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CBSE Questions for Class 7 Maths Fractions And Decimals Quiz 7 - MCQExams.com
CBSE
Class 7 Maths
Fractions And Decimals
Quiz 7
State true or false
$$3.68\times 5=18.4$$
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0%
True
0%
False
Explanation
Multiply $$3.68 \times 5$$
$$ = \dfrac{{368}}{{100}} \times 5$$
$$ = \dfrac{{1840}}{{100}}$$
=$$18.4$$
The sum of two numbers is $$31.021$$. If one of them is $$11.56$$, then the other number is _______ .
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$$19.461$$
0%
$$17.461$$
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$$18.641$$
0%
$$19.561$$
The product of $$3.92\times 0.1\times 0.0\times 6.3$$ is _______
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$$0.392$$
0%
$$0.1176$$
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$$0$$
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$$6.3$$
State true or false:
$$1.5\times 0.3 = 0.45$$
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0%
True
0%
False
Explanation
$$1.5\times 0.3 = \dfrac{15}{10}\times \dfrac{3}{10}$$
$$ = \dfrac{45}{100}$$
$$ = 0.45$$
Ans. True
If the numerator and denominator of a proper fraction are increased by the same quantity, then the resulting fraction is?
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Always greater than the original fraction
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Always less than the original fraction
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Always equal to the original fraction
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None of the above
Explanation
If the numerator and denominator of a proper fraction are increased by the same quantity, then the resulting fraction is always greater than the original fraction.
Let us understand and verify it with the help of couple of examples:
$$(i)$$ Let $$\dfrac{1}{2}$$ be an original fraction.
$$\dfrac{1}{2}=0.5$$
If the numerator and denominator are increased by $$5$$, the fraction becomes:
$$\dfrac{1+5}{2+5}=\dfrac{5}{7}=0.71$$
$$\therefore$$ $$\dfrac{1}{2}<\dfrac{5}{7}$$
$$(ii)$$ Let $$\dfrac{7}{9}$$ be an original fraction.
$$\dfrac{7}{9}\approx 0.78$$
If the numerator and denominator are increased by $$1$$, the fraction becomes:
$$\dfrac{7+1}{9+1}=\dfrac{8}{10}=0.8$$
$$\therefore$$ $$\dfrac{7}{9}<\dfrac{8}{10}$$
Hence, if the numerator and denominator of a proper fraction are increased by the same quantity, then the resulting fraction is always greater than the original fraction.
Therefore, option A is correct.
A $$8m$$ $$57cm$$ pole was put in a pond to measure its depth. If $$4m$$ $$66cm$$ of pole remained outside water, then depth of pond is _____ .
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$$3.91m$$
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$$3.00m$$
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$$3.45m$$
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$$3.23m$$
Evaluate: $$3.7-1.9$$
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$$0.6$$
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$$7.3$$
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$$3.4$$
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$$1.8$$
Explanation
$$3.7-1.9$$
$$=1.8$$
The simplification of $$33.6 - 2 { .05 } + 0.133$$ is equal to
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$$31.63$$
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$$29.643$$
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$$25. { 61 }3$$
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None of these
A proper fraction with denominator $$3$$ , which is less than 1 is
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$$\frac{4}{3}$$
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$$\frac{2}{3}$$
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$$1 \frac{2}{3}$$
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None
Explanation
Clearly from question denominator$$=3$$
numerator $$=2$$
Fraction $$=\dfrac{2}{3}$$
A fraction whose numerator is greater than its denominator is
fraction.
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an improper
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a proper
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a mixed
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None of these
Explanation
That will be an improper fraction
Ex $$\dfrac{6}{5}$$
Multiply $$\dfrac{6}{13}$$ by the reciprocal of $$\dfrac{-7}{16}$$
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$$\dfrac{-95}{91}$$
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$$\dfrac{-96}{91}$$
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$$\dfrac{96}{91}$$
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None of these
Explanation
Reciprocal of $$\dfrac{-7}{16}$$ is $$\dfrac{-16}{7}$$
Now $$\dfrac{6}{13}\times$$ Reciprocal of $$\dfrac{-7}{16}$$
$$=\dfrac{6}{13}\times\dfrac{-16}{7}$$
$$=\dfrac{6\times -16}{13\times 7}=\dfrac{-96}{91}$$
Solve the following equation
$$\dfrac25\times\dfrac{-3}7-\dfrac16\times\dfrac32+\dfrac1{14}\times\dfrac25$$
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$$7$$
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$$4$$
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$$\dfrac{-11}{28}$$
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$$\dfrac{4}{3}$$
Explanation
Given,
$$\dfrac{2}{5}\times \dfrac{-3}{7}-\dfrac{1}{6} \times \dfrac{3}{2}+\dfrac{1}{14} \times \dfrac{2}{5}$$
$$=-\dfrac{6}{35}-\dfrac{1}{4}+\dfrac{1}{35}$$
$$=-\dfrac{1}{7}-\dfrac{1}{4}$$
$$=\dfrac{-11}{28}$$
Simplify:
$$\displaystyle\frac{2.3\times2.3}{2.3\times2.3-2\times2.3\times2.3+2.3\times2.3+1}$$
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$$0$$
0%
$$3.24$$
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$$1.96$$
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$$5.29$$
Explanation
We have,
$$\dfrac { 2.3\times 2.3 }{ 2.3\times 2.3-2\times 2.3\times 2.3+2.3\times 2.3+1 } $$
$$\dfrac { 2.3\times 2.3 }{ 0+1 } $$
$$=2.3\times 2.3=5.29$$
Hence, this is the answer.
