MCQ Questions for Class 8 Maths Comparing Quantities Quiz 9

Aarati bought 10 dresses at RsShe paid Rs 200 extra as expenses. If she sold all the dresses at the cost of Rs 780 per dress, how much percentage profit or loss does she make?

0%
20% profit
0%
20% loss
0%
40% profit
0%
30% profit

Explanation

Cost price of

$10$ dresses is

$Rs.\ 6300$ and expanses is

$Rs.\ 200$ .

So, cost price after expanses

$=Rs.\ (6300+200)=Rs.\ 6500$

Also, selling price of

$1$ dress is

$Rs.\ 780$ .

Hence, selling prince

$10$ dresses

$=10\times 780=Rs.\ 7800$

Now,

$SP>CP$ , so their will be net profit.

So, profit percent is,

$Profit(\%)=\dfrac{7800-6500}{6500}\times 100=\dfrac{1300}{65}=20\%$

The value of a machine depreciates every year by

$5\%$ . If the present value of the machine be Rs.

$100,000$ , what will be its value after two years?

0%
Rs. $100,050$
0%
Rs. $90, 250$
0%
Rs. $99,250$
0%
Rs. $99,000$

Explanation

current value of Machine

$=Rs. 100,00$

After 1 year

value decreased by

$5 \%$

value of Machine is

$Rs. 95 \%$

$of$

$100,000$

$\Rightarrow \dfrac{95}{100} \times 100,000 = Rs. 95,000$

After 2 years

again the value is decreased by

$5 \%$ from previous year' s Value

Now value of Machine is

$= 95 \%$

$of$

$95,000$

$= \dfrac{95}{100} \times 95,000$

$=0.95\times 95,000$

$= Rs. 90,250$ is the value of machine at the of two years

$15.5$ litres of refined oil costs Rs.

$1063.30$ , what is the cost of

$1$ litre of refined oil?

0%
Rs. $68.60$
0%
Rs. $75.95$
0%
Rs. $70.89$
0%
Rs. $62.55$

Explanation

Given that

$15.5$ litres refined oil costs

$\rightarrow$

$1063.30$ Rs

Cost of

$1$ litre refined oil will be

$\dfrac {1063.30}{15.5}=$

$68.60$

Thus

$1$ litre refined oil costs Rs.

$68.60$ .

Hence, option A is correct.

The compound interest on Rs.

$100000$ at

$20\%$ per annum for

$2$ years

$3$ months, compound annually is ________.

0%
Rs. $151200$
0%
Rs. $100000$
0%
Rs. $51200$
0%
Rs. $251200$

Explanation

Given,

$P=100000$ ,

$r=0.2$ ,

$n=2+\dfrac{1}{4}$ (converting

$2$ years

$3$ months to years)

$=n=2.25$

Interest is compounded anually,

For first year

$=100000\times 0.2\times 1=20000$

For second year

$P_{new }= 120000$

Interest

$=120000\times 0 .2\times 1=24000$

For last

$0.02544$ year,

$p_{new}=144000$
Interest

$= 144000\times 0.2\times 0.25=7200$

New amount

$=144000+7200 = 151200$

$\text{Interest} = 151200+100000=51200$

Bhajan Singh purchased

$120$ reams of paper at Rs.

$80$ per ream. He spent Rs.

$280$ on transportation, paid octroi at the rate of

$40$ paise per ream and paid Rs.

$72$ to the coolie. If he wants to have a gain of

$8\%$ , what must be the selling price per ream?

0%
Rs. $86$
0%
Rs. $87.48$
0%
Rs. $89$
0%
Rs. $90$

Explanation

Total money he spent

$=(120\times 80)+(280+0.4)\times (120+72)$

$=10000$

Let the selling price of paper per ream is

$x$ then total

$S.P.=120x$

If he wants to have a gain of

$8\%$ .

Then by using the formula

$P\%=\dfrac{S.P.-C.P.}{C.P.}\times100$

$8=\dfrac{120x-10000}{10000}\times100$

$\Rightarrow 120x=1.08\times 10000$

$\Rightarrow x=90$

Therefore, selling price per ream is Rs.

$90$ .

After allowing a discount of

$25\%$ on the marked price of a shirt, it is sold for Rs.

$240$ . Find the marked price of the shirt.

