M.P=Rs. 11700

Let the marked price of the computer=Rs.x

Printed price=Rs.1600

Let the profit of the retailer=Rs.x

Let cost price be $$x$$
SP $$= x + 14\% $$ of $$ x=x+\dfrac{14x}{100} = 1.14x$$
If CP and SP were Rs. $$132$$ less, the profit would be $$(14 + 12)\%$$
New, CP $$= (x - 132)$$
SP $$ = 1.14x - 132$$
SP $$-$$ CP $$= 26\%$$ of $$(x - 132)$$
$$1.14x - 132 - x + 132 = \dfrac{26\times (x-132)}{100}$$
$$0.14x \times100 = 26x - 3432$$
$$14x - 26x = -3432$$
$$12x = 3432$$
$$x = 286$$
So, CP was Rs. $$286$$.

$$let,\,C.P=x$$
and $$gain\%=10\%$$
$$S.P=\left(\dfrac{100+gain}{100}\right)\times C.P\Rightarrow S.P=\dfrac{110x}{100}$$

$$new \,C.P=C.P-50$$
$$new \,S.P=S.P-50$$
$$gain\%=5\%\,more \,than\,previous=15\%$$
$$\Rightarrow New\,S.P=\left(\dfrac{100+gain}{100}\right)\times(New\,C.P)$$
$$\Rightarrow (S.P-50)=\left(\dfrac{100+15}{100}\right)\times(C.P-50)$$
$$\Rightarrow (\dfrac{110x}{100}\,-\,50)=\dfrac{115}{100}\times (x-50)$$
$$\Rightarrow \dfrac{110x}{100}\,-50=\dfrac{115x}{100}-\dfrac{115}{2}$$
$$\Rightarrow \dfrac{115}{2}\,-\,\dfrac{100}{2}=\dfrac{115x}{100}-\dfrac{110x}{100}$$
$$\Rightarrow \dfrac{15}{2}=\dfrac{5x}{100}$$
$$\therefore x=150$$

Let CP = x
SP = x + 5% of x = 1.05x
Now,
If he had bought it in 5% less,
CP = x - 5% of x = 0.95x
New SP = 1.05x + 45
New gain = 20% of 0.95x
1.05 + 45 - 0.95x = 20% of 0.95x
0.1x + 45 = 0.19x
0.09x = 45
x = 500
CP = Rs. 500

Let C.P. be $$x$$

Cost Price of bullock and cart $$=$$ Rs. $$1800$$.
Let bullock price was $$X$$ and cart price was $$(1800-X)$$
SP of both $$= 1800+\dfrac {155}{6}\%$$ of $$1800 = 2265$$
Profit $$=$$ Rs. $$465$$
$$X + 20\%$$ of $$X + (1800-X)+30\%$$ of $$(1800-X)=2265$$
$$1.2 X+1800-X +\dfrac { (54000 - 30 X)}{100} = 2265$$
$$1.2 X+1800 - X + 540 - 0.3 X = 2265$$
$$1.2 X - 1.3 X = 2265 - 1800 - 540$$
$$- 0.1 X = -75$$
$$X = 750$$
Cost of bullock is Rs. $$750$$.

Let C.P. $$= x$$
S.P. $$= x - 10\% $$ of $$ x=x-\dfrac{10x}{100}=\dfrac{90x}{100} = 0.9x$$
New S.P. $$= 0.9x + 5$$
Gain $$ =$$ S.P. $$ -$$ C.P.
$$\Rightarrow 15\%  $$ of $$ x = 0.9x + 5 - x$$
$$\Rightarrow 0.15x + x - 0.9x=5$$
$$\Rightarrow 0.25x = 5$$
$$\Rightarrow x = \dfrac{5}{0.25 }=$$ Rs. $$20$$
So, initial selling price $$= 20 - 10\% $$ of $$ 20=20-\frac{10}{100}\times 20 =$$ Rs. $$ 18.$$.

Let Total Profit is Rs. 100
After 5 % charity, profit  = Rs 95
So, share of A = (95 *3)/5 = Rs. 57
Now, comparing,
A share $$57$$ on profit $$100$$
So, A's share 1 on profit $$= 100/57$$
Thus, A shares Rs. $$8550$$ on  =$$ (8550 *100)/57 = Rs. 15000$$

Let initial rate was $$100$$
Now, $$40 \%$$ decrement in duty,
rate $$=$$ $$ 100 - 40 = 60$$
To make their revenue $$ 100 $$, consumption must be increase of $$40$$.
So, $$\%$$ increment $$ =$$ $$\dfrac{ (40 \times 100)} { 60} = \dfrac{200}{ 3} \%$$

Let the C.P. be $$x$$.
Then, Profit $$= 863 - x$$
Loss $$= x - 631$$
Given, profit $$=$$ Loss
$$\Rightarrow 863 - x = x - 631$$
$$\Rightarrow 2x = 863+631 = 1494$$
$$\Rightarrow x = \dfrac {1494}{2} = 747$$
Cost Price $$=$$ Rs. $$747$$

Let the cost of one toy be $$ x$$
Then, cost of $$18$$ toy $$= 18x$$
Gain $$ = 3x $$
SP of $$18$$ toys $$ =$$ Rs. $$16800$$
Gain $$=$$ S.P. $$-$$ C.P.
$$\Rightarrow 3x = 16800 - 18x$$
$$\Rightarrow 21x = 16800$$
$$\Rightarrow x = \dfrac{16800}{21}=$$ Rs. $$ 800$$

Total profit $$=$$ Rs. $$1100$$
Percent profit $$= 20$$
$$\Rightarrow 20\%  = 1100$$

Let price of two articles are $$3x$$ and $$4x$$
After increment price become $$3.3x$$ and $$(4x + 4)$$
Now, according to question,
$$\dfrac{3.3x}{(4x + 4)} = \dfrac{3}{4}$$
$$13.2x = 12x + 1$$
$$13.2x - 12x = 12$$
$$1.2x = 12$$
$$x = 10$$
So, original price of second article $$= 4x = 4 \times10 = $$Rs $$40$$.

Let the C.P for $$A=$$ Rs. $$ x$$ 

$$\text{CP of 2 dozen of apples}=Rs.\ 58$$

Total Population $$=18522000\left [1+\dfrac{5}{100}\right]^3$$ 

$$\Rightarrow$$  In this question we have given, 20% of student are not employed. Total student population is 100%.

M.P $$=Rs.11700$$

List price $$=Rs.18000$$

Let printed price of the article be Rs. $$x$$
According to the given statement:
        $$x \left(\displaystyle\frac{100+7}{100}\right) = 1070$$

Let the cost of the article be reduced to Rs. $$x$$.

According to question,

Let marked price of the article be Rs. $$x$$.
$$\therefore$$  Rs. $$x +$$ Rs. $$\displaystyle\frac{9x}{100} = $$ $$Rs. 2,452.50   $$           $$\because$$ Sales-tax $$= 9\%$$
On solving, we get : $$x = 2,250$$
$$\therefore$$ Marked price of the article $$= Rs. 2,250 =$$ Its selling price
Since, the shopkeeper buys the article for Rs. $$1,500$$ and spends $$20\%$$ of the cost as overheads,
$$\therefore$$ Total cost price of the article $$= Rs. 1,500 + 20\%\ of\ Rs. 1,500$$
                                           $$= Rs. 1,500 + Rs. 300 = Rs. 1,800$$
Profit = Selling price - Total cost price
         $$= Rs. 2,250 - Rs. 1,800 = Rs. 450$$
Profit % $$= \displaystyle\frac{450}{1800} \times 100$$% $$= 25\%$$

Difference between depreciations of 2nd year and 3rd year
$$= Rs. 4,752 - Rs. 4,181.76 = Rs. 570.24$$
$$\Rightarrow$$ Depreciation of one year on Rs. 4,752 $$=$$ Rs. 570.24
$$\Rightarrow$$ Rate of depreciation $$=\displaystyle \frac{Rs. 570.24}{Rs. 4,752}\times 100\%=12\%$$    Ans.

Therefore, population after $$2$$ years $$=12500\times\begin{Bmatrix}1+\dfrac{8}{100}\end{Bmatrix}^2$$

Let marked price be Rs. $$x$$.
$$\therefore    x + 12$$% of $$x = 2,016$$

Initial price of bike is Rs. $$20000$$, time $$=2$$ years, rate od depreciation $$=5\%$$

$$\Rightarrow$$  We have given that $$r$$ = Percent interest.

SP of the shirt $$=432$$

The first year's increase of $$10$$ percent can be expressed as $$1.10$$, the second year's increase can be expressed as $$1.05$$ and third year's decrease can be expressed as $$0.90$$. 

Original cost of an article $$=$$ Rs. $$80$$
Decrease in cost is $$=15$$ $$\%$$ of Rs. $$80=\dfrac{15}{100}\times80=\dfrac{1200}{100}=$$ Rs. $$12$$
Therefore, new cost of an article $$=$$ Rs. $$80-$$ Rs. $$12=$$ Rs. $$68$$.

Sales tax $$=$$ Price $$\times$$ Tax Rate

$$\Rightarrow$$  Let number of towels bought for $$\$120$$ be $$n$$.

Let the number of years be $$n$$

Given, $$P=15000, r=4\%, n=2$$ years

Merchant $$B$$ computes his profit as a percentage of selling price. He makes a profit of $$25\%$$ on selling price of Rs. $$1000$$ i.e. his profit $$=25\%$$ of $$1000=$$ Rs. $$250$$.
Merchant $$A$$ computes his profit as a percentage of cost price.
Therefore, when he makes a profit of $$25\%$$ or $$\left (\dfrac{1 }{4}\right)^{th}$$ of his cost price, then his profit expressed as a percentage of selling price $$=$$ or $$20\%$$ of selling price.
So, merchant $$A$$ makes a profit of $$20\%$$ of Rs. $$1000=$$ Rs. $$200$$.
Merchant B makes a profit of Rs. $$250$$ and merchant A makes a profit of Rs. $$200$$.
Hence, merchant $$B$$ makes Rs. $$50$$ more profit than merchant $$A$$.

Formulas required for this sum:

To get the percent you will divide the numerator by the denominator.

Sahil purchased a machine at $$Rs.\ 10000$$.

Let the selling price per article be $$=$$ Rs. $$1$$
Therefore, selling price of $$50$$ articles $$=$$ Rs. $$50$$
Profit on sale of $$50$$ articles $$=$$ selling price of $$25$$ articles $$=$$ Rs. $$25$$.
S.P $$=$$Rs. $$ 50$$, Profit $$=$$ Rs. $$25$$ 

The approximate values is the estimated values and the exact value is the real value.

Given, absolute value $$=120$$ and exact value $$=60$$ 

Given:-

Population after $$4$$ years $$=$$ $$\text{Present Population}$$ $$\left (1+\dfrac{r}{100}\right)^n$$

An income tax is a government tax on the taxable profit earned by an individual or corporation.