MCQExams
0:0:1
CBSE
JEE
NTSE
NEET
Practice
Homework
×
CBSE Questions for Class 7 Maths The Triangle And Its Properties Quiz 1 - MCQExams.com
CBSE
Class 7 Maths
The Triangle And Its Properties
Quiz 1
The pair of adjacent sides in the given quadrilateral is ___.
Report Question
0%
AB, BC
0%
AB, CD
0%
BC, AD
0%
None of these.
Which of the given figures is a quadrilateral?
Report Question
0%
0%
0%
0%
none of the above
AM is a median of a $$\triangle ABC$$. Which of the following is true?
Report Question
0%
AB + BM + MC > AC
0%
AB + BC + AM > AC
0%
AM + BC + CA > 2 AB
0%
None of these.
Which two triangles have $$\angle B$$ as common?
Report Question
0%
$$\triangle ABD \ and \ \triangle ADC$$
0%
$$\triangle ABD \ and \ \triangle ABC$$
0%
$$\triangle ABC \ and \ \triangle ADC$$
0%
None of these.
Some of the angles in the given figure are
Report Question
0%
$$\angle DBE$$
0%
$$\angle ACE$$
0%
$$\angle BDC$$
0%
$$\angle BCA$$
Identify all the triangles in the given figure.
Report Question
0%
ABC
0%
DEB
0%
BCD
0%
ADC
Following is pair of opposite sides in the given quadrilateral.
Report Question
0%
AB, BC
0%
BC, AD
0%
AB, CD
0%
BC, CD
The distance from A to town B is five miles. C is six miles from B. Which of the following could be the distance from A to C?
I. $$11$$
II. $$1$$
III. $$7$$
Report Question
0%
I only
0%
II only
0%
I and II only
0%
II and III only
0%
I, II and III
Write the correct answer of the following:
The median of a triangle divides it into two
Report Question
0%
triangles of equal area
0%
congruent triangles
0%
right triangles
0%
isosceles triangles
Explanation
The median of a triangle divides it into two triangles of equal area.
Hence, (a) is the correct answer.
A triangle with all 3 equal sides is called
Report Question
0%
isosceles
0%
equilateral
0%
scalene
0%
none of these
Explanation
An
equilateral triangle
is one in which all three sides and angles are equal.
So, $$B$$ is correct.
What is the name of the closed figure with four sides?
Report Question
0%
Hexagon
0%
Triangle
0%
Pentagon
0%
Quadrilateral
Explanation
A quadrilateral is a closed figure having four sides.
Therefore, $$D$$ is the correct answer.
The construction of a triangle ABC, given that BC = 3 cm is possible when difference of AB and AC is equal to :
Report Question
0%
3.2 cm
0%
3.1 cm
0%
3 cm
0%
2.8 cm
Explanation
Let the length of $$AB$$ be $$x$$ and $$AC$$ be $$y$$
A triangle can be formed if the sum of any two sides is greater then the third
$$\Rightarrow BC+AC>AB\\ \Rightarrow 3+AC>AB\\ \Rightarrow 3>AB-AC\\ \Rightarrow AB-AC<3$$
So only option $$D$$is correct.
In a right triangle, the square of the hypotenuse is $$x$$ times the sum of the squares of the other two sides. The value of $$x$$ is:
Report Question
0%
$$2$$
0%
$$1$$
0%
$$\dfrac12$$
0%
$$\dfrac14$$
Explanation
In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Its a standard pythagoras theorem for right angle triangles.
$$\mbox {Hyp}^2 = \mbox {Perpendicular}^2 + \mbox {Base}^2$$
Accordig to question we have
$$\mbox {Hyp}^2 = x(\mbox {Perpendicular}^2 + \mbox {Base}^2)$$
So on comparing the above two equations,
We get, $$x=1$$.
In $$\Delta ABC$$, if AB $$=$$ BC then :
Report Question
0%
$$\angle B > \angle C$$
0%
$$\angle A = \angle C$$
0%
$$\angle A = \angle B$$
0%
$$\angle A < \angle C$$
Explanation
In $$\triangle ABC$$ , $$AB=AC$$
$$\therefore$$ the triangle is isoceles.
In an isoceles triangle the angles opposite to equal sides are equal.
$$\therefore \angle A=\angle C$$
Find all the angles of an equilateral triangle.