0%
Rs. $115$
0%
Rs. $320$
0%
Rs. $240$
0%
Rs. $50$

Explanation

Let marked price be

$x$

Selling price

$=$ Rs

$240$

Discount allowed on the shirt

$= 25\%$

$\Rightarrow x - \dfrac{25 x}{100} = 240$

$\Rightarrow \dfrac{75x}{100} = 240$

$\Rightarrow x =$ Rs.

$320$

The cost of a vehicle is Rs.

$1,75,000$ . If its value depreciates at the rate of

$20\%$ per annum, then the total depreciation after

$3$ years was _________.

0%
Rs. $86,400$
0%
Rs. $82,500$
0%
Rs. $84, 500$
0%
Rs. $85,400$

Explanation

Cost of vehicle

$= 175000$

Depreciation for first year

$= \dfrac{20}{100}\times175000=35000$

Cost of vehicle after first year

$= 175000-35000=140000$

Depreciation for second year

$= \dfrac{20}{100}\times140000 = 28000$

Cost of vehicle after second year

$= 140000-28000=112000$

Depreciation for third year

$= \dfrac{20}{100}\times112000 = 22400$

Total depreciation after

$3$ years

$= 35000+28000+22400 = 85400$

Hence, the answer is Rs.

$85,400$ .

How many of the following transactions are profitable?
i) Two tables bought for Rs.30,500 and sold each at Rs.15,500.
ii) Three fans bought for Rs.12,500 and sold each at Rs.4,300.
iii) Three shirts bought for Rs.450 each and sold at Rs.1,430.
iv) Two computers bought for Rs.15,200 each and sold at Rs.38,500.
v) A pair of denims bought for Rs.1,000 and sold at Rs.850.
vi) Two mobiles bought for Rs.49,000 and sold each at Rs.25,300.

0%
$6$
0%
$3$
0%
$4$
0%
$5$

Explanation

Profit is there when selling price is greater then cost price.

$(1)$

$CP=Rs.30,500\\SP=15,500\times 2=31,500\\SP>CP$

$\implies$ Profit

$(2)$

$CP=Rs.12,500\\SP=4,300\times 3=12,900\\SP>CP$

$\implies$ Profit

$(3)$

$CP=450\times 3=Rs.1,350\\SP=1,430\\SP>CP$

$\implies$ Profit

$(4)$

$CP=15,200\times 2=Rs.30,000\\SP=38,500\\SP>CP$

$\implies$ Profit

$(5)$

$CP=Rs.1,000\\SP=850\\SP<CP$

$\implies$ Loss

Hence ,there are total

$5$ profitable transactions.

Kabir buys an article with

$25\%$ discount on its marked price. He makes a profit of

$10\%$ by selling it at Rs.

$660$ . The marked price is ___________.

0%
Rs. $600$
0%
Rs. $700$
0%
Rs. $800$
0%
Rs. $685$

Explanation

let the marked price is Rs.

$x$

the price for which he bought

$=(1-.25)\times x=0.75x$

he sells it at

$660$ and makes a profit of

$10\%$

$\dfrac{660-0.75x}{0.75x}=0.1$

$660-0.75x = 0.075x$

$660=0.825x$

$x=800$

If selling price of

$10$ articles is equal to cost price of

$11$ articles, then gain is:

0%
$8$ %
0%
$9$ %
0%
$8.5$ %
0%
$10$ %

Explanation

Let CP of

$1$ article =Rs.

$1$
CP of

$11$ article =Rs.

$11$
CP of

$10$ article =Rs.

$10$
SP of

$10$ article =Rs.

$11$
Profit %

$=\cfrac { 11-10 }{ 10 } \times 100$

$=10$ %

A man earns Rs.

$20$ on the first day and spends Rs.

$15$ on the next day. He again earns Rs.

$20$ on the third day and spends Rs.

$15$ on the fourth day. If he continues to save in this way, how soon will he have Rs.

$60$ in hand?

0%
On $12$ th day
0%
On $24$ th day
0%
On $17$ th day
0%
On $27$ th day

Explanation

In two days saving

$=$ Rs.

$5$
Saving in

$16$ days

$=$ Rs.

$40$
Income on

$17$ th day

$=$ Rs.

$60$
Inhand on

$17$ th day

$=$ Rs.

$60$ .

A shirt was sold at a profit of 15

$\%$ . If its cost had been 5

$\%$ less and it had been sold for Rs. 21 less, then the profit would have been 10

$\%$ . Find the cost of the shirt.

