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CBSE Questions for Class 7 Maths Fractions And Decimals Quiz 5 - MCQExams.com
CBSE
Class 7 Maths
Fractions And Decimals
Quiz 5
Solve: $$2 \dfrac { 1 } { 2 } \mathrm { } \text { of } 10 \mathrm { cm }$$
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30 cm
0%
25 cm
0%
20 cm
0%
50 cm
Explanation
Given $$2 \dfrac { 1 } { 2 } \mathrm { } \text { of } 10 \mathrm { cm }$$
$$=2\dfrac{1}{2}\times 10$$
$$=\dfrac{2\cdot2+1}{2}\times 10$$
$$=\dfrac{5}{2}\times 10$$
$$=5\times 5=25$$
A proper fraction with denominator $$10$$ is
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$$\dfrac{8}{7}$$
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$$\dfrac{4}{7}$$
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$$\dfrac{6}{10}$$
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$$\dfrac{11}{7}$$
Explanation
In a proper fraction numerator of the fraction is less than the denominator of the fraction. Also, the denominator must be $$10$$ according to the question.
Hence, option $$C$$ is correct.
Which one of the following is an improper fraction
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$$\dfrac{11}{4}$$
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$$\dfrac{3}{8}$$
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$$\dfrac{3}{4}$$
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$$\dfrac{9}{11}$$
Explanation
We have,
let, $$2\dfrac{3}{4}$$
$$=\dfrac{(4\times 2)+3}{4}$$
$$=\dfrac{8+3}{4}$$
$$=\dfrac{11}{4}$$
Hence, this is answer.
The improper fraction is :
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$$\dfrac { 12 }{ 15 } $$
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$$\dfrac { 13 }{ 17 } $$
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$$\dfrac { 16 }{ 21 } $$
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$$\dfrac { 25 }{ 11 } $$
Explanation
A fraction in which the numerator is greater than the denominator is an improper fraction.
$$(a)\dfrac{12}{15}:$$ Here $$12<15\Rightarrow$$Numerator $$<$$ Denominator.Hence it is not an improper fraction.
$$(b)\dfrac{13}{17}:$$ Here $$13<17\Rightarrow$$Numerator $$<$$ Denominator.Hence it is not an improper fraction.
$$(c)\dfrac{16}{21}:$$ Here $$16<21\Rightarrow$$Numerator $$<$$ Denominator.Hence it is not an improper fraction.
$$(d)\dfrac{25}{11}:$$ Here $$25>11\Rightarrow$$Numerator $$>$$ Denominator.Hence it is an improper fraction.
State whether the following statements are true or false:
Every improper fraction can be converted into a mixed fraction.
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0%
True
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False
Explanation
The given statement is true because every improper fraction can be converted into a mixed fraction.
For example:-
$$\dfrac{{22}}{7} = 3\dfrac{1}{7}$$
The product of $$\frac{11}{13}$$ and
4 is:
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$$3\frac {5}{13}$$
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$$5\frac{3}{13}$$
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$$13\frac{3}{13}$$
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$$13\frac{5}{13}$$
$$3.\overline{25}$$ is equal to
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$$ 2+\dfrac{25}{99} $$
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$$ 3+\dfrac{24}{99} $$
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$$ 3+\dfrac{25}{99} $$
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$$ 3+\dfrac{25}{98} $$
Explanation
$$3.\bar { 25 } =3+25*0.\bar { 01 } =3+25*\dfrac { 1 }{ 99 } =3+\dfrac { 25 }{ 99 } $$
Solve : $$25 +\displaystyle{\frac{3}{100}}+\displaystyle{\frac{4}{1000}}=$$ ?
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$$25.34$$
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$$25.304$$
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$$25.034$$
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$$25.0034$$
Explanation
The value of $$25 $$ $$+$$ $$\displaystyle{\frac{3}{100}}$$ $$+$$ $$\displaystyle{\frac{4}{1000}}$$ is
$$=25+0.03+0.004$$
$$= 25.034$$
Which of the following is a proper fraction ?
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0%
0%
0%
All the above
Explanation
Fraction is proper if the
denominator is
greater than the
numerator.
Fraction is improper if the
numerator is greater than or equal to
the
denominator.
fig A = $$\cfrac{4}{8}$$ = proper fraction
fig B = $$\cfrac{6}{9}$$ = proper fraction
fig C = $$\cfrac{1}{4}$$ = proper fraction
Example for a proper fraction is
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$$\displaystyle \frac {28}{13}$$
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$$\displaystyle \frac {11}{23}$$
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$$\displaystyle \frac {16}{9}$$
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$$\displaystyle \frac {14}{3}$$
Explanation
Proper fraction is a fraction in which the numerator is less than the denominator, for example $$\dfrac {11}{23}$$.
Hence,
$$\dfrac {11}{23}$$
is a proper fraction.
If $$\displaystyle \frac{547.527}{0.0082}=x $$, then the value of $$\displaystyle \frac{547527}{82}$$ is
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$$\displaystyle \frac{x}{10}$$
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$$10x$$
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$$100x$$
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$$\displaystyle \frac{x}{100}$$
Explanation
Given, $$\displaystyle \frac{547.527}{0.0082}=x $$
$$\displaystyle \Rightarrow \frac{547527\times 10000}{82\times 1000}=x $$
$$\displaystyle \Rightarrow \frac{5475270}{82}=x $$
$$\displaystyle \Rightarrow \frac{5475270}{82\times10}=\frac{x}{10} $$
$$\displaystyle \Rightarrow \frac{547527}{82}=\frac{x}{10} $$
Hence, $$Op-A$$ is correct.
The result of $$(54.327\times 357.2\times 0.0057)$$ is the same as
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$$5.4327\times 3.572\times 5.7$$
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$$5.4327\times 3.572\times 0.57$$
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$$54327\times 3572\times 0.0000057$$
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$$5432.7\times 3.572\times 0.000057$$
Explanation
$$54.327 \times 357.2 \times 0.0057 = \cfrac {54327}{1000} \times \cfrac {3572}{10} \times \cfrac {57}{10000}$$
$$= \cfrac {54327}{1000} \times \cfrac {10}{10} \times \cfrac {3572}{10} \times \cfrac {100}{100} \times \cfrac {57}{10000} \times \cfrac {1000}{1000}$$
$$= \cfrac {54327}{10000} \times 10 \times \cfrac {3572}{1000} \times 100 \times \cfrac {57}{10000} \times \cfrac {1000}{1000}$$
$$= 5.4327 \times 3.572 \times 5.7 \times 10 \times 100 \times \cfrac {1}{1000}$$
$$= 5.4327 \times 3.572 \times 5.7$$
Hence, option A is correct.
$$\displaystyle 4\frac{7}{11}$$ = $$\displaystyle \frac{?}{11}$$
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$$44$$
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$$7$$
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$$51$$
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$$28$$
Explanation
$$\displaystyle 4 \frac{7}{11} = \frac{4 \times 11 + 7}{11} = \frac{51}{11}$$
Expanded form of $$78.059$$ is
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$$78$$ + $$\displaystyle{\frac{5}{10}}$$ + $$\displaystyle{\frac{9}{100}}$$
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$$70 + 8 + 0 +$$ $$\displaystyle{\frac{5}{100}}$$ + $$\displaystyle{\frac{9}{1000}}$$
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$$70 + 8 +$$ $$\displaystyle{\frac{5}{10}}$$ + $$\displaystyle{\frac{9}{100}}$$
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none
Explanation
Expanded form of $$78.059$$ is $$70+ 8+\displaystyle \frac { 0 }{ 10 } +\frac { 5 }{ 100 } +\frac { 9 }{ 1000 } $$
If $$\displaystyle\frac { 1 }{ 6.198 } = 0.16134$$, then the value of $$\displaystyle\frac { 1 }{ 0.0006198 } $$ is.
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$$16134$$
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$$1613.4$$
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$$0.16134$$
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$$0.016134$$
Explanation
$$\displaystyle\frac { 1 }{ 0.0006198 } = \displaystyle\frac { 1 }{ \displaystyle\frac { 6.198 }{ 10000 } } \\= \displaystyle\frac { 10000 }{ 6.198 } \\=10000\times\dfrac{1}{6.198}\\= 10000 \times 0.16134 \\= 1613.4$$
$$\displaystyle \frac { 2 }{ 4 }$$ of a rupee = .......paise
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20
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50
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40
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10
Explanation
1 rupee=100 paise
so $$\dfrac{2}{4}$$ of a rupee=$$\dfrac{2}{4}\times100=50$$ paise
$$58+\frac {3}{100}+\frac {7}{1000}= ......$$
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58.0037
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58.37
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58.037
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none of these
Explanation
$$58+\frac {3}{100}+\frac {7}{1000}$$
$$=58+\frac {0}{10}+\frac {3}{100}+\frac {7}{1000}=58.037$$
$$\displaystyle \frac { 1 }{ 6 } $$ of 48 liter = ........ liter
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0%
7
0%
1
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8
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6
Explanation
$$\dfrac{1}{6}$$ of 48 liter
=
$$\dfrac{1}{6}\times$$
48 liter
=8 liter
$$\displaystyle 3\frac{2}{5}=3+ $$ ____
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$$\displaystyle \frac{3}{5}$$
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$$\displaystyle \frac{1}{5}$$
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$$\displaystyle \frac{2}{5}$$
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$$\displaystyle 3\frac{2}{5}$$
Explanation
$$3\dfrac{2}{5}$$ can be written as $$\dfrac{17}{5}$$.
$$\therefore \dfrac{17}{5}=\dfrac{15+2}{5}=3+\dfrac{2}{5}$$
Hence, the answer is $$\dfrac{2}{5}$$.
Which of the following is not an improper
fraction?
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$$\cfrac {4}{3}$$
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$$\cfrac {3}{2}$$
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$$\cfrac {5}{3}$$
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$$\cfrac {7}{11}$$
Explanation
Fractions
that are greater than $$0$$ but less than $$1$$ are called
proper fractions
.
In
proper fractions
, the numerator is less than the denominator.
