MCQ Questions for Class 7 Maths Fractions And Decimals Quiz 5

Solve:

$2 \dfrac { 1 } { 2 } \mathrm { } \text { of } 10 \mathrm { cm }$

0%
30 cm
0%
25 cm
0%
20 cm
0%
50 cm

Explanation

Given

$2 \dfrac { 1 } { 2 } \mathrm { } \text { of } 10 \mathrm { cm }$

$=2\dfrac{1}{2}\times 10$

$=\dfrac{2\cdot2+1}{2}\times 10$

$=\dfrac{5}{2}\times 10$

$=5\times 5=25$

A proper fraction with denominator

$10$ is

0%
$\dfrac{8}{7}$
0%
$\dfrac{4}{7}$
0%
$\dfrac{6}{10}$
0%
$\dfrac{11}{7}$

Explanation

In a proper fraction numerator of the fraction is less than the denominator of the fraction. Also, the denominator must be

$10$ according to the question.

Hence, option

$C$ is correct.

Which one of the following is an improper fraction

0%
$\dfrac{11}{4}$
0%
$\dfrac{3}{8}$
0%
$\dfrac{3}{4}$
0%
$\dfrac{9}{11}$

Explanation

We have,

let,

$2\dfrac{3}{4}$

$=\dfrac{(4\times 2)+3}{4}$

$=\dfrac{8+3}{4}$

$=\dfrac{11}{4}$

Hence, this is answer.

The improper fraction is :

0%
$\dfrac { 12 }{ 15 }$
0%
$\dfrac { 13 }{ 17 }$
0%
$\dfrac { 16 }{ 21 }$
0%
$\dfrac { 25 }{ 11 }$

Explanation

A fraction in which the numerator is greater than the denominator is an improper fraction.

$(a)\dfrac{12}{15}:$ Here

$12<15\Rightarrow$ Numerator

$<$ Denominator.Hence it is not an improper fraction.

$(b)\dfrac{13}{17}:$ Here

$13<17\Rightarrow$ Numerator

$<$ Denominator.Hence it is not an improper fraction.

$(c)\dfrac{16}{21}:$ Here

$16<21\Rightarrow$ Numerator

$<$ Denominator.Hence it is not an improper fraction.

$(d)\dfrac{25}{11}:$ Here

$25>11\Rightarrow$ Numerator

$>$ Denominator.Hence it is an improper fraction.

State whether the following statements are true or false:
Every improper fraction can be converted into a mixed fraction.

0%
True
0%
False

Explanation

The given statement is true because every improper fraction can be converted into a mixed fraction.

For example:-

$\dfrac{{22}}{7} = 3\dfrac{1}{7}$

The product of

$\frac{11}{13}$ and 4 is:

0%
$3\frac {5}{13}$
0%
$5\frac{3}{13}$
0%
$13\frac{3}{13}$
0%
$13\frac{5}{13}$

$3.\overline{25}$ is equal to

0%
$2+\dfrac{25}{99}$
0%
$3+\dfrac{24}{99}$
0%
$3+\dfrac{25}{99}$
0%
$3+\dfrac{25}{98}$

Explanation

$3.\bar { 25 } =3+25*0.\bar { 01 } =3+25*\dfrac { 1 }{ 99 } =3+\dfrac { 25 }{ 99 }$

Solve :

$25 +\displaystyle{\frac{3}{100}}+\displaystyle{\frac{4}{1000}}=$ ?

0%
$25.34$
0%
$25.304$
0%
$25.034$
0%
$25.0034$

Explanation

The value of

$25$

$+$

$\displaystyle{\frac{3}{100}}$

$+$

$\displaystyle{\frac{4}{1000}}$ is

$=25+0.03+0.004$

$= 25.034$

Which of the following is a proper fraction ?

0%
0%
0%
0%
All the above

Explanation

Fraction is proper if the denominator is greater than the numerator.

Fraction is improper if the numerator is greater than or equal to the denominator.

fig A =

$\cfrac{4}{8}$ = proper fraction

fig B =

$\cfrac{6}{9}$ = proper fraction

fig C =

$\cfrac{1}{4}$ = proper fraction

Example for a proper fraction is

0%
$\displaystyle \frac {28}{13}$
0%
$\displaystyle \frac {11}{23}$
0%
$\displaystyle \frac {16}{9}$
0%
$\displaystyle \frac {14}{3}$

Explanation

Proper fraction is a fraction in which the numerator is less than the denominator, for example

$\dfrac {11}{23}$ .

Hence,

$\dfrac {11}{23}$ is a proper fraction.

$\displaystyle \frac{547.527}{0.0082}=x$ , then the value of

$\displaystyle \frac{547527}{82}$ is

0%
$\displaystyle \frac{x}{10}$
0%
$10x$
0%
$100x$
0%
$\displaystyle \frac{x}{100}$

Explanation

Given,

$\displaystyle \frac{547.527}{0.0082}=x$

$\displaystyle \Rightarrow \frac{547527\times 10000}{82\times 1000}=x$

$\displaystyle \Rightarrow \frac{5475270}{82}=x$

$\displaystyle \Rightarrow \frac{5475270}{82\times10}=\frac{x}{10}$

$\displaystyle \Rightarrow \frac{547527}{82}=\frac{x}{10}$

Hence,

$Op-A$ is correct.