0%
$Rs.\ 210$
0%
$Rs.\ 220$
0%
$Rs.\ 100$
0%
$Rs.\ 200$

Explanation

Given that:

A shirt was sold at a profit of

$15\%$ .

If the cost had been

$5\%$ less, and it had been sold for

$Rs.\ 21$ less, then the profit would have been

$10\%$ .

To find out:

The cost of the shirt.

Let the cost of the shirt be

$Rs.\ x$ .

We know that,

$S.P.=\dfrac{(profit\%+100)C.P.}{100}$

Here,

$profit\%=15$

$\therefore\ S.P.=\dfrac{(15+100)x}{100}\\$

$\Rightarrow S.P.=1.15x\\$

Now, if the cost is

$5\%$ less, then,

$C.P.=95\%\ of\ x\\$

$\Rightarrow C.P.=\dfrac{95}{100}x\\$

$\therefore \ C.P.=0.95x\\$

Also, the selling price is

$Rs. \ 21$ less.

$\therefore\ S.P.=1.15x-21\\$

In this case, the profit would have been

$10\%$ , as given in the problem.

Now, we know that,

$profit\%=\dfrac{S.P.-\ C.P.}{C.P.}\times 100$

$\therefore \ 10=\dfrac{(1.15x-21)-0.95x}{0.95x}\times 100\\$

$\Rightarrow 10=\dfrac{1.15x-21-0.95x}{0.95x}\times 100\\$

$\Rightarrow 10\times 0.95x=(0.20x-21)\times 100\\$

$\Rightarrow 9.5x=20x-2100\\$

$\Rightarrow 20x-9.5x=2100\\$

$\Rightarrow 10.5x=2100\\$

$\Rightarrow x=\dfrac{2100}{10.5}\\$

$\therefore \ x=Rs.\ 200\\$

Hence, the cost of the shirt is

$Rs.\ 200$ .

Publisher sells books to retailer at marked price which is

$20$ % above his outlay. If on cash payment, he allows a discount of

$10$ % go the marked price. The publisher thus gains

0%
$12$ %
0%
$10$ %
0%
$8$ %
0%
$14$ %

Explanation

Let CP of Book

$=100$
MP

$=120$
SP after Discount

$=\cfrac { 90 }{ 100 } \times 120=108$
Profit

$\% =8$ %

A dealer marked his goods

$20$ % above the cost price and allows a discount of

$10$ %. Then, the gain percent is

0%
$2$ %
0%
$4$ %
0%
$6$ %
0%
$8$ %

Explanation

Let CP be

$=100$
MP

$20$ % above CP

$=120$
After allowing Discount of

$10$ %

$SP=\cfrac { 90 }{ 100 } \times 120=108$
Gain

$=8$ %

Suppose for the principal

$P$ , rate

$R\%$ and time

$T$ years the simple interest is

$S$ and compound interest is

$C$ . Consider the possibilities :
(i)

$C > S$ (ii)

$C = S$ (iii)

$C < S$

Which of the following options hold?

0%
Only (i) is correct.
0%
Either (i) or (ii) is correct
0%
Either (ii) or (iii) is correct
0%
Only (iii) is correct.

Explanation

Case 1.

$C> S$

This is possible if interest is compounded quarterly or half-yearly.

Case 2.

$C=S$

This is possible if interest is compounded yearly.

Case 3.

$C<S$

It can not be true because simple interest cannot be greater than compound interest.

Hence, Option B is correct option.

Jogen's taxable income for

$2010-11$ is Rupees

$5,00,000$ . The tax rates are (i) nil for first

$1,50,000$ , (ii)

$10\%$ for

$1,50,001$ -

$3,00,000$ and (iii)

$20\%$ for the remaining. His Tax liability is:

0%
Rs $45000$
0%
Rs $50000$
0%
Rs $55000$
0%
Rs $60000$

A shopkeeper sold an article for

$\text{Rs. } 2090.42$ without any loss or profit. Approximately, what will be the profit percent, if he sells that article for

$\text{Rs. }2602.58$ ?

