MCQ Questions for Class 8 Maths Comparing Quantities Quiz 10

A trader allows successive discounts of $15\%$ and $10\%$ on the marked price of an article. If the marked price is $Rs. 100$ , what would be the selling price?

0%
$Rs.\ 76.50$
0%
$Rs.\ 75$
0%
$Rs.\ 80$
0%
$Rs.\ 77$

Explanation

Marked Price

$= Rs\ 100$

Price after

$15\%$ discount:

$15\%$ Discount

$= 0.15 x 100 = Rs\ 15$

Price after discount

$= 100 - 15 = Rs\ 85$

Price after

$10\%$ discount:

$10\%$ Discount

$= 0.10 x 85 = Rs\ 8.50$

Price after discount

$= 85 - 8.5 = Rs\ 76.50$

Hence, the selling price is

$Rs\ 76.50$

Brinda purchased

$18$ coats at the rate of Rs.

$1500$ each and sold them at a profit of

$6\%$ . If customer is to pay sales tax at the rate of

$4\%$ , how much will one coat cost to the customer and what will be the total profit earned by Brinda after selling all coats?

0%
Rs. $1520$
0%
Rs. $1550$
0%
Rs $1653.6$ and Rs. $1620$
0%
Rs. $1660$

Explanation

$\Rightarrow$

$Cost \ price \ (CP)=Rs.1500$

Profit

$=6\%$

$\Rightarrow$

$Selling \ Price \ (SP)=106\%\times Rs.1500=Rs.1590.........$ (without sales tax).

After

$4\%$ Sales tax ,

Net

$SP=104\% \ of \ Rs.1590=Rs.1653.6$

Net profit over

$18$ coats

$=(1590\times 18) - (1500 \times 18)=Rs.1620$ .

(Since sales tax is paid to government and not earned as a profit by Bindra).

A house and a shop were sold for Rs. 1 lakh each. In this transaction, the house sale resulted into 20% loss whereas the shop sale resulted into 20% profit. The entire transaction resulted in:

0%
no loss, no gain
0%
loss of Rs. $\dfrac{1}{12}$ lakh
0%
loss of Rs. $\dfrac{1}{18}$ lakh
0%
gain of Rs. $\dfrac{1}{24}$ lakh

The lebelled price of a cupboard is

$Rs. 6500$ . The shopkeeper sold it by giving

$5%$ discount on the labelled price and earned a profit of

$15%$ . What approximately is the cost price of the cupboard?

0%
$Rs. 5000$
0%
$Rs. 5350$
0%
$Rs. 5600$
0%
$Rs .5800$
0%
$Rs .6000$

If Aparna got Rs.25 discount on purchasing a book for Rs.225, then the discount percentage is :

0%
12%
0%
11%
0%
10%
0%
9%

Explanation

Price of the book

$= Rs. 225$

Discount

$Rs. 25$

Actual price

$= Rs. \left( 225 + 25 \right) = Rs. 250$

Discount

$\% = \cfrac{25}{250} \times 100 = 10 \%$

Hence the discount percentage is

$10 \%$ .

Hence the correct answer is

$\left( C \right) 10 \%$ .

The market price of a mixer is

$2300$ rupees. A customer purchased it for

$Rs.1955$ . Find percentage of discount offered to the customer.

0%
$67.26\%$
0%
$10.26\%$
0%
$55.26\%$
0%
$13.26\%$

Explanation

Let the Discount amount be

$x$ ,

Market price

$=Rs. \ 2300$

Selling price

$=Rs.\ 1995$

Market price

$=$ selling price

$(1-\dfrac{x}{100})$

$\Rightarrow 2300-\dfrac{x}{100}\times2300=1995$

$\Rightarrow 2300-1995=23x$

$\Rightarrow x=13.26$

Hence, discount percentage

$=13.26$ %

$12$ Copies of book were sold for

$Rs. 1800$ thereby gaining cost price of

$3$ copies. The cost price of a copy of the book is

0%
$Rs. 120$
0%
$Rs. 150$
0%
$Rs. 1200$
0%
$Rs. 1500$

Explanation

Let Cost price of

$1$ book

$=x$

Selling price of

$12$ books

$=Rs.1800$

Gain

$=3x$

Selling price of

$12$ book -Cost price of

$12$ books = Gain

$1800-12x=3x$

$1800=12x+3x$

$1800=15x$

$x=120$

$\therefore$ Cost of

$1$ book

$=Rs\ 120$

If market price of a article is

$Rs.1900$ , and selling price is

$Rs.1750$ , then find the discount percentage.