Mark against the correct answer in each of the following:
$$ ( 1.007 - 0.7) = ? $$
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$$ 1 $$
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$$ 0.37 $$
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$$ 0.307 $$
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None of these
Explanation
$$ 3.07 $$
First convert the given decimals into like decimals
$$ = (1.007 – 0.700)$$
$$ = 0.307 $$
$$5.2 - 3.6$$ is equal to
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$$0.16$$
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$$2.6$$
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$$0.26$$
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$$1.6$$
Explanation
$$5.2 - 3.6 = \dfrac{52}{10} - \dfrac{36}{10} $$
$$= \dfrac{16}{10}$$
$$=1.6$$
$$ \dfrac{11}{7} $$ can be expressed in the form
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$$ 7 \dfrac{1}{4} $$
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$$ 4 \dfrac{1}{7} $$
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$$ 1 \dfrac{4}{7} $$
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$$ 11 \dfrac{1}{7} $$
Explanation
Numbers of the type $$ 7 \dfrac{1}{4} , 4\dfrac{1}{7}, 1\dfrac{4}{7} , 11\dfrac{1}{7}$$…….. are called mixed fractions. A mixed fraction is a combination of whole and fractional parts.
To find a mixed fraction, divide: 11 by 7
$$ \dfrac{11}{7} = \dfrac{1 × 7 + 4}{7}$$
Where, 1 is the quotient and 4 is the remainder
A mixed fraction is written as $$Quotient \dfrac{remainder}{divisor}$$
$$\dfrac{11}{7}=1 \dfrac{4}{7}$$
$$\therefore \textbf{Option C is correct.}$$
$$ 15.8-6.73 $$ is equal to
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$$ 8.07 $$
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$$ 9.07 $$
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$$ 9.13 $$
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$$ 9.25 $$
Explanation
To subtract two decimals, convert 15.8 into like decimals with 2 decimal places,
$$15.8 =15.80$$
Now, subtracting decimals we get,
$$15.80 - 6.73 = 9.07$$
$$\therefore \textbf{Option B is correct.}$$
$$ 0.07 + 0.008 $$ is equal to
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$$ 0.15 $$
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$$ 0.015 $$
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$$ 0.078 $$
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$$ 0.78 $$
Explanation
To add two decimals, we need to convert 0.07 to 3 decimal places,
0.07 = 0.070
Now adding both the like decimals 0.070 and 0.008, we get
$$\therefore \textbf{Option (C) is correct}$$
The mixed fraction $$ 5 \dfrac{4}{7} $$ can be expressed as
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$$ \dfrac{33}{7} $$
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$$ \dfrac{39}{7} $$
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$$ \dfrac{33}{4} $$
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$$ \dfrac{39}{4} $$
Explanation
An improper fraction is obtained by adding the whole part with a fractional part of a mixed fraction.
$$ 5\dfrac{4}{7}$$ can be expressed into improper fraction as ,
$$ = \dfrac{ 5×7+4}{7}$$
$$ = \dfrac{35+4}{7} $$
$$ = \dfrac{39}{7}$$
$$\therefore \textbf{Option B is correct.}$$
The product of 7 and $$ 6\frac{3}{4}$$ is:
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$$42 \frac{1}{4}$$
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$$47\frac{1}{4}$$
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$$42\frac{3}{4}$$
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$$47\frac{3}{4}$$
$$ 42.28-3.19=39.09 \quad $$
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0%
True
0%
False
Explanation
$$ 42.28 - 3.19 = 39.09 $$
$$ 42.28 $$
$$ -3.19 $$
__________
$$ 39.09 $$
$$ 3.03+ 0.016=3.019 $$
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0%
True
0%
False
Explanation
$$ \Rightarrow 3.030 + 0.016 = 3.046 $$
$$ \Rightarrow 3.046 \neq 3.019 $$
State whether the following statements are true $$\left(T\right)$$ or false $$\left(F\right)$$:
A fraction in which the numerator is greater than is denominator is called an improper fraction
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0%
True
0%
False
Explanation
True
A fraction in which the numerator is greater than the denominator is called an improper fraction .
The product of $$0.03$$ and $$ 0.9$$ is:
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$$2.7$$
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$$0.27$$
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$$0.027$$
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$$0.0027$$
Explanation
We need to find the product of $$0.03$$ and $$0.9$$
$$0.03\times 0.9=0.027$$
Hence, the correct option is $$Op-C$$
$$24.58=2\times 10+4\times 1+5\times 10+8\times 100$$
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0%
True
0%
False
Explanation
False
$$RHS=2\times 10+4\times 1+5\times 10+8\times 100=20+4+50+800=874\\ LHS\neq RHS$$
$$329.25=3\times 10^{2}+2\times 10^{1}+9\times 10^{0}+2\times 10^{-1}+5\times 10^{-2}$$
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0%
True
0%
False
Explanation
True
$$RHS=3\times 10^{2}+2\times 10^{1}+9\times 10^{0}+2\times 10^{-1}+5\times 10^{-2}$$
$$=3\times 100+2\times 10+9\times 1+\dfrac{2}{10}+\dfrac{5}{10\times 10}$$
$$=3\times 100+2\times 10+9\times 1+0.2+0.05=329.25$$
Therefore, $$LHS=RHS$$
$$0.31$$ is greater than
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$$0.32$$
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$$0.30$$
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$$0.34$$
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$$0.33$$
$$5.462$$ is greater than
Report Question
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$$5.352$$
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$$5.468$$
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$$5.523$$
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$$5.469$$
$$1.461$$ is less than
Report Question
0%
$$1.462$$
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$$1.469$$
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$$1.490$$
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$$1.450$$
$$0.046$$ is less than
Report Question
0%
$$0.048$$
0%
$$0.045$$
0%
$$0.056$$
0%
$$0.050$$
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