A statement in which the values of two mathematical expressions are equal.

An expression that computes the values of variables.

MCQ Questions for Class 7 Maths Simple Equations Quiz 2

$12, a, 6, 8, 2, 14$
The average (arithmetic mean) of the numbers listed above is

$6$ . Calculate the value of

$a$ .

0%
$-36$
0%
$-6$
0%
$0$
0%
$6$
0%
$36$

Explanation

We know that average of a bunch of numbers is the sum of the numbers divided by how many numbers in the bunch.

We can set up an equation for the average from the given question,

$\Rightarrow \dfrac { 12+a+6+8+2+14 }{ 6 } =6$

$\Rightarrow \dfrac { 42+a }{ 6 } =6$

$\Rightarrow 42+a=36$

$\Rightarrow a=-6$

Sumeet guessed a number

$x$ and then he added

$30$ to it. Give the expression for double of it.

0%
$2(x+30)$
0%
$\dfrac{1}{2(x+30)}$
0%
$2x+30$
0%
$x+60$

Explanation

According to the question,
The expression is

$x+30$ .

$\therefore$ double of it will be

$2(x+30$ ).

So. option

$A$ is correct.

Frame the given statement into a mathematical expression: "Thrice of a number increased by

$150$ ."

0%
$150-x$
0%
$3x-150$
0%
$3x+150$
0%
None of these

Explanation

Let

$x$ be the required number.

$\therefore$ thrice of a number shall be

$\displaystyle 3\times x=3x$ .

According to the question, if it is increased by

$150$ ,

the number would be

$\displaystyle (3x+150)$ .

What is an equation?

0%
A statement in which the values of two mathematical expressions are equal.
0%
An expression that computes the values of variables.
0%
A mathematical expression.
0%
None of these

$3251+587+369-$ ?

$=3007$

0%
$1250$
0%
$1300$
0%
$1375$
0%
$1200$
0%
None of these

Explanation

$3251$ Let

$4207-x=3007$
+

$587$ Then,

$x=4207-3007=1200$
+

$369$
---------------

$4207$
---------------

Given that

$5x-2\left( 6+7x \right) =15$ , the value of

$x$ is

0%
$1\dfrac { 13 }{ 14 }$
0%
$1\dfrac { 8 }{ 19 }$
0%
$\dfrac { 1 }{ 3 }$
0%
$-3$

Explanation

In order to simplify :-

$5x-2(6+7x)=15$
Solving bracket first,

$-2(6+7x)$ =

$-12-14x$ ........ eq

$(1)$
using eq

$(1)$ ,

$5x-12-14x= 15$

$\Rightarrow 5x-14x= 15+12$

$\Rightarrow -9x = 27$

$\Rightarrow x =\dfrac{27}{-9}$

$\Rightarrow x = -3$
Option

$D$ is correct.

If the average of

$3, 4$ , and

$x$ is

$2$ , then find

$x$ .

0%
$-15$
0%
$-1$
0%
$-8$
0%
$-6$
0%
$-2$

Explanation

Given: The average of

$3,4$ and

$x$ is

$2$
we have to find

$x$

$\Rightarrow \dfrac { 3+4+x }{ 3 } =2$

$\Rightarrow 7+x=6$

$\Rightarrow x=-1$

$x$ is

$-1$

Hence, the answer is option

$B$ .

Find the value of

$p$ in the equation

$\dfrac{p}{9}-8=17$

0%
$225$
0%
$-225$
0%
$\dfrac{225}{9}$
0%
$\dfrac{9}{225}$

Explanation

$\frac { p }{ 9 } -8=17$

$\Longrightarrow\displaystyle \frac { p }{ 9 } =17+8$

$\Longrightarrow \dfrac { p }{ 9 } =25$
Now, multiplying both sides by

$9$ we get,

$\Longrightarrow\displaystyle \frac { p }{ q } \times 9=25\times 9=225$

$\Longrightarrow\displaystyle p=225$

Which of the following equations has

$x = 2$ as a solution?

0%
$x + 2 = 5$
0%
$x - 2 = 0$
0%
$2x + 1= 0$
0%
$x + 3 = 6$

Explanation

$\textbf{The value of the variable in an equation which satisfies the equation is called a solution to the}$

$\textbf{ equation.}$

Let us now try and check the value of

$x=2$ for all the four given equations
For option (A)

$\begin{aligned}&x+2=5 \\&2+2 \neq 5\end{aligned}$

$\textbf{ Does not satisfy}$

For option (B)

$\begin{aligned}&x-2=0 \\&2-2=0\end{aligned}$

$\textbf{ Satisfies.}$

For option (C)

$\begin{aligned}&2 x+1=0 \\&(2 \times 2)+1 \neq 0\end{aligned}$

$\textbf{ Does not satisfy}$

For option (D)

$\begin{aligned}&x+3=6 \\&2+3 \neq 6\end{aligned}$

$\textbf{ Does not satisfy}$

$\textbf{Clearly option B is correct as it gives us the Left hand side equal to the Right hand side.}$

Convert this statement in mathematical form.
Twice of remainder when 8 is subtracted from a number is 10.

0%
$2x-8=10$
0%
$2(x-8)=10$
0%
$\dfrac{2x}{8}=10$
0%
$2x-10=8$

Explanation

let number be

$x$ ,then remainder

$=x-8$

$2(x-8)=10$

The value of x in the equation

$5x - 35 = 0$ is:

0%
$2$
0%
$7$
0%
$8$
0%
$11$

Explanation

Given,

$5x-35=0$

Transpose

$35$ to R.H.S.,

$5x=35$

Divide throughout by

$5$

$\dfrac {5x}{5}=\dfrac {35}{5}$

$\Rightarrow x=7$

$12$ times a number is

$4$ less than the

$5$ times the number. Write an equation representing the statement given.

0%
$12x -4 = 5x$
0%
$12x+4 = 5x$
0%
$12+ 4x= 5$
0%
$12 -4x= 5$

Explanation

Let the number be

$x$

$\Rightarrow 12\times x=5\times x-4$

$\Rightarrow 12x+4=5x$

Three times the number is

$300$ . Convert this statement in mathematical form.

0%
$3x=100$
0%
$3+x=300$
0%
$3 =300+x$
0%
$3x=300$

Explanation

$3$ times the number is

$300.$

$\Rightarrow$ Let the number

$=x$

$\Rightarrow 3$ times the number

$=3x$

$\Rightarrow$ This is equal to

$3x=300.$

Hence, the answer is

$3x=300.$

If the mean of

$6, 8, 5, x$ and

$4$ is

$7$ , then the value of

$x$ is ______.

0%
$11$
0%
$12$
0%
$13$
0%
$14$

Explanation

Given, mean

$= 7$ and data is

$6,8,5,x,4$

Therefore,

$\dfrac {6+8+5+x+4}{5}$

$= 7$

$\Rightarrow$

$x + 23 = 35$

$\Rightarrow$

$x = 12$

The substraction of 3 from 2x is represent as

0%
2x-3
0%
3-2x
0%
2x+3
0%
$\frac{2x}{3}$

Explanation

Subtraction

$3$ from

$2x=2x-3$

Is this an equation

$21=z+11$

0%
$Yes$
0%
$NA$
0%
$No$
0%
$15$

Explanation

$21=z+11$ is a equation

$\dfrac{9}{5}$ is the solution of the equation

$4X-1=8$

0%
True
0%
False

Explanation

$4 \times \dfrac{9}{5}=8$

$\dfrac{36}{5}=8$
But,

$\dfrac{36}{5}\neq8$

Hence,

$\dfrac{9}{4}$ is the solution of the given equation, not the

$\dfrac{9}{5}$

State true (T) or false (F):

$x=5$ is a solution of the equation

$3x+2=13$ .

0%
True
0%
False

Explanation

Substituting

$x=5$ in the given equation, we get,

$3x+2=13$

$\Rightarrow 3\times 5+2=13\\ \Rightarrow 15+2=13\\ \Rightarrow 17=13$

which is not true.

Hence the given statement is false.

The graph of the linear equation

$3x + 5y = 15$ cuts the

$x-$ axis at the point

0%
(5, 0)
0%
(3, 0)
0%
(0, 5)
0%
(0, 3)

Explanation

For graph to cut x-axis;

we will substitute

$y=0$ in

$3x+5y=15$

as equation of x-axis is

$y=0$ .

So;

$3x+5(0) = 15$

$\Rightarrow 3x=15$

$\Rightarrow x = 5$

$\therefore$ Point is

$(x, o) = (5,0)$

$\boxed{\text{Hence, answer is (a)}}$

State weather the statement is true(T) or false (F):
In the equation

$3x-3=9$ , transposing

$-3$ to RHS, we get

$3x=9$ .

0%
True
0%
False

Explanation

False,

It is given that,

$3x-3=9$

$\Rightarrow 3x=9+3$ [Transposing

$-3$ to RHS]

$\Rightarrow 3x=12$ .

CBSE Questions for Class 7 Maths Simple Equations Quiz 2 - MCQExams.com

0:0:1

Practice Class 7 Maths Quiz Questions and Answers

CBSE Questions for Class 7 Maths Simple Equations Quiz 2 - MCQExams.com

0:0:1

Practice Class 7 Maths Quiz Questions and Answers

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