0%
$9.78\%$
0%
$5.09\%$
0%
$6.89\%$
0%
$7.89\%$

Explanation

Given,

Marked price

$=Rs.1900$

Selling price

$=Rs.1750$

$Discount\%=\dfrac{Marked\ Price -\ Selling\ Price}{Marked \ price}\times 100\%$

$\Rightarrow Discount\%=\dfrac{1900 -1750}{1900}\times 100\%$

$\Rightarrow Discount\%=\dfrac{150}{1900}\times 100\%$

$\Rightarrow Discount\%=7.89$ %

If selling price =

$Rs.900$ . Discount is

$20\%$ , then find the market price.

0%
$Rs.\ 1005$
0%
$Rs.\ 1025$
0%
$Rs.\ 2125$
0%
$Rs.\ 1125$

Explanation

Let the market price be

$x$ ,

According to question, Discount is

$20$ %,

So,

$x-\dfrac{20}{100}x=SP$

$\implies \dfrac{4x}{5}=900$

$\implies x=1125$

Hence , Market Price

$=Rs.\ 1125$

Ram purchases a chair at

$Rs.70$ and spent

$Rs.17$ on its repair and

$50$ paise on cartage. If he sold the chair at

$Rs.100$ then his approximate margin of profit will be ?

0%
$13.30$ %
0%
$11.25$ %
0%
$12.5$ %
0%
$14.3$ %

Explanation

$Profit ~\%=\dfrac{SP-CP}{CP}\times100$

$=\dfrac{100-87.5}{87.5}\times100$

$=14.3\%$

A steno-typist deposits Rs.

$10,000$ in a bank for a period of

$3$ years at

$12$ % per annum compound interest. The interest accrued to her after maturity will be

0%
$Rs. 3600$
0%
$Rs. 4029$
0%
$Rs. 4032$
0%
$Rs. 4049.28$

The cost price of

$20$ articles is the same as the selling price of X articles. If the profit is

$25$ %, then the value of X is :

0%
$Rs.15$
0%
$Rs.16$
0%
$Rs.18$
0%
$Rs.25$

Explanation

Let the Cost price for one article be

$CP$

The Cost price of

$20$ articles is

$20CP$

The Selling price be

$SP$

The Selling price is

$X\times SP$

According to the question

$20CP=X\times SP\cdots(1)$

The profit is

$25\%$

$\implies$ Profit is

$\dfrac{25}{100}\times CP=\dfrac {CP}4$

$\implies SP-CP=\dfrac{CP}4$

$4SP-4CP=CP$

$4SP=5CP\cdots(2)$

Dividing

$(1)$ with

$(2)$

$$\dfrac{20CP}{5CP}=\dfrac{X\times SP}{4SP}

$\implies 4=\dfrac{X}4$

$\implies X=16$

What would be the C.I. obtained on an amount of Rs.

$12000$ at the rate of

$9$ p.c.p.a for

$3$ years?

0%
Rs. $3840$
0%
Rs. $3540.348$
0%
Rs. $3540$
0%
Rs. $3640$

Explanation

Given:

$P=12000$

$R=9\%$

$F=n=3\ year$

$A=P \left (1+\dfrac {R}{100}\right)^n$

$=12000 \left (1+\dfrac {9}{100}\right)^3$

$=12000 \left (\dfrac {109}{100}\right)^3$

$=12000\times \dfrac {109}{100}\times \dfrac {109}{100}\times \dfrac {109}{100}$

$A=15540.348$

C.I.

$=A- P$

C.I.

$=15540.348-12000$

C.I

$=$ Rs.

$3540.348$

Hence option (B) is the correct option

$A$ is

$150$ % of

$B$ then

$B$ is what percent of

$A+B$ ?