The result of

$(54.327\times 357.2\times 0.0057)$ is the same as

0%
$5.4327\times 3.572\times 5.7$
0%
$5.4327\times 3.572\times 0.57$
0%
$54327\times 3572\times 0.0000057$
0%
$5432.7\times 3.572\times 0.000057$

Explanation

$54.327 \times 357.2 \times 0.0057 = \cfrac {54327}{1000} \times \cfrac {3572}{10} \times \cfrac {57}{10000}$

$= \cfrac {54327}{1000} \times \cfrac {10}{10} \times \cfrac {3572}{10} \times \cfrac {100}{100} \times \cfrac {57}{10000} \times \cfrac {1000}{1000}$

$= \cfrac {54327}{10000} \times 10 \times \cfrac {3572}{1000} \times 100 \times \cfrac {57}{10000} \times \cfrac {1000}{1000}$

$= 5.4327 \times 3.572 \times 5.7 \times 10 \times 100 \times \cfrac {1}{1000}$

$= 5.4327 \times 3.572 \times 5.7$

Hence, option A is correct.

$\displaystyle 4\frac{7}{11}$ =

$\displaystyle \frac{?}{11}$

0%
$44$
0%
$7$
0%
$51$
0%
$28$

Explanation

$\displaystyle 4 \frac{7}{11} = \frac{4 \times 11 + 7}{11} = \frac{51}{11}$

Expanded form of

$78.059$ is

0%
$78$ + $\displaystyle{\frac{5}{10}}$ + $\displaystyle{\frac{9}{100}}$
0%
$70 + 8 + 0 +$ $\displaystyle{\frac{5}{100}}$ + $\displaystyle{\frac{9}{1000}}$
0%
$70 + 8 +$ $\displaystyle{\frac{5}{10}}$ + $\displaystyle{\frac{9}{100}}$
0%
none

Explanation

Expanded form of

$78.059$ is

$70+ 8+\displaystyle \frac { 0 }{ 10 } +\frac { 5 }{ 100 } +\frac { 9 }{ 1000 }$

$\displaystyle\frac { 1 }{ 6.198 } = 0.16134$ , then the value of

$\displaystyle\frac { 1 }{ 0.0006198 }$ is.

0%
$16134$
0%
$1613.4$
0%
$0.16134$
0%
$0.016134$

Explanation

$\displaystyle\frac { 1 }{ 0.0006198 } = \displaystyle\frac { 1 }{ \displaystyle\frac { 6.198 }{ 10000 } } \\= \displaystyle\frac { 10000 }{ 6.198 } \\=10000\times\dfrac{1}{6.198}\\= 10000 \times 0.16134 \\= 1613.4$

$\displaystyle \frac { 2 }{ 4 }$ of a rupee = .......paise

0%
20
0%
50
0%
40
0%
10

Explanation

1 rupee=100 paise

$\dfrac{2}{4}$ of a rupee=

$\dfrac{2}{4}\times100=50$ paise

$58+\frac {3}{100}+\frac {7}{1000}= ......$

0%
58.0037
0%
58.37
0%
58.037
0%
none of these

Explanation

$58+\frac {3}{100}+\frac {7}{1000}$

$=58+\frac {0}{10}+\frac {3}{100}+\frac {7}{1000}=58.037$

$\displaystyle \frac { 1 }{ 6 }$ of 48 liter = ........ liter

0%
7
0%
1
0%
8
0%
6

Explanation

$\dfrac{1}{6}$ of 48 liter

$\dfrac{1}{6}\times$ 48 liter

=8 liter

$\displaystyle 3\frac{2}{5}=3+$ ____

0%
$\displaystyle \frac{3}{5}$
0%
$\displaystyle \frac{1}{5}$
0%
$\displaystyle \frac{2}{5}$
0%
$\displaystyle 3\frac{2}{5}$

Explanation

$3\dfrac{2}{5}$ can be written as

$\dfrac{17}{5}$ .

$\therefore \dfrac{17}{5}=\dfrac{15+2}{5}=3+\dfrac{2}{5}$

Hence, the answer is

$\dfrac{2}{5}$ .

Which of the following is not an improper fraction?

0%
$\cfrac {4}{3}$
0%
$\cfrac {3}{2}$
0%
$\cfrac {5}{3}$
0%
$\cfrac {7}{11}$

Explanation

Fractions that are greater than

$0$ but less than

$1$ are called proper fractions.

In proper fractions, the numerator is less than the denominator.

When a fraction has a numerator that is greater than or equal to the denominator, then the fraction is an improper fraction.

An improper fraction is always

$1$ or greater than

$1$ .