Report Question
0%
$$60^{0},60^{0},60^{0}$$
0%
$$90^{0},30^{0},60^{0}$$
0%
$$90^{0},45^{0},45^{0}$$
0%
$$120^{0},30^{0},30^{0}$$
Explanation
Given, $$\triangle ABC$$ is an equilateral triangle. In an equilateral triangle all the angles are equal.
$$\angle A = \angle B = \angle C = x$$
Sum of angles = 180
$$\angle A + \angle B + \angle C = 180$$
$$x + x + x = 180$$
$$x = 60$$
Thus, $$\angle A = \angle B = \angle C = 60^{\circ}$$
In ABC, If BC=AB and $$\angle B = 80^{\circ}$$, then $$\angle A$$ is equal to:
Report Question
0%
$$80^{\circ}$$
0%
$$40^{\circ}$$
0%
$$50^{\circ}$$
0%
$$100^{\circ}$$
Explanation
$$BC=AB$$
$$\Rightarrow \angle A=\angle C$$ (As angles opposite to equal side are equal)
let thte angles be $$x$$ each.
Now by angle sum property
$$\angle A+\angle B+\angle C={ 180 }^{ \circ }\\ \Rightarrow x+{ 80 }^{ \circ }+x={ 180 }^{ \circ }\\ \Rightarrow 2x={ 180 }^{ \circ }-{ 80 }^{ \circ }\\ \Rightarrow 2x={ 100 }^{ \circ }\\ \Rightarrow x={ 50 }^{ \circ }\\ \therefore \angle A={ 50 }^{ \circ }$$
Find $$x$$ in the given figure.
Report Question
0%
$$80^{\circ}$$
0%
$$40^{\circ}$$
0%
$$160^{\circ}$$
0%
$$20^{\circ}$$
Explanation
Exterior angle of triangle is the sum of two interior opposite angles of triangle.
$$\Rightarrow x+{ 60 }^{ \circ }={ 100 }^{ \circ }\\ \Rightarrow x={ 100 }^{ \circ }-{ 60 }^{ \circ }\\ \Rightarrow x={ 40 }^{ \circ }$$
The exterior angle of a triangle is equal to the sum of two
Report Question
0%
Exterior angles
0%
Interior angles
0%
Interior opposite angles
0%
Alternate angles
Explanation
The exterior angle of a triangle is equal to the sum of two interior opposite angles.
Write the measure of each angle of an isosceles right-angled triangle.
Report Question
0%
$$45^o, 90^o \,\, and \,\, 45^o$$
0%
$$30^o, 90^o \,\, and \,\, 60^o$$
0%
$$60^o, 60^o \,\, and \,\, 60^o$$
0%
$$30^o, 120^o \,\, and \,\, 30^o$$
Explanation
Since, the angle is right angled isosceles triangle. One of the angles will be $$90^{\circ}$$. let the other two angles be $$x$$
Thus, sum of angles = 180
$$90 + x + x = 180$$
$$2x = 90$$
x = $$45^{\circ}$$
The measure of each angle is: $$45^{\circ}, 45^{\circ}, 90^{\circ}$$
Define Pythagoras theorem.
Report Question
0%
In a right angled triangle , square of a hypotenuse is not equal to the sum of the squares of two sides.
0%
In a right-angled triangle, the square of a hypotenuse is equal to the sum of the squares of the other two sides.
0%
In a right angled triangle , hypotenuse is equal to the sum of two sides.
0%
In a triangle , square of a side is equal to the square of another side.
Explanation
In a right angled triangle ,square of hypotenuse (longest side) is equal to the sum of squares of other two sides.
In $$\triangle ABC$$
$${ \left( AC \right) }^{ 2 }{ =\left( AB \right) }^{ 2 }+{ \left( BC \right) }^{ 2 }$$
In figure, if lines PQ and RS intersect at point T, such that $$\angle PRT=40^o, \angle RPT=95^o$$ and $$\angle TSQ=75^o$$, find $$\angle SQT$$.
Report Question
0%
$$20^o$$
0%
$$ 60^o$$
0%
$$30^o$$
0%
$$80^o$$
Explanation
In $$\triangle PRT$$
$$\angle PTS=\angle PRT+\angle RTP$$ (As exterior angle is equal to sum of interior opposite angles )
$$\Rightarrow \angle PTS={ 95 }^{ \circ }+{ 40 }^{ \circ }={ 135 }^{ \circ }$$
Now in $$\triangle SQT$$
$$\angle STQ=\angle SQT+\angle TSQ$$ (As exterior angle is equal to sum of interior opposite angles )
$$\Rightarrow { 135 }^{ \circ }=\angle SQT+{ 75 }^{ \circ }\\ \Rightarrow \angle SQT={ 135 }^{ \circ }-{ 75 }^{ \circ }={ 60 }^{ \circ }$$
The $${\triangle }$$ formed by BC =7.2 cm , AC =6 cm and $${\angle C}$$ = $${120^0}$$ is:
Report Question
0%
An acute angle $${\triangle }$$
0%
An obtuse angled $${\triangle }$$
0%
A right angled $${\triangle }$$
0%
None of these
Explanation
Given $$\angle C=120^{\circ}$$
Here one of the angles of the triangle is greater than $$90^{\circ}$$ . So the $$\triangle$$ is obtuse angled triangle.