0%
$30$ %
0%
$35$ %
0%
$40$ %
0%
$45$ %

Explanation

$A=\dfrac{150}{100}B$

$A+B=\dfrac{150}{100}B+B=\dfrac{250}{100}B=2.5B$

B is

$\dfrac{B}{A+B}\% of A+B$

$\dfrac{1}{2.5}\times100$

$=40\%$

Option C is correct

If the cost of transporting

$150$ kg of goods for

$120$ km is Rs

$50.$ what will be the cost of transporting

$180$ kg of goods for

$300$ km?

0%
Rs. $110$
0%
Rs. $200$
0%
Rs. $180$
0%
Rs. $150$

Explanation

Cost of transporting $150\ kg$ over $120\ km=50$

Cost of transporting $1\ kg$ over $1\ km=\dfrac{50}{(150\times 130)}$

Cost of transporting $180\ kg$ over $300\ km=\dfrac{50}{(150\times 130)}\times (180\times 300)=Rs.150$

The population of a town in

$2009$ was

$125000$ . It increase

$10\%$ per year. What is the population after

$3$ years?

0%
$166375$
0%
$170000$
0%
$125000$
0%
$10000$

Explanation

Taking

$P$ as the population of the town in

$2009$ ,

$n$ is the number of years after which the population is to be calculated and

$R$ is the rate at which the population increases, then:

Population after

$3$ years

$= P \left(1 + \dfrac{R}{100}\right)^{n}$

$= 12500 \left(1 + \dfrac{10}{100}\right)^{3}$

$= 12500 \left(1 + \dfrac{1}{10}\right)^{3}$

$= 12500 \left( \dfrac{11}{10}\right)^{3}$

$= 12500 \times \dfrac{1331}{1000}$

$= 16,637.5$

Ram, Karan and Rohan invested capital in the ratio of

$2 : 3 : 4$ for time period of

$6 : 4 : 3$ . Find the ratio of profit distributed?

0%
$12 : 13 : 14$
0%
$13 : 12 : 14$
0%
$1 : 1 : 1$
0%
$14 : 12 : 13$

Explanation

Profit depends on total amount invested.

amount invested by Ram =

$2\times6 = 12k$

amount invested by Karan =

$3\times 4 = 12k$

amount invested by Rohan =

$4\times 3 = 12k$

As amount total invested is same in all three cases hence profit distributed will be same and is

$1 : 1 : 1$

The population of Mumbai increase

$5\%$ per annum, its population was

$1000000$ in

$2004$ . What was it's population after

$3$ year?

0%
$1157625$
0%
$123575$
0%
$132557$
0%
$11000$

Explanation

Population after

$3$ years

$= P\left(1 + \dfrac{r}{100}\right)^{n}$

$= 1000000\left(1 + \dfrac{5}{100}\right)^{3}$

$= 1000000\left(1 + \dfrac{1}{20}\right)^{3}$

$= 1000000\left( \dfrac{21}{20}\right)^{3}$

$= 1000000 \times \dfrac{9261}{8000}$

$= 1157625$

If Rs

$2800$ is

$\dfrac{2}{7}th$ of the value of a house, the worth of the house (in Rs ) is?

0%
$8,00,000$
0%
$9800$
0%
$10,00,000$
0%
$12,00,000$

Explanation

let the worth of the house be

$x$

Given that

$\dfrac {2}{7}$ of value of house is

$2800$

$\dfrac {2}{7}x=2800$

$x=2800\times \dfrac {7}{2}$

$=1400\times 7$

$Rs. 9800$

Worth of house

$=Rs. 9800$

At what prices should a shopkeeper mark a radio that costs him Rs 1200 in order that he may offer a discount of 20% on the marked price and still make a profit of 25%

0%
RS 1675
0%
- RS 1875
0%
RS 1900
0%
RS 2025
0%
None of these

Explanation

Given: Cost price

$=$ Rs.

$1200$

Profit

$\%=25$

$\therefore$ Selling price

$=125\%$ of

$1200$

$=\dfrac{125}{100}\times 1200$

$=$ Rs.

