Explanation
In $$ \triangle ABD $$, we have sum of two sides $$>$$ third side $$ => AB + AD > BD $$ OR
$$ => AB + AD > BE + ED -- (1) $$Also, in $$ \triangle BCE $$, we have sum of two sides $$>$$ third side $$ => EB + EC > BC $$ ---- (2)Adding equations $$ 1, 2 $$ we get$$ => AB + AD + EB +EC > BE + ED +BC $$$$ => AB + AD + EC > ED + BC $$
But $$ EC = ED $$
Hence, $$ AB + AD > BC$$
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