0%
$15\%$
0%
$20\%$
0%
$25\%$
0%
$30\%$

Explanation

Selling price of an article without any loss or profit

$=\text{Rs. } 2090.42$

$\therefore$ Cost price

$=\text{Rs. } 2090.42$

New selling price

$=\text{Rs. } 2602.58$

Profit

$=S.P - C.P. = \text{Rs. }2602.58 - \text{Rs. } 2090.42$

$=\text{Rs. } 512 .16$

$\therefore\text{Profit} \%=\dfrac{\text{Profit}}{C.P} \times 100 = \dfrac{512.16}{2090.42}\times 100$

$\simeq 25\%$ (approx)

A customized jewellery was sold at Rs

$1000$ with

$90\%$ discount on the 'making charges'. If the payment made for making charges was

$Rs100$ , what was the approximate rate of discount on the product?

0%
$35$
0%
$45$
0%
$47$
0%
$90$

Explanation

SP of jewellery include Rs

$100$ making charges =

$1000$
Where cost of jewellery = Rs

$900$
After

$90\%$ discount,

$10\%$ of making charge = Rs

$100$
Let making charge be =

$x$

$\dfrac{10x}{100} = 100$

$x = 1000$
Total CP of jewellery =

$1000+900 = Rs 1900$
Overall discount =

$\dfrac{900}{1900}\times100 = 47\%$ approx

A shop gives

$15$ % discount on the purchase of a T.V. If paid for a cash immediately, a further discount of

$12$ % is given. If the marked price is Rs.

$15,000$ ,what is the price of the T.V if cash purchase is made?

0%
Rs. $11,475$
0%
Rs. $11,220$
0%
Rs. $12,750$
0%
Rs. $10,950$

Explanation

Price of TV

$=15000$

After successive discount of

$15 \%$ and

$12 \$ % ,

We have

$15000\times \left( 1-\cfrac { 15 }{ 100 } \right) \times \left( 1-\cfrac { 12 }{ 100 } \right)$

$=Rs.11220$

Mr. Z buys an article for Rs. 70/- and sells it at a loss of 20%. Then the selling price will be

0%
Rs. 60
0%
Rs. 58
0%
Rs. 56
0%
Rs. 55

Explanation

Cost price of the article

$=Rs.\ 70 /-$ .

Loss

$=20\%\$

$\therefore Loss = 70 \times \dfrac{20}{100}=Rs.\ 14$

$\therefore$ Selling Price

$=Rs.\ 70-14$

$=Rs.\ 56$

A merchant bought 60 sheep. He sold 40 of them at Rs.10 of the sheep died. What should be the S.P of the remaining sheep, if he wants a profit of Rs. 800?

0%
Rs. 150
0%
Rs. 200
0%
Rs. 250
0%
Rs. 180

The compound interest on Rs. 5,000 for two years at 4% is

0%
Rs. 400
0%
Rs. 408
0%
Rs. 420
0%
Rs. 440

Explanation

SOLUTION:

The formula for compound interest is:

$A=P (1+\dfrac{r}{n})^{nt}$

$A=5000(1+\dfrac{4}{100})^{2}$

$A= 5408$

$interest = P -A = 408$

hence the correct opt: B

Choose the correct answer from the alternative given.
If the annual rate of simple interest increases from 10% to 12.5% . A mans yearly income increases by Rs.his principal (in rupees) is:

0%
50,000
0%
45,000
0%
60,000
0%
65,000

Explanation

Change in Rate of interest=

$\left ( \dfrac{25}{2} - 10 \right )\%= \dfrac{5}{2}\%$
According to the question,

$\dfrac{5}{2}$ % of principal = Rs. 1250
Hence, Principal =

$\dfrac{1250 \times 2 \times 100}{5}$ = Rs. 50000

After allowing

$15$ % discount, the selling price of a radio becomes

$Rs. 255$ . The marked price is

0%
$Rs. 500$
0%
$Rs. 600$
0%
$Rs. 400$
0%
$Rs. 300$

Explanation

Let the marked price of Radio be

$Rs. x$ .

After giving

$15\%$ discount, the selling price will be

$0.85x$
According to the question,

$0.85x = 255$

$x=\dfrac{255}{0.85}$

$x = Rs. 300$
Hence, the marked price of Radio is

$Rs. 300$ .

45% of x + 30% of 90=30%Then what is the value of x?