Now looking at options

$\dfrac{4}{3}=1.33 > 1$

$\dfrac{3}{2}= 1.5 > 1$

$\dfrac{5}{3}= 1.66 >1$

$\dfrac{7}{11}= 0.63 < 1$

$\dfrac{7}{11}$ is Not a Improper fraction.

So option

$D$ is correct.

Mixed fraction for

$\displaystyle \frac{39}{12}$ is

0%
$\displaystyle 3\tfrac{1}{12}$
0%
$\displaystyle 3\tfrac{2}{12}$
0%
$\displaystyle 3\tfrac{3}{12}$
0%
$\displaystyle 2\tfrac{14}{12}$

Explanation

To convert an improper fraction to a mixed fraction, we divide the numerator by the denominator, then write down the whole number answer.

Finally we write down any remainder above the denominator.

$39÷12=3$ leaving remainder

$3$

Therefore, the answer will be,

$3$ whole

$\dfrac {3}{12}$

Hence, the mixed fraction of

$\dfrac {39}{12}$ is

$3\dfrac {3}{12}$ .

Divide

$125.625$ by

$0.5$

0%
$251.25$
0%
$2512.5$
0%
$25125$
0%
$25.125$

$4\displaystyle \frac {7}{11}\, =\, \displaystyle \frac {?}{11}$

0%
44
0%
7
0%
51
0%
28

Explanation

$4\displaystyle \frac {7}{11}\, =\, \displaystyle \frac {4\, \times\, 11\, +\, 7}{11}\, =\, \displaystyle \frac {51}{11}$

Product of

$\displaystyle 3.92\times 0.1\times 0.0\times 6.3$ is:

0%
$0.392$
0%
$0.1176$
0%
$0$
0%
$6.3$

Explanation

We know if we multiply

$0$ by any number then result will be zero.

So the value of

$3.92\times .01\times 0.0\times 6.3=0$

Hence, the answer is

$0$ .

Example of improper fraction is ________

0%
$\displaystyle \frac{2}{3}$
0%
$\displaystyle \frac{1}{2}$
0%
$\displaystyle \frac{23}{22}$
0%
$\displaystyle \frac{11}{15}$

Explanation

When the numerator is greater than the denominator, it is called an improper fraction.

So only

$\dfrac{23}{22}$ is an improper fraction.

Hence, the answer is

$\dfrac{23}{22}$ .

Example of proper fraction is _________

0%
$\displaystyle \frac{5}{7}$
0%
$\displaystyle \frac{4}{3}$
0%
$\displaystyle \frac{16}{15}$
0%
$\displaystyle \frac{22}{21}$

Explanation

When the numerator is less than the denominator, it is called a proper fraction.

So only

$\dfrac{5}{7}$ is a proper fraction.

Hence, the answer is

$\dfrac{5}{7}$ .

$\displaystyle 1\frac{3}{4}$ is a _______ fraction.

0%
Proper
0%
improper
0%
mixed
0%
None of the above

Explanation

$1\dfrac{3}{4}$ is a mixed fraction because it has both integer and a proper fraction.

Hence, the answer is 'mixed'.

A grasshopper can jump up to 91.4 cm in a single jump. if the grasshopper jumped 731.2 cm altogether, how many jumps did it make ?

0%
17
0%
8
0%
9
0%
12

Explanation

Distance covered by grasshopper in one jump:

$91.4 cm$

Total distance covered by grasshopper:

$731.2 cm$

No. of jumps made =

$\dfrac{Total\quad distance \quad covered}{Distance\quad covered\quad in\quad one\quad jump}$

$\dfrac{731.2}{91.4}$

$8$ jumps

Find the product:

$\displaystyle 1\frac{1}{3}\times 3\frac{1}{4}\times \frac{7}{8}$

0%
$\displaystyle 3\frac{18}{24}$
0%
$\displaystyle 2\frac{19}{24}$
0%
$\displaystyle 3\frac{19}{24}$
0%
$\displaystyle 2\frac{18}{24}$

Explanation

Let's first convert the mixed fraction into simple fraction

$\dfrac{4}{3},$

$\dfrac{13}{4},$

$\dfrac{7}{8}$ .

The product is

$\dfrac{4}{3} \times \dfrac{13}{4}\times \dfrac{7}{8}=\dfrac{91}{24}$

This can also be written as

$3\dfrac{19}{24}$ .

Find the product:

$\displaystyle 16.89\times 1000$

0%
$1689$
0%
$16809$
0%
$16890$
0%
$168.9$

Explanation

To fnd

$16.89\times 1000$

Since,

$1000$ has

$3$ zeros and

$16.89$ has decimal point after

$2$ digits

So, the product will have no decimal points and zero at the end

Therefore, value of

$16.89\times 1000$ is

$16890$ .

CBSE Questions for Class 7 Maths Fractions And Decimals Quiz 5 - MCQExams.com

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Practice Class 7 Maths Quiz Questions and Answers

CBSE Questions for Class 7 Maths Fractions And Decimals Quiz 5 - MCQExams.com

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Practice Class 7 Maths Quiz Questions and Answers

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