Explanation
Let total cost of all goods be Rs. 100. He sold 13 of his goods that is Rs. 33.3 at a profit of 14% Then profit =33.3×14100= Rs. 4.662 Simillarly 35=60, Profit 17.5% Then profit =60×17.5100=0.60×17.5=10.5 Now 100−(33.3+60)=100−93.3= Rs. 6.7 Profit on Rs. 6.7=6.7×20100=1.34 Total profit =4.662+10.5+1.34= Rs. 16.502=16.5%
Let the C.P. for Sanjay be Rs. x Then, S.P. for Sanjay = x + 46\% of x =x+\dfrac {46}{100}x=\dfrac {146x}{100} \therefore C.P. of Salman =\dfrac {146x}{100}+40 \because Salman made neither profit nor loss. \dfrac {146x}{100}+40=1500 \Rightarrow \dfrac {146x}{100}=1460
\Rightarrow x=\dfrac {1460\times 100}{146}= Rs. 1000.
Let the C.P. of a goat be Rs. x
Then, C.P. of the other goat = Rs. (1008 - x) \because S.P. of the both the goats is the same, Therefore, x\times \dfrac {(100-20)}{100}=(1008-x)\times \dfrac {144}{100} \Rightarrow 80x=1008\times 144-144x \Rightarrow 224x=1008\times 144 \Rightarrow x= Rs. \dfrac {1008\times 144}{224}= Rs. 648
C.P. = Rs. 950 - 10\% of Rs. 950
\Rightarrow 950-\dfrac{10}{100}\times 950
\Rightarrow 950-95= Rs. 855 Repairs cost = Rs. 45 \therefore Net C.P. = Rs. 855+ Rs. 45= Rs. 900, \text{Profit}=25\%
S.P. =\dfrac{100+\text{profit}\%}{100}\times \text{C.P.}
\therefore S.P. = Rs. \left (\dfrac {900\times 125}{100}\right )= Rs. 1125
Let the C.P. of the article be Rs. x
Then, S.P. of the article at a loss of 20\% =\dfrac {80}{100}\times x= Rs. \dfrac {80x}{100} S.P. of the article at a profit of 5\% =\dfrac {105}{100}\times x= Rs. \dfrac {105x}{100} According to the question, we have \dfrac {80x}{100}+100=\dfrac {105x}{100}
\Rightarrow \dfrac {105x}{100}-\dfrac {80x}{100}=100 \Rightarrow x=\dfrac {100\times 100}{25}= Rs. 400
S.P. of each article = Rs. \left (\dfrac {37.40}{2}\right )= Rs. 18.70 Discount rate =15\% \therefore M.P. of each article = Rs. \dfrac {18.70\times 100}{(100-15)}= Rs. \dfrac {1870}{85}= Rs. 22.
Let the C.P. of the item be Rs. 100 Then, M.P. = Rs. 140, Discount = 25\% \therefore S.P. = Rs. 140 - 25\% of Rs. 140 = Rs. 140-\dfrac {25}{100}\times Rs. 140
=140-35= Rs. 105 \therefore Profit = Rs. 105- Rs. 100= Rs. 5 Profit \% =\dfrac {5}{100}\times 100=5\%.
S.P. = Rs. 444, Discount = 26\% Let M.P. = Rs. x
Then, M.P. - discount = S.P,
x - 26\% of x = 444 \Rightarrow x-\dfrac{13x}{50} = 444 \Rightarrow \dfrac{37x}{50}=444
\Rightarrow x=\dfrac{444\times 50}{37}= Rs. 600
Let the C.P. of the transistor be Rs. xProfit =30\% of Rs. x = Rs. \dfrac {3x}{10}S.P. = Rs. 572
C.P. + Profit = S.P. Therefore, x+\dfrac {3x}{10}=572
\Rightarrow \dfrac {13x}{10}=572 \Rightarrow x= Rs. \dfrac {572\times 10}{13}= Rs. 440
Given, C.P. = Rs. 380, Profit = 25\% \therefore S.P. = Rs. \left (\dfrac {380\times 125}{100}\right )= Rs. 475 Discount = 5\% \therefore M.P. = Rs. \left (\dfrac {475\times 100}{95}\right )= Rs. 500
Let the M.P. of the cupboard be Rs x.
Then, (100-12.5)\% of (100-7.5)\% of Rs. x=2590
\Rightarrow \dfrac {87.5}{100}\times \dfrac {92.5}{100}\times x=2590 \Rightarrow x=\dfrac {2590\times 100\times 100}{87.5\times 92.5}= Rs. 3200
Given, Cost price of an article, CP= Rs 180 Profit or gain = 20 % Discount on the marked price of an article =10% Marked price of an article, MP=? Let the marked priice of an article be x. Discount on the marked price on an article =x-0.10 x =0.9 x \therefore Selling Price of an article is, SP=0.9x We know that, \dfrac{SP-CP}{CP}=Gain% Put SP=0.9x, CP=180, and Gain=20 % \dfrac{0.9x-180}{180}=20% \dfrac{0.9x-180}{180}=\dfrac{20}{100} \dfrac{0.9x-180}{180}=\dfrac{1}{5} \dfrac{0.9x-180}{36}=1 0.9x=36+180 0.9x=216 x=\dfrac{216}{0.9} x=240 \therefore Marked Price of an article is Rs 240.
Let the C.P. of the goods =Rs 100. Then, Marked price of the goods = Rs 140 Discount = 20% \therefore S.P. of the goods = 80% of Rs 140=Rs 112 \therefore Profit % =\dfrac {(112-100)}{100}\times 100=12%
Let M.P. = Rs. 100
Then S.P. =\dfrac{2}{5} of M.P. =\dfrac{2}{5}\times 100= Rs. 40
Loss =25\%
Then, C.P. =\dfrac{100}{100- \text{loss} \%}\times S.P.
\Rightarrow \dfrac{100}{100-25}\times 40
\Rightarrow \dfrac{100}{75}\times 40= Rs. \dfrac{160}{3}
M.P. : C.P. =100:\dfrac{160}{3}=300 : 160
=15:8
M.P. = Rs. 2,72,000. Discount = Rs. [(4\% of 2,00,000)+ (2.5\% of 72,000)]
=\left [\left (\dfrac{4}{100}\times 200000)+(\dfrac{2.5}{100}\times 72000\right)\right] = Rs. (8,000 + 1,800) = Rs. 9,800. Therefor, actual price = Rs. (2,72,000 - 9,800)= Rs. 2,62,200.
Let the C.P is =Rs. x
When S.P is Rs.340 then gain %=\dfrac{340-x}{x}\times 100
When S.P is rs.350 then gain %=\dfrac{350-x}{x}\times 100
According to the question
\Rightarrow \left[\dfrac{350-x}{x}\times 100 \right]-\left[\dfrac{340-x}{x}\times 100 \right]=5
\Rightarrow \dfrac{100}{x}[350-x-340+x]=5
\Rightarrow \dfrac{100}{x}[10]=5
\Rightarrow x=\dfrac{1000}{5}=200
Hence C.P of article is Rs.200.
let the M.P = Rs. x
Then S.P=x-10\% of x
\Rightarrow x-\dfrac{10x}{100}
\Rightarrow x-\dfrac{x}{10}
\Rightarrow \dfrac{9x}{10}Then \dfrac{9x}{10}=9
\Rightarrow 9x=10\times 9
\Rightarrow x=10
Let C.P. be Rs x
Then (1060 - x ) = \dfrac{120}{100} \times (x-950) \Rightarrow 10600 - 10x = 120x- 120 \times 950 \Rightarrow 220x = 220000 \Rightarrow x = 1000 \therefore Desired S.P. = Rs. \left (\dfrac{120}{100} \times 1000\right) = Rs. 1200
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