0%
80
0%
85
0%
90
0%
95

Explanation

SOLUTION:

$\dfrac {45}{100}$ x

$x$ +

$\dfrac {30}{100}$ x

$90$ =

$\dfrac {30}{100}$ x

$210$

$\dfrac {45}{100}$ x

$x$ = 63-27=36

$x$ = 36 x

$\dfrac {100}{45}$

$x$ = 80

hence the correct opt: A

The sale price of an article including taxes is

$Rs.\ 616.$ The rate of sales tax is

$10\%.$ If the shopkeeper has made a profit of

$12\%.$ find the cost price

0%
$Rs.\ 500$
0%
$Rs.\ 450$
0%
$Rs.\ 600$
0%
$Rs.\ 550$

Explanation

Let us assume that the sales price and cost price of the article is

$x$ and

$y.$

$\begin{aligned}{}SP + Tax& = 616\\x + \frac{{10x}}{{100}}& = 616\\\frac{{11x}}{{10}} &= 616\\x& = \frac{{616 \times 10}}{{11}}\\ &=Rs.\ 560\end{aligned}$

And,

$\begin{aligned}{}CP + Profit &= SP\\y + \frac{{12y}}{{100}}& = 560\\\frac{{28y}}{{25}} &= 560\\y& = \frac{{560 \times 25}}{{28}}\\ &=Rs.\ 500\end{aligned}$

Hence, the cost price of the article is

$Rs.\ 500.$

Two numbers are less than a third number by

$30\%$ and

$37\%$ respectively. How much percent is the second number less than the first?

0%
$10\%$
0%
$15\%$
0%
$20\%$
0%
$25\%$

Explanation

${\textbf{Step - 1: Taking two general number according to the given conditions}}{\text{.}}$

${\text{Let the three number be }}x,y{\text{ and }}z.$

${\text{We know that the first number is les than the third one by 30% ,so we can write,}}$

$x = z - 30\% (z) = z - \dfrac{{30}}{{100}}z = \dfrac{{70}}{{100}}z$

$x = 0.7z$

${\text{Similarly,we know that the second number is 37% less,so we can write}}$

$y = z - 37\% (z) = z - \dfrac{{37}}{{100}}z$

$y = 0.63z$

${\textbf{Step - 2: Finding relation between }}x{\text{ and }}y.$

${\text{Difference between }}x,y{\text{ = }}0.7z - 0.63z{\text{ }} = 0.07x$

${\text{So, required percentage is difference is what percent of first number}}$

$= \dfrac{{7x}}{{100}} \times \dfrac{{10}}{{7x}} \times 100 = \dfrac{{10}}{{100}} \times 100 = 10\%$

${\textbf{Hence option A is correct}}{\text{.}}$

The S.I. accrued on an amount of Rs.

$25,000$ at the end of three years is Rs.

$7,500$ . What would be the C.I. accrued on the same amount at the same rate in the same period?

0%
$7,750$
0%
$8,275$
0%
$8,500$
0%
$8,250$
0%
None of these

Explanation

Apply the formula for simple interest

$7500=\dfrac{25000\times R\times3}{100}$

$\implies R=\dfrac{7500}{250\times3}=10\%$

Interest for the

$1$ st year

$=\dfrac{25000\times10\times1}{100}$

$=2500$

Amount After the

$1$ st year

$=25000+$

$2500$

$=27500$

Interest for the

$2$ nd year

$=\dfrac{27500\times10\times1}{100}$

$=2750$

Amount After the

$2$ nd year

$=27500+$

$2750$

$=30250$

Interest for the

$3$ rd year

$=\dfrac{30250\times10\times1}{100}$

$=3025$

Amount After the

$3$ rd year

$=30250+$

$3025$

$=33275$

$\therefore$ Compound Interest(CI)

$=33275-$

$25000$

$=Rs.8275$

Choose the correct answer from the alternative given.
A man had

$100$ kgs of sugar, part of which he sold at

$7\%$ profit and rest at

$17\%$ profit. He gained

$10\%$ on the whole. How much did he sell at

$7\%$ profit?

0%
$65$ kg
0%
$35$ kg
0%
$30$ kg
0%
$70$ kg

A shopkeeper offers successive discounts of

$20$ %,

$10$ % and

$5$ % respectively on a Titan watch which is marked at Rs.

$1500$ . He offers successive discounts of

$20$ %.

$20$ % and

$10$ % espectively on a Ajanta watch which is marked at Rs.

$2000$ . What is the difference between their selling price?