$1500$

Let the marked price be

$x$

and discount is of

$20\%$ [Given]

$\Rightarrow 80\%$ of

$x=1500$

$\Rightarrow \dfrac{80}{100}\times x=1500$

$\Rightarrow x=\dfrac{1500\times 100}{80}$

$\Rightarrow x=1875$

Hence the marked price should be

$Rs.1875$

Which of the following is the most beneficial customer?

0%
A discount of 40%
0%
Two successive discounts of 20% each
0%
A discount followed by a 30% discount.
0%
A discount followed by a 10% discount.

Explanation

More the discount more it is beneficial Let

$x$ be the cost price of article.

$2$ successive discount

$\rightarrow \dfrac{20}{100}\times \left[\dfrac{20}{100}x\right]\rightarrow \left[\dfrac{x}{25}\right]$

$40\%$ at a time discount

$\rightarrow \dfrac{40}{100}x\rightarrow \left[\dfrac{2x}{5}\right]\rightarrow \left[\dfrac{10x}{25}\right]$

$\therefore b \,discount >a\,discount$

The owner of a toy shop charges his customer

$33$ % more then the cost price. If the customer paid Rs.

$4921$ for a toy, then what was the cost price of the toy?

0%
Rs. $3850$
0%
Rs. $3700$
0%
Rs. $3550$
0%
Rs. $3900$

Explanation

Let cost price of the toy

$=x$

Owner will change

$=x+ \dfrac{33}{100} \times x$

$=494$

$4921=\dfrac{133}{100}x$

$x=\dfrac{4921 \times 100}{133}$

$x=3700\ Rs$

Calculate the amount and compound interest on
(i) INR

$10800$ for

$3$ years at

$12\dfrac{1}{2}\%$ per annum compounded annually .

0%
$4555.25$
0%
$4050.42$
0%
$4577.34$
0%
$4566.20$

Explanation

The amount after

$n$ years compounded annually is given as,

$A=P\left(1+\dfrac{r}{100}\right)^n$

Where,

$P=$ Principal

$r=$ rate of interest

According to the given condition,

Amount After three years

$=10800\left({1}+{\dfrac{12.5}{100}}\right)^3$

$=10800\left (\dfrac{112.5}{100}\right)^3\\$

$=15377.34$

compound interest

$=15377.34-10800$

$=Rs\ 4577.34$

If a mobile costs Rs.

$2786$ , then

$257$ mobiles costs?

0%
Rs. $716002$
0%
Rs. $4279$
0%
Rs. $72002$
0%
Rs. $716232$

Explanation

The cost of

$1$ mobile phone is

$Rs. 2786$

$\Rightarrow$ The cost of

$257$ mobile phone are

$Rs \left( 257\times 2786\right)$

$=Rs. 7,16,002$

Hence, the answer is

$Rs. 7,16,002.$

Rani bought a piece of cloth for

$Rs.950$ and spend

$Rs.300$ on designing it. At what price should she sell it to make

$30$ % profit?

0%
$1525$
0%
$1625$
0%
$1600$
0%
$1500$

Explanation

Total price of cloth

$= 950 + 300$

$= Rs. 1250$

Let she sell in

$Rs. x$

$Profit = \dfrac {x - 1250}{1250} \times 100 = 30$

$10x = 13\times 1250$

$x = 1625$ .

The owner of an electronics shop charges his customer

$22$ % more then the cost price. If a customer paid

$Rs.10980$ for a DVD player then what was the cost price of a DVD player?

0%
$Rs. 8000$
0%
$Rs.8800$
0%
$Rs.9500$
0%
$Rs.9000$

Explanation

Let the cost price of DVD player

$=x$

owner will take

$=x+\dfrac{22}{100}\times x$ from the customer,

According to the question;

$\left(x+\dfrac{22}{100}x\right)=10980$

$\dfrac{122}{100}x=10980$

$x=\dfrac{10980\times 100}{122}$

$x=9,000 =$ Cost price of DVD player

To get

$55\%$ of a number, the number should be multiplied by

0%
$\dfrac {11}{20}$
0%
$3.5$
0%
$\dfrac {7}{50}$
0%
$0.035$

Rice costing rs

$480$ is needed for

$8$ member for

$20$ days. What is the cost of the rice required for

$12$ members for

$15$ days

0%
$240$
0%
$540$
0%
$440$
0%
$520$

Explanation

Rice cost for $8$ members for $20$ days= $480$ rs

$8$ members for $1$ day = $480/20=24$

$1$ member for $1$ day = $24/8=3$

$12$ members for $1$ day = $12 \times 3=36$

$12$ members for $15$ days = $36 \times 15=540$

Cost of rice required for

$12$ members for

$15$ days = Rs

$540$

Three hundred oranges were bought at Rs.40 per dozen and sold at a profit of Rs.The selling price of the oranges per dozen is

0%
Rs. 41.50
0%
Rs. 41
0%
Rs. 45
0%
Rs. 42.50

Explanation

Let the selling price of the oranges per dozen

$= x$

profit for selling one dozen oranges

$= S.P - C.P=(x - 40)$

$300$ oranges

$= 25$ dozen orange

profit for

$25$ dozen

$= 25 (x - 40)$

$25 = 25(x - 40)$

$1 = x - 40$

$x = 41$

Amit invested an amount of Rs.25000 in fixed deposit @C.I. 8% per annum for 2 years. What amount Amit will get?

0%
Rs. 28240
0%
Rs. 28540
0%
Rs. 29240
0%
Rs. 29160

A shopkeeper purchased

$20$ dozen bananas for

$\text{Rs }\,208$ , Four dozen of the bananas were rotten. At what price per dozen must he sell the remaining bananas so that he is neither at a loss nor at a profit?

0%
$\text{Rs }\ 13$
0%
$\text{Rs }\ 9$
0%
$\text{Rs }\ 11$
0%
$\text{Rs }\ 17$

Explanation

Cost of

$20$ dozen bananas

$=\text{Rs }208$

Remaining bananas

$=$ Total bananas

$-$ rotten bananas

$=20-4=16$ dozens

let the selling price of 1 dozen bananas be

$x$

as per the question,

$16$ dozen bananas are required to be sold at

$\text{Rs }208$

$\implies 16x=208$

$\implies x=13$

Hence, the remaining bananas are to be sold at

$\text{Rs 13}$ per dozen

A shopkeeper sells 20 article for Rs. 6000 and earns profit equal to the selling price of 5 articles. Find the cost price of each articles?

0%
$200$
0%
$225$
0%
$325$
0%
$400$

Explanation

Given that,

A shopkeeper sells

$20$ articles for

$Rs.\ 6000$ .

He earns of profit equal to the selling price of

$5$ articles.

To find out,

The cost price of each article.

Selling price of

$20$ articles

$=Rs.\ 6000$

Hence, the selling price of one article

$=\dfrac{6000}{20}$

$=Rs.\ 300$

Hence, profit

$=$ selling price of

$5$ articles

$=5\times 300$

$=Rs.\ 1500$

We know that,

$C.P.=S.P.-\ profit$

Hence, the cost price of

$20$ articles

$=Rs.\ 6000-Rs.\ 1500$

$=Rs.\ 4500$

So, the cost price of one article

$=\dfrac{4500}{20}$

$=Rs.\ 225$

Hence, the cost price of each article is

$Rs.\ 225$ .

The compound interest on

$Rs.5,000$ at

$4\%$ per annum for

$2$ years compounded annually will be

0%
$Rs.806$
0%
$Rs.708$
0%
$Rs.5,408$
0%
$Rs.408$

Explanation

Given,

$P=5000$

$R=4\%$

$T=2\ years$

Amount

$A=P\Big(1+\dfrac{R}{100}\Big)^T$

$A=5000\Big(1+\dfrac{4}{100}\Big)^2$

$=5000\times\Big(\dfrac{104}{100}\Big)^2$

$=Rs. 5408$

Compound interest

$=A-P$

$=5408-5000=Rs. 408$

$10$ cylindrical pillars of building have to be painted.If the diameter of each pillar is

$50$ m and the height is

$4$ m.Find the cost of painting at the rate of Rs.

$7$ per square metre.

0%
Rs. $44,000$
0%
Rs. $4400$
0%
Rs. $440$
0%
Rs. $44$

Explanation

Diameter of the pillar

$=50$ m

Radius

$=25$ m

Height

$=4$ m

$\therefore$ Curved surface area of a pillar

$=2\pