
x 2400 +
x
100
x 600 =
50
100
x 3840
960
+
x
100
x 600 = 1920
x
100
x 600
= 960
x = 160
hence the correct opt: D
175
×
?
=
140
%
of 1200
Report Question
0%
8.4
0%
7.5
0%
13.44
0%
9.6
Explanation
solution:
175 x
x
=
140
100
of 1200
175 x
x
= 1680
x
=
1680
175
x
= 9.6
hence the correct opt: D
A shopkeeper mixes two varieties of Tea, one costing Rs.
40
/kg and another Rs.
50
/kg in the ratio
3
:
2
. if he sells the mixed variety of Tea at Rs.
48
/kg, his gain or loss percent is
Report Question
0%
48.4
% gain
0%
48.4
% loss
0%
10
% gain
0%
10
% loss
Explanation
Average CP of Mixed Tea when Mixed in Ratio
3
:
2
=
40
×
3
+
50
×
2
3
+
2
=
220
5
=
R
s
.44
Wen SP=Rs.
48
/
k
g
=
4
44
×
100
=
9.09
≈
10
% gain
If some articles are bought at prices ranging from Rs. 200 to Rs. 350 and are sold at prices ranging from Rs. 300 to Rs. 425, what is the maximum possible profit that might be made in selling 16 such articles?
Report Question
0%
Rs. 3600
0%
Rs. 1200
0%
Rs. 800
0%
Rs. 400
Explanation
Maximum profit will be if we purchase in minimum
price & sell in maximum price.
Minimum price for purchasing = Rs 200
Maximum price for purchasing = Rs 425
Net profit on 1 article
425
−
200
=
R
s
225
Net profit on 16 article
=
225
×
16
=
R
s
3600
Indirect tax is:
Report Question
0%
Sales Tax
0%
House Tax
0%
Water Tax
0%
Surcharge
Explanation
Direct taxes are paid in entirety by a taxpayer directly to the government. It is also defined as the tax where the liability, as well as the burden to pay it, resides on the same individual. Direct taxes are collected by the central government as well as state governments according to the type of tax levied. Major types of direct tax include Income tax, corporate tax etc.
Indirect tax includes those taxes where the liability to pay the tax lies on a person who then shifts the tax burden to another individual.
Some types of indirect taxes are sales tax, service tax etc.
Therefore sales tax is an indirect tax.
P
sells a table to
Q
at a profit of
10
% and
Q
sells it to
R
at a profit of
12
%. If
R
pays Rs.
246.40
for it, then how much had
P
paid for it?
Report Question
0%
200.00
0%
300.00
0%
248.00
0%
346.00
Explanation
Let
P
paid for table
=
Rs.
P
After all
R
paid =Rs.
246.40
According to the question,
246.40
=
P
[
110
100
]
[
112
100
]
P
=
246.40
×
100
×
100
110
×
112
=
246400
11
×
112
=
R
s
.200
A shopkeeper earns
15
% profit on a shirt even after allowing
31
% discount on the marked price.If the market price
1250
, then the cost price of the shirt is
Report Question
0%
870
0%
800
0%
750
0%
690
Explanation
According to the problem the S.P and C.P is
D
i
s
c
o
u
n
t
=
31
100
×
1250
=
387.5
S
.
P
=
1250
−
387.5
S
.
P
=
862.5
C
.
P
=
100
100
+
15
×
862.5
=
100
115
×
862.5
=
17250
23
=
750
Therefore, the cost price is Rs
750
.
A shopkeeper sells a sweater at a loss of
5
%
. If he had sold it for Rs.
260
more, he would have made a profit of
15
%
. Calculate the purchase price of the sweater.
Report Question
0%
Rs
1900
0%
Rs
1400
0%
Rs
1000
0%
Rs
1300
Explanation
case1:Let CP be
x
Loss=5%
S
P
1
=
x
−
5
%
o
f
x
S
P
1
=
95
%
o
f
x
=
95
100
x
Case2: CP
=
x
,
P
2
=
15
%
S
P
2
=
x
+
15
%
o
f
x
=
115
100
x
Difference in SP is given
260
Thus,
S
P
2
−
S
P
1
=
260
115
x
−
95
x
100
=
260
⇒
20
x
=
260
×
100
⇒
x
=
26000
20
⇒
x
=
1300
Thus purchase price is
1300
Rs.
If the cost of a dozen soaps is
R
s
285.60
, what will be the cost of
15
such soaps?
Report Question
0%
Rs.
827
0%
Rs.
772
0%
Rs.
676
0%
Rs.
357
Explanation
Cost of
12
soaps
=
285.60
Cost of one soap
=
285.60
12
Cost of
15
soaps
=
285.60
12
×
15
=
R
s
.357
The compound interest on Rs. 50,000 at 4% per annum for two years compounded anually is :
Report Question
0%
4000
0%
4080
0%
4280
0%
4050
Explanation
C.I. = Amount - Principle
=>
P
(
(
1
+
r
100
)
T
−
1
)
CI =
50
,
000
(
1
+
4
100
)
2
−
1
)
C.I.=
4080.
If a banana's cost is
R
s
.
1.25
and apple's cost is
R
s
.
1.75
what will be the cost of
2
Dozen of Banana and
3
Dozen of apple?
Report Question
0%
R
s
.
93
0%
R
s
.
83
0%
R
s
.
85
0%
R
s
.
70
Explanation
∵
Cost of one banana
=Rs.1.25
\therefore 2
dozens banana's cost
=24\times 1.25=Rs.30
\because
One apple's cost
=Rs.1.75
\therefore 3
dozens banana's cost
=36\times 1.75=Rs.63
Total cost
=63+30=Rs.93
Hence, option (A) is the correct option
The cost price of
16
articles is equal to selling price of
12
articles then the gain or loss per cent is
Report Question
0%
13 \frac {1}{3}
% gain
0%
33 \frac {1}{3}
% gain
0%
33 \frac {1}{3}
% loss
0%
13 \frac {1}{3}
% loss
Explanation
C.P. of 16 articles = S.P. of 12 articles (given)
Let SP of 1 article = Rs. x
then, SP of 12 articles = 12 x Rs.
C.P. of 16 articles = S.P. of 12 articles
CP of 16 articles = 12 x Rs.
SP of 16 articles = 16 x Rs.
SP > CP
Profit
= SP - CP \\ = 16 x - 12 x \\ = 4 x
Profit %
= \dfrac{\textrm{Profit}}{C} \times 100 \\ = \dfrac{4x}{12x} \times 100 \\ = 33\dfrac{1}{3} \%
Rahul and Sunjay invested
Rs.\,\,25,000\,\,
and
\;\,Rs.\,\,35,000
respectively in a business. They will share the profit in the proportion.............
Report Question
0%
7:5
0%
5:7
0%
8:5
0%
5:8
Explanation
Given
Rahul and Sunjay invested
Rs.\,\,25,000\,\,
and
\;\,Rs.\,\,35,000
respectively in a business.
Now their distribution of the profit will be in the ratio of their invested amounts.
This ratio will be
25,000:35,000
=25:35
=5:7
.
If 16 shirts were sold for 20 notes of Rs 100, double its notes of Rs 50 and 200 notes of Rs 20, then what is the selling price of a shirt ?
Report Question
0%
Rs 250
0%
Rs 400
0%
Rs 350
0%
Rs 500
Explanation
Total amount obtained for 16 shirts
= 20 \times 100 + 40 \times 50 + 200 \times 20
= 8000 \ Rs
So, Selling Price of a shirt
= \dfrac{8000}{16} = 500 \ Rs
Thus, D is the correct answer.
State whether the statements are True or False.
12\%
of
120
is
100.
Report Question
0%
True
0%
False
Explanation
12\%
of
120 = \dfrac{12}{100} \times 120 = 14.40
Hence the stattement is false.
Compound interest is the interest calculated on the previous year's amount.
Report Question
0%
True
0%
False
Explanation
The given statement is true. Compound interest means that the interest on previous year is liable to more interest
If the marked price of an article is Rs. x, and the selling price is Rs. y, then what is the discount percentage?
Report Question
0%
\frac{(x-y)100}{x}
0%
\frac{(y-x)100}{x}
0%
(\frac{y-x}{y})100
0%
\frac{x-y}{100}
The manufacturer A of a certain item sells it to a wholesaler at a profit of 20% on his manufacturing cost. The wholesaler sells it to a retailer at a profit of 25% and the retailer sells it to a consumer at a profit of 20%. The price paid by the consumer over and above manufacturing cost will be
Report Question
0%
65%
0%
80%
0%
85%
0%
90%
Explanation
Let the manufacturing cost be Rs.
x
.
Then the
wholesaler's cost price
= x+\cfrac{20}{100}x = Rs. \cfrac{6x}{5}
Retailer's cost price
= \cfrac{6x}{5}+\cfrac{25}{100}.\cfrac{6x}{5} = Rs. \cfrac{3x}{2}
Finally, consumer's purchasing price
= \cfrac{3x}{2}+\cfrac{20}{100}\times \cfrac{3x}{2} = Rs. \cfrac{9x}{5}
Thus, on the manufacturing cost of Rs.
x
, the consumer pays
(\cfrac{9x}{5}-x) = Rs. \cfrac{4x}{5}
over and above.
\therefore
% price paid by consumer over and above manufacturing cost
= \cfrac{4x}{5}\times\cfrac{1}{x} \times 100 = 80
.
A person purchases
20
litres of juice at
Rs. 2.20
per litre and diluted it with water to make the contents
22
litres. In order to earn
10\%
profit he should sell the juice at
Report Question
0%
Rs. 2.20
0%
Rs. 2.00
0%
Rs.2.35
0%
Rs. 2.40
Explanation
Volume of juice purchased
= 20
litres
Rate at which juice purchased
= Rs.2.20
per litre
\Rightarrow
Cost price of juice
= 20 \times 2.2 = Rs..44
In order to gain
10\%
profit,
Selling price
= \dfrac{110}{100} \times 44 = 48.4
Final volume of juice after dilution
= 22
litres
\therefore
Rate of selling
= \dfrac{48.4}{22} = Rs. 2.20
A and B invest Rs. 200 and Rs. 300, respectively, in a business for a period of three years and two years, respectively. Then the profit will be divided into the ratio of
Report Question
0%
4 : 3
0%
2 : 3
0%
1 : 1
0%
6 : 5
Explanation
Interest earned
\propto
Amount invested
\times
Time
\therefore
Profit of A
:
Profit of B
= 200\times 3 : 300 \times 2
= 1:1
How many
\text{kg}
of sugar costing
\text{Rs.}\ 5.75
per
\text{kg}
should be mixed with
75\ \text{kg}
of cheaper sugar costing
\text{Rs.}\ 4.50
per
\text{kg}
so that the mixture is worth
\text{Rs.}\ 5.50
per
\text{kg}
?
Report Question
0%
350\ \text{kg}
0%
300\ \text{kg}
0%
250\ \text{kg}
0%
325\ \text{kg}
Explanation
Let say
x\ \text{kg}
sugar costing
\text{Rs.}\ 5.75
per
\text{kg}
is added.
Total cost
= \text{Rs.}\ (5.75x + 75) \times 4.50
=\text{Rs.}\ (5.75x+337.5)
Total sugar
= (x + 75)\ \text{kg}
Average cost of sugar mixture
=\dfrac{\text{Total cost of sugar}}{\text{Total sugar}}
5.5 = \dfrac{\left(5.75x + 337.5\right)}{\left(x + 75\right)}
5.5x + 412.5 = 5.75x + 337.5
75 = 0.25x
x =\dfrac{75}{0.25}
\therefore\,x = 300\ \text{kg}
The list price of a parker pen is Rs. 160 and a customer buys it for Rs. 122.40 after two successive discounts. If first is 10%, then the second is
Report Question
0%
18%
0%
17%
0%
16%
0%
15%
Explanation
\Rightarrow
The list price of parker pen is
Rs.160
\Rightarrow
Selling price of parker pen is
Rs.122.40
\Rightarrow
Total discount =
Rs.160-Rs.122.40=Rs.37.60
\Rightarrow
Fist discount is
10\%
on list price
\therefore
Fist discount =
\dfrac{10}{100}\times 160=Rs.16
\Rightarrow
Second discount =
Rs.37.60-Rs.16=Rs.21.60
\Rightarrow
Pen price after 1st discount =
Rs.160-Rs.16=Rs.144
\Rightarrow
Second discount
\%
=
\dfrac{21.60}{144}\times 100=15\%
A shopkeeper professes to sell the goods at cost price, but he uses a weight of 900 grams for a Kilogram. Then his gain percent is
Report Question
0%
\dfrac{100}{9}
%
0%
\dfrac{100}{8}
%
0%
\dfrac{100}{7}
%
0%
\dfrac{100}{6}
%
Explanation
Shopkeeper uses weight of 900 grams for a kilogram or 1000 grams.
\Rightarrow
\text{Profit} = 1000-900=100
\text{Profit}\ \%=\dfrac{100}{900}\times 100=\dfrac{100}{9}\%
A began business with Rs. 4,500 and was joined afterward by B with Rs. 5,If the profit at the end of the year was divided in the ratio of 2:1, then the time of joining B was after:
Report Question
0%
5 months
0%
7 months
0%
8 months
0%
9 months
Explanation
\Rightarrow
Let B remained in the business for
x
months. Then,
\Rightarrow
\dfrac{A}{B}=\dfrac{4500\times 12}{5400\times x}=\dfrac{54000}{5400x}=\dfrac{10}{x}
\therefore
\dfrac{10}{x}=\dfrac{2}{1}
\Rightarrow
2x=10
\therefore
x=5
\Rightarrow
Thus, B remained in the business for 5 months.
\Rightarrow
So, B joined the business after
7\, months.
The population of a small town is increased by
\cfrac{15}{2}
% per annum for two years. If the present population is
73, 960
, then two years before the population was
Report Question
0%
68,000
0%
70,000
0%
64,000
0%
60,000
Explanation
A=P(1+\cfrac{R}{100})^n
73960=P(1+0.075)^2
\therefore P=64000
During a sale, a shop offered a discount of
10\%
on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs
1450
and two shirts marked at Rs
850
each
Report Question
0%
Rs
2835
0%
Rs
3000
0%
Rs
2830
0%
Rs
2800
Explanation
Given Marked Price of Jeans = Rs 1,450
Market Price of two Shirts= Rs 1,700
Total Price of a pair of jeans and two shirts
=1450+2\times 850=3150
Now,
Discount = Marked Price x % Discount
=3150\times \dfrac { 10 }{ 100 }
=315
\therefore
Effective Price After Discount = Rs.
\left( 3150-315 \right) =
Rs.
2,835
If the population of a town is 64,000 and its annual increase is 10%, then its correct population at the end of 3 years will be
Report Question
0%
80,000
0%
85,000
0%
85,100
0%
85,184
Explanation
Population (P)
= 64,000
Annual increase rate
(r) = 10\%
Hence, population after
n=3
years
= P(1+\cfrac{r}{100})^n
= 64,000(1+\cfrac{10}{100})^3
= 64,000\times (\cfrac{11}{10})^3
= 64,000\times \cfrac{11\times 11\times 11}{1000}
= 85,184
A shopkeeper sells a badminton racket marked at Rs. 30 at 15% discount and gives a shuttle cock costing Rs. 1.50 free with each badminton racket. He then makes a profit of 20%. His cost price per badminton racket is
Report Question
0%
Rs. 35
0%
Rs. 30
0%
Rs. 25
0%
Rs. 20
Explanation
\Rightarrow
Marked price =
Rs.30
\Rightarrow
Selling price =
Rs.[(\dfrac{85}{100}\times 30)-1.50]
\Rightarrow
Selling price =
Rs.(25.50-1.50)=Rs.24
.
\Rightarrow
Let Cost price be
Rs.x
\Rightarrow
Then,
120\%
of
x=24
\Rightarrow
x=\dfrac{24\times 100}{120}=Rs.20
.
An agent makes a profit of 20% even after a discount of 10% on the advertised price. If he makes a profit of Rs. 900 on the sale of a scooter, then the advertised price is
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0%
Rs. 4,500
0%
Rs. 4,000
0%
Rs. 6,000
0%
Rs. 5,050
Explanation
The advertising price is basically the marked price.
Agent makes a profit of
20\%
after giving a discount of
10\%
Marked Price
\times
(1
-
Discount
\%) =
Cost Price
\times (1 +
Profit
\%)
\therefore MP\times \dfrac{90}{100} = CP \times \dfrac{120}{100} = SP
Profit
= SP - CP
\therefore 900 = \dfrac{20}{100} \times CP
CP = 4500
\Rightarrow
Advertised Price
= \dfrac{120}{90} \times 4500 =
Rs.
6000
Answer
=
Rs
6000
A sum of money becomes Rs. 13380 after 3 years and Rs. 20070 after 6 years on compound interest. The sum is
Report Question
0%
Rs. 8800
0%
Rs. 8890
0%
Rs. 8920
0%
Rs. 9040
Explanation
Let the sum be Rs.
x
. Then ...(i)
x (1+\cfrac{R}{100})^3 = 13380
and
x (1+\cfrac{R}{100})^6 = 20070
...(ii)
Dividing equation (ii) by (i), we get
(1+\cfrac{R}{100})^3 = (\cfrac{200070}{13380}) = (\cfrac{3}{2})
\therefore x\cfrac{3}{2} = 13380
\Rightarrow x = (13380\times \cfrac{2}{3}) = 8920
Hence, the sum is Rs. 8920
A shopkeeper gives a discount of 25% on the marked price of an article and still earns a profit of 20% on his outlay, if he had not given any discount, then the profit on his outlay would have been
Report Question
0%
45%
0%
50%
0%
55%
0%
60%
Explanation
Let the Market Price
=
Rs. 100, Discount
=
25%
Discounted Price
= Rs. 100\times \cfrac{100-25}{100}
Rs. 100\times \cfrac{75}{100} = Rs. 75
Profit = 20
%
\therefore
Cost Price
= Rs. 75\times \cfrac{100}{100+20}
= Rs. 75\times \cfrac{100}{120} = Rs. \cfrac{125}{2}
Had he not given discount, his profit would have been
= Rs. 100-Rs. \cfrac{125}{2} = Rs. \cfrac{75}{2}
Profit on Rs.
\cfrac{125}{2} = Rs. \cfrac{75}{2}
\therefore
Profit on Rs. 100
= \cfrac{75}{2}\times \cfrac{2}{125}\times 100 = 60\%
An article marked at Rs 135 is sold for Rs 118.Then the rate of discount offered is
Report Question
0%
10%
0%
12%
0%
14%
0%
16%
Explanation
Given: Marked price of article is
Rs.135
.
and Selling price of article is
Rs.118.80
Price of article after discount
=
Marked price of article -
Selling price of article
=Rs.135-Rs.118.8
=Rs16.2
\Rightarrow
Rate of discount
=\dfrac{16.2}{135}\times 100
=12\%
A tree increases annually by one-fourth of its height. What will be it's height after
2
years, if it stands
64
cm high today?
Report Question
0%
76
cm
0%
80
cm
0%
100
cm
0%
105
cm
Explanation
Initial height
=64\ cm
Every year it increases one-fourth of it's height.
Increase
\%= (\cfrac{1}{4}\times 100\%)=25\%
Height after
2
years
= 64\times \left(1+\cfrac{25}{100}\right)^2\ cm
= 64\times \left(1+\cfrac{1}{4}\right)^2\ cm
= 64\times \left(\cfrac{5}{4}\right)^2\ cm
= (64\times \cfrac{5}{4}\times \cfrac{5}{4})\ cm
= 100\ cm
Hence, the height of the tree after
2
years will be
100\ cm
A started business with Rs. 4,500 and B joined afterward with Rs. 3,If the profits at the end of one year were divided in the ratio 2 : 1, respectively, then B would have joined A for business after
Report Question
0%
1 month
0%
2 months
0%
3 months
0%
4 months
Explanation
A's 1 month's investment
= Rs. (4500\times 12)
= Rs. 54,000
Let B joins after
x
months.
\therefore
B's 1 month's investment
= Rs.3,000 (12 -x)
By hypothesis
54,000 : 3,000 (12 -x) = 2 : 1
or
\cfrac{18}{12-x} = 2
or
18 = 24-2x
or
2x = 6
\therefore x = 3
months
The current population of a town is 10,If the population increases by
10\%
every year, then the population of the town after three years will be
Report Question
0%
13,310
0%
13,500
0%
14,000
0%
14,500
Explanation
A=P(1+\cfrac{R}{100})^n
A=10000(1+0.1)^3=13310
If the simple interest on a sum of money at 5% per annum for 3 years is Rs. 12000, the compound interest on the same sum for the same period at the same rate, is
Report Question
0%
Rs. 12600
0%
Rs. 12610
0%
Rs. 12640
0%
Rs. 12650
Explanation
Clearly, Rate =
5\; \%
, Time =
3
years and S.I. =
\text{Rs.}\;12000
Sum
= \text{Rs.} \left (\cfrac{100\times 12000}{3\times 5}\right ) = \text{Rs.}\; 80000
Amount
= \text{Rs. } \left [80000\times \left (1+\cfrac{5}{100}\right )^3\right ]
= \text{Rs. } 92610
We know that C.I. = Amount - Sum
So,
C.I.
= 92610-80000
= \text{Rs. } 12610
What was the cost price of the suitcase purchased by Samir?
(1) Samir got 20 per cent concession on the labelled price.
(2) Samir sold the suitcase for Rs. 2000 with 25 per cent profit on the labelled price.
Report Question
0%
1280
0%
2301
0%
1602
0%
1222
Explanation
(2)
\Rightarrow
Labelled price
=\frac {2000}{125}\times 100=Rs. 1600
(1)
\Rightarrow
C.P. of suitcase
=1600(1-\frac {20}{100})=Rs. 1280
Hence, both the statements together are necessary to answer the question.
A shopkeeper purchases 11 pens for Rs. 10 and sells them at the rate of Rs. 11, then the profit is
Report Question
0%
8%
0%
9%
0%
10%
0%
11%
A shopkeeper mixes 80 kg sugar worth of Rs. 6.75 per kg with 120 kg of sugar worth of Rs. 8 per kg. He earns a profit of 20% by selling the mixture. He sells it at the rate.
Report Question
0%
Rs. 7.50 per kg
0%
Rs. 9 per kg
0%
Rs. 8.20 per kg
0%
Rs. 8.85 per kg
Explanation
Total cost
=80\times 6.75+120\times 8=Rs. 1500
Selling price
=1500\times \dfrac {120}{100}=Rs. 1800
S.P. per kg
=\dfrac {1800}{200}=Rs.9
If the cost of a pen is Rs. 12.60 and the gain was
10\%
of the marked price, then the marked price of the pen was
Report Question
0%
Rs. 15
0%
Rs. 14
0%
Rs. 13
0%
Rs. 12
Explanation
Given cost price 12.60
Profit
= 10\%
Selling price = Cost price + Profit
Profit
=12.60 \times \cfrac{10}{100}=1.26
Selling price
= 12.60+1.26=13.86
,
which is approximately 14.
So, the correct answer is option B.
Marked price of a Saree is Rs. 600 and is available on Rs.Rate of discount is :
Report Question
0%
25%
0%
30%
0%
15%
0%
40%
Explanation
MP=600, SP=450
Disc=\dfrac{600-450}{600}=\dfrac {150}{600}\times 100=25
%
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