0%
Rs. $152$
0%
Rs. $126$
0%
Rs. $26$
0%
Rs $0$

Explanation

Selling price of Titan watch
=

$0.8 \times 0.9 \times 0.95 \times 1500 = Rs. 1026$
Selling price of Ajanta watch
=

$0.8 \times 0.8 \times 8.9 \times 2000 = Rs. 1152$
Difference is selling price = Rs.

$(1152 - 1026) = Rs. 126$

The difference in compound interest and simple interest for one year for Rs.

$1,000$ at

$10\%$ p.a. is?

0%
$10$
0%
$5$
0%
$0$
0%
None of the above

Explanation

$SI = \cfrac{1000 \times 10 \times 1}{100} = ₹100$

Compound interest for the first year

$= \cfrac{1000 \times 10 \times 1}{100} = ₹100$

$CI - SI =$

$100-100 = 0$

If the interest on a certain sum for first year at

$5\%$ p.a. compounded is Rs.

$25$ then, the total interest at the end of second year will be.

0%
$51.25$
0%
$50$
0%
$26.25$
0%
None of the above

Explanation

$I=25$

$R=5%$

$SI=\cfrac{P\times R \times T }{100}$

$25 = \cfrac{P \times 5\times 1}{100}$

$P= \cfrac{25 \times 100}{5} = ₹500$

Amount after first year

$= 500 + 25 = 525$

Interest for second year

$= \cfrac{525 \times 5\times 1}{100} = 26.25$

Total interest

$= 25+26.25$

$= Rs51.25$

Mrs. S deposited Rs.

$1,00,000$ in a nationalized bank for

$3$ years. If the rate of interest is

$7\%$ p.a., Interest is compounded annually. Calculate the amount at the end of third year (i.e., Principal

$+$ compound interest)

0%
$1,22,504.03$
0%
$1,02,504.30$
0%
$1,22,505.30$
0%
$1,22,405.30$

Explanation

Interest for the

$1^{ st }$ year

$= Rs.\dfrac { 100000\times 1\times 7 }{ 100 } =Rs. 7000$

Amount after the

$1^{ st }$ year

$= Rs. 100000 + Rs.7000= Rs. 107000$

Interest for the

$2^{nd}$ year

$= Rs.\dfrac{107000\times 1\times 7}{100} = Rs.7490$

Amount after the

$2^{nd}$ year

$= Rs. 107000 + Rs. 7490 = Rs. 114490$

Interest for the

$3^{ rd }$ year

$= Rs. \dfrac { 114490\times 1\times 7 }{ 100 } = Rs. 8014.3$

$\therefore$ Amount at the end of the

$3^{rd}$ year

$= Rs. 114490+ Rs. 8014.3= Rs. 122504.30$

A loss of

$20$ % is incurred when

$6$ articles are sold for a rupee. To gain

$20$ % how many articles should be sold for a rupee?

0%
$1$
0%
$2$
0%
$3$
0%
$4$

Explanation

Given than,

$SP = 1, Loss$ %

$= 20$ %
We know that,

$SP = 0.8\times CP$

$CP = \dfrac {5}{4}$
To gain

$20$ %,

$SP = 1.2\times CP = \dfrac {120}{100}\times \dfrac {5}{4} = \dfrac {3}{2} \Rightarrow SP = \dfrac {3}{2}$
For

$Rs. 3/2$ number of articles sold

$= 6$
For

$Rs. 1$ number of articles to be sold

$= 6\times \dfrac {2}{3} = 4$ articles.

$5$ % more is gained by selling a watch for

$Rs. 350$ than by selling it for

$Rs. 340$ . The cost price of the watch is

0%
$Rs. 110$
0%
$Rs. 140$
0%
$Rs. 200$
0%
$Rs. 250$

Explanation

Let cost price be

$Rs. x$
Then

$5$ % of

$x = (350 - 340)$

$5$ % of

$x = 10$

$x = 10\times \dfrac {100}{5} = 200$
Hence, cost price is

$Rs. 200$ .

The cost

$C$ of sending a parcel post package weighing

$P$ gms,

$P$ an integer is

$Rs. 10$ for the first grams and

$Rs. 3$ for each additional grams. The formula for the cost is

0%
$C = 10 + 3P$
0%
$C = 10P + 3$
0%
$C = 10 + 3 (P - 1)$
0%
$C = 9 + 3P$
0%
$C = 10P - 7$

Explanation

For

$P - 1$ gms the charge is

$3$ rupees per grams. For the first gram the charge is

$10$ rupees.

$\therefore C = 10 + 3(P - 1)$ ; or
The charge for each gram is

$3$ rupees with an additional charge of

$7$ rupees for the first gram.

$\therefore C = 3P + 7 = 3P - 3 + 10 = 10 + 3(P - 1)$ .

A shop keeper earns a profit of

$12$ % on selling a book at

$10$ % discount on the printed price. The ratio of cost price to the printed price of the book is

0%
$45 : 56$
0%
$50 : 61$
0%
$99 : 125$
0%
None of these

Explanation

Using the formula

$\dfrac {100\pm (Profit\ Loss)}{100 - Discount} = \dfrac {M.P}{C.P}$

$\dfrac {M.P}{C.P} = \dfrac {112}{100 - 10} = \dfrac {112}{90} = \dfrac {56}{45}$
Hence,

$\dfrac {C.P}{M.P} = \dfrac {45}{56}$ .

The cost price of an article is

$x$ . It is marked up by

$150$ %. It is sold at Rs.

$600$ after giving

$40$ % discount. What is

$x$ (in Rs.)?

0%
$494.44$
0%
$666.66$
0%
$840$
0%
$942$

Explanation

Given that, the cost price of an article is

$Rs.\ x$ . It is marked up by

$150\%$ and sold at

$Rs.\ 600$ after a discount of

$40\%$ .

To find out: The value of

$x$ .

$C.P.=Rs.\ x$

Hence, marked price

$(M.P.)=150\% \ of\ x=Rs.\ 1.5x$

We know that,

$S.P.=\dfrac{100-\%\text{discount}}{100}\times M.P.$

$\therefore \ 600=\dfrac{100-40}{100}\times 1.5x$

$\Rightarrow \ 600=\dfrac{6}{10}\times 1.5x$

$\Rightarrow \ 1.5x=1000$

$\Rightarrow \ x=\dfrac{1000}{1.5}=\dfrac{10000}{15}$

$\therefore \ x=666.66$

Hence, the cost price of the article

$(x)$ is

$Rs.\ 666.66$ .

In case of compound interest, interest also earns interest.

0%
True
0%
False

Find the whole quantity if

$5\%$ of it is

$600$ .

0%
$3000$
0%
$6000$
0%
$12000$
0%
$15000$

Explanation

Given

$\dfrac{5}{100}$ of

$x=600$

$\implies x=\dfrac{600\times 100}{5}= Rs$

$12000$

A house and store were sold for

$\text{Rs. } 12,000$ each. The house was sold at a loss of

$20\%$ of the cost and the store at a gain of

$20\%$ of the cost. The entire transaction resulted in

0%
No loss or gain
0%
Loss of $\text{Rs. } 1000$
0%
Gain of $\text{Rs. } 1000$
0%
Gain of $\text{Rs. } 2000$
0%
None of these

Explanation

$12,000 = H - \dfrac {1}{5}H \therefore H = 15,000$

$12,000 = S + \dfrac {1}{5}S \therefore S = 10,000$

$H + S = 25,000$ .

Therefore, the sale resulted in a loss of

$Rs. 1000$ .

A housewife saved Rs.

$250$ in buying a dress on sale, If she spent Rs.

$25$ for the dress, she saved about:

0%
$80\%$
0%
$90.90\%$
0%
$89\%$
0%
$11\%$
0%
$12\%$

Explanation

The housewife saved

$250$ Rs and she spent

$25$ Rs on the dress.

$\Rightarrow$ Actual cost

$=275$

Saved percentage =

$\dfrac {250}{275}×100$

$\therefore$ saved percentage

$=90\%$

A shopkeeper allows a discount of

$10\%$ on the marked price of an item but charges a sales tax of

$8\%$ on the discounted price. If the customer pays

$Rs.680.40$ as the price including the sales tax, then what is the marked price of the item?