When a
fraction
has a numerator that is greater than or equal to the denominator, then the
fraction
is an
improper fraction
.
An
improper fraction
is always $$1$$ or greater than $$1$$.
Now looking at options
$$\dfrac{4}{3}=1.33 > 1$$
$$\dfrac{3}{2}= 1.5 > 1$$
$$\dfrac{5}{3}= 1.66 >1$$
$$\dfrac{7}{11}= 0.63 < 1$$
So
$$\dfrac{7}{11}$$ is Not a Improper fraction.
So option $$D$$ is correct.
Mixed fraction for $$\displaystyle \frac{39}{12}$$ is
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$$\displaystyle 3\tfrac{1}{12}$$
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$$\displaystyle 3\tfrac{2}{12}$$
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$$\displaystyle 3\tfrac{3}{12}$$
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$$\displaystyle 2\tfrac{14}{12}$$
Explanation
To convert an improper fraction to a mixed fraction, we divide the numerator by the denominator, then write down the whole number answer.
Finally we write down any remainder above the denominator.
$$39÷12=3$$ leaving remainder $$3$$
Therefore, the answer will be, $$3$$ whole $$\dfrac {3}{12}$$
Hence, the mixed fraction of
$$\dfrac {39}{12}$$ is
$$3\dfrac {3}{12}$$.
Divide $$125.625$$ by $$0.5$$
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$$251.25$$
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$$2512.5$$
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$$25125$$
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$$25.125$$
$$4\displaystyle \frac {7}{11}\, =\, \displaystyle \frac {?}{11}$$
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0%
44
0%
7
0%
51
0%
28
Explanation
$$4\displaystyle \frac {7}{11}\, =\, \displaystyle \frac {4\, \times\, 11\, +\, 7}{11}\, =\, \displaystyle \frac {51}{11}$$
Product of $$\displaystyle 3.92\times 0.1\times 0.0\times 6.3$$ is:
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$$0.392$$
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$$0.1176$$
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$$0$$
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$$6.3$$
Explanation
We know if we multiply $$0$$ by any number then result will be zero.
So the value of $$ 3.92\times .01\times 0.0\times 6.3=0$$
Hence, the answer is $$0$$.
Example of improper fraction is ________
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$$\displaystyle \frac{2}{3}$$
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$$\displaystyle \frac{1}{2}$$
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$$\displaystyle \frac{23}{22}$$
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$$\displaystyle \frac{11}{15}$$
Explanation
When the numerator is greater than the denominator, it is called an improper fraction.
So only $$\dfrac{23}{22}$$ is an improper fraction.
Hence, the answer is $$\dfrac{23}{22}$$.
Example of proper fraction is _________
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$$\displaystyle \frac{5}{7}$$
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$$\displaystyle \frac{4}{3}$$
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$$\displaystyle \frac{16}{15}$$
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$$\displaystyle \frac{22}{21}$$
Explanation
When the numerator is less than the denominator, it is called a proper fraction.
So only $$\dfrac{5}{7}$$ is a proper fraction.
Hence, the answer is $$\dfrac{5}{7}$$.
$$\displaystyle 1\frac{3}{4}$$ is a _______ fraction.
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Proper
0%
improper
0%
mixed
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None of the above
Explanation
$$1\dfrac{3}{4}$$ is a mixed fraction because it has both integer and a proper fraction.
Hence, the answer is 'mixed'.
A grasshopper can jump up to 91.4 cm in a single jump. if the grasshopper jumped
731.2 cm altogether, how many jumps did it make ?
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0%
17
0%
8
0%
9
0%
12
Explanation
Distance covered by grasshopper in one jump: $$91.4 cm$$
Total distance covered by grasshopper: $$731.2 cm$$
No. of jumps made = $$\dfrac{Total\quad distance \quad covered}{Distance\quad covered\quad in\quad one\quad jump}$$
= $$\dfrac{731.2}{91.4}$$
= $$8$$ jumps
Find the product:
$$\displaystyle 1\frac{1}{3}\times 3\frac{1}{4}\times \frac{7}{8}$$
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$$\displaystyle 3\frac{18}{24}$$
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$$\displaystyle 2\frac{19}{24}$$
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$$\displaystyle 3\frac{19}{24}$$
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$$\displaystyle 2\frac{18}{24}$$
Explanation
Let's first convert the mixed fraction into simple fraction $$\dfrac{4}{3},$$ $$\dfrac{13}{4},$$ $$\dfrac{7}{8}$$ .
The product is
$$\dfrac{4}{3} \times \dfrac{13}{4}\times \dfrac{7}{8}=\dfrac{91}{24}$$
This can also be written as $$3\dfrac{19}{24}$$.
Find the product:
$$\displaystyle 16.89\times 1000$$
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$$1689$$
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$$16809$$
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$$16890$$
0%
$$168.9$$
Explanation
To fnd
$$16.89\times 1000$$
Since, $$1000$$ has $$3$$ zeros and $$16.89$$ has decimal point after $$2$$ digits
So, the product will have no decimal points and zero at the end
Therefore, value of $$16.89\times 1000$$ is $$16890$$.
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