Therefore option $$B$$ is correct.
If two angles in a triangle are $$40^o$$ and $$60^o$$, then the third angle is:
Report Question
0%
$$90^o$$
0%
$$80^o$$
0%
$$70^o$$
0%
$$60^o$$
Explanation
Let the third angle be $$x$$
We know, by angle sum property, the sum of all angles of a triangles is $$ 180^0$$.
$${ 40 }^{ \circ }+{ 60 }^{ \circ }+x={ 180 }^{ \circ }\\ { 100 }^{ \circ }+x={ 180 }^{ \circ }\\ \Rightarrow x={ 80 }^{ \circ }$$
One of the angles of a triangle is $$65^o$$. Find the remaining two angles, if their difference is $$25^o$$.
Report Question
0%
$$70^o, 45^o$$
0%
$$55^o, 40^o$$
0%
$$50^o, 85^o$$
0%
$$75^o, 40^o$$
Explanation
Let one angle be $$\angle x$$
$$\therefore$$ other angle is $$\angle x+25^o$$
Now,
We know, by angle sum property, the sum of all angles of a triangles is $$ 180^0$$.
$$\implies x+x+25^o+65^o=180^o$$
$$\implies 2x=180^o-90^o$$
$$\implies x=45^o$$
Thus, the angles are $$45^o$$ and $$70^o$$
The given road sign is an equilateral triangle. What is the measure of each angle?
Report Question
0%
$$45^\circ$$
0%
$$90^\circ$$
0%
$$60^\circ$$
0%
$$36^\circ$$
Explanation
In an equilateral triangle all the angles are equal . Let each angle be $$x$$
Now by angle sum property
$$x+x+x={ 180 }^{ \circ }\\ \Rightarrow 3x={ 180 }^{ \circ }\\ \Rightarrow x={ 60 }^{ \circ }$$
So option $$C$$ is correct.
For any triangle $$ABC$$, the true statement is
Report Question
0%
$${ AC }^{ 2 }={ AB }^{ 2 }+{ BC }^{ 2 }$$
0%
$$AC=AB+BC$$
0%
$$AC>AB+BC$$
0%
$$AC<\,AB+BC$$
Explanation
For any $$\triangle ABC$$, the sum of two sides must be greater than the third side.
Hence, $$AB + BC > AC$$.
Number of interior angles formed in a triangle are:
Report Question
0%
$$1$$
0%
$$2$$
0%
$$3$$
0%
$$4$$
Explanation
Number of interior angles formed in a triangle are $$3.$$
Here, $$m\angle A, m\angle B$$ and $$m\angle C$$ stand for measure of angle $$A,B$$ and $$C.$$
The sum of all exterior angles of a triangle is
Report Question
0%
$$360^o$$
0%
$$180^o$$
0%
$$540^o$$
0%
none of these
Explanation
$$\textbf{Step 1: Naming the angles of the triangle}$$
$$\text{Let the angles of the triangle be }x,\;y,\;\text{and }z$$
$$x+y+z=180^{\circ}$$
$$x+y=\text{Exterior angle A}$$
$$y+z=\text{Exterior angle B}$$
$$x+z=\text{Exterior angle C}$$
$$\textbf{Step 2: Finding sum of exterior angles}$$
$$\text{Sum of exterior angles}=x+y+y+z+x+z$$
$$=2x+2y+2z$$
$$=2(x+y+z)=2\times180=360^{\circ}$$
$$\textbf{Final Answer: The sum of all exterior angles of a triangle is }\mathbf{360^{\circ}}.$$
The triangle formed by $$BC = 5 \ cm, AC = 3 \ cm, AB = 5.8 \ cm$$ is:
Report Question
0%
a right angled $$\Delta $$
0%
an isosceles $$\Delta $$
0%
an equilateral $$\Delta $$
0%
a scalene $$\Delta $$
Explanation
Given three lengths of sides are different.
Also, the sides do not follow Pythagora's theorem.
So, it is a scalene triangle.
Option $$D$$ is correct.
In the given figure, XYZ is a/an_________triangle.
Report Question
0%
isosceles
0%
equilateral
0%
scalene
0%
none of these
Explanation
In the given $$\triangle XYZ,$$
$$XY = XZ = 8$$ cm
Since two sides are equal of the given triangle.
$$\therefore \triangle XYZ $$ is an isosceles triangle.
Option A is correct.
0:0:1
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
0
Answered
0
Not Answered
0
Not Visited
Correct : 0
Incorrect : 0
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)
Practice Class 7 Maths Quiz Questions and Answers
<
>
Support mcqexams.com by disabling your adblocker.
×
Please disable the adBlock and continue.
Thank you.
Reload page