0%
Rs. $630$
0%
Rs. $700$
0%
Rs. $780$
0%
Rs. $680$

Explanation

Let marked price be

$Rs.x$

Price after discount of

$10\%=x-x\times \dfrac{10}{100}=\dfrac{9x}{10}$

Price after Tax

$=\dfrac{9x}{10}+\left(\dfrac{9x}{10}\times \dfrac{8}{100} \right)=\dfrac{972x}{1000}$

It is given that:

$\Rightarrow$

$\dfrac{972x}{1000}=680.40$

$\Rightarrow$

$x=\dfrac{680400}{972}$

$\therefore$

$x=Rs.700.$

$\therefore$ Marked price of the item is

$Rs.700$

A TV was bought at a price of Rs. 21,000. After one year the value of the TV was depreciated by 5%. (Depreciation means reduction of value due to use and age of the item). Find the value of the TV after one year.

0%
19,750
0%
17,950
0%
19,950
0%
19,000

Explanation

$\textbf{Step -1:Calculate the value to be deduced}.$

$\text{We are given that after one year, the value of the TV is depreciated by}$

$5\%.$

$\text{Value to be deduced =}$

$5$

$\text{% of}$

$Rs.21,000$

$=Rs.\dfrac{21000\times 5}{100}$

$=Rs.\: 1050$

$\textbf{Step -2:Calculate the value of the TV after one year}.$

$\text{Value after one year=}$

$Rs.(21000-1050)$

$=Rs.\: 19,950$

$\textbf{Hence, the correct option is C.}$

What would be the

$C.I$ obtained on an amount of

$12500$ at the rate of

$12$

$p.c.p.a.$ after

$2$ years?

0%
Rs. $3180$
0%
Rs. $3360$
0%
Rs. $3540$
0%
Rs. $3720$

Explanation

The formula of for compound interest is

$C.I. = P\left( 1+\cfrac{r}{100} \right)^{n}-P$

$=12,500 \left( 1+\cfrac{12}{100} \right)^{2}-12500$

$= 12500\times \frac{112}{100}\times \frac{112}{100}-12500$

$=3180$

$11$ Mango are bought for

$Rs.10$ and sold at

$10$ for

$Rs.11$ . What was Gain or Loss

$\%$ ?

0%
$24\%$
0%
$21\%$
0%
$26\%$
0%
$25\%$

What is the cost price of a pen if it is sold for Rs 60 gaining 20% profit?

0%
Rs 72
0%
Rs 50
0%
Rs 48
0%
Rs 40

The population of a city increases by 30% every year. If the present population is 3,38,What will the population of the city two years ago?

0%
3,00,000
0%
2,50,000
0%
3,50,000
0%
2,00,000

A wholesaler bought

$120$ watches for

$\text{Rs }30$ each. He sold

$50\%$ of the watches for

$\text{Rs }20$ each, one-third at

$\text{Rs }40$ each and the rest for

$\text{Rs }60$ . What was the wholesaler's approximate avenge profit per watch?

0%
$\text{Rs }3.3$
0%
$\text{Rs }5$
0%
$\text{Rs }7$
0%
$\text{Rs }9$
0%
$\text{Rs }11$

Explanation

C.P. of each watch

$=\text{Rs }30$ , number of watches

$=120$

total C.P.

$=30\times 120=\text{Rs }3600$

Wholesaler sold

$50\%$ (

$60$ watches) at

$\text{Rs }20$

S.P. of these

$60$ watches

$(S.P_1)=60 \times 20=\text{Rs }1200=$

$\left(\dfrac{1}{3}\right)^{rd}$ of

$120$ watches are sold at

$\text{Rs }40$

$S.P_2=40\times 40=\text{Rs }1600$

rest

$(120-60-40=20)$ watches are sold at

$\text{Rs }60$

$S.P_3=20\times 60=\text{Rs }1200$

Total S.P.

$=1200+1600+1200=\text{Rs }4000$

profit

$=$ S.P.

$-$ C.P.

$=4000-3600=\text{Rs }400$

Average profit per watch

$=\dfrac{400}{120}=\text{Rs }3.3$

The cost of a refrigerator is

$Rs. 9000$ . Its value depreciates at the rate of

$5\%$ every year. The total depreciation in its value at the end of

$2$ years

$877.5$

0%
True
0%
False

Explanation

Cost Price

$=9000$ , R

$=5\%$

Depreciation

$=\dfrac{R}{100}\times CP$

After

$1$ year

Depriciation

$=\dfrac{5}{100}\times 9000$

$=450$

After

$2$ years

Depreciation

$=\dfrac{5}{100}\times 8550$

$=427.5$

Total Depreciation

$=450+427.5=877.5$

Hence the statement is True.

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 9 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 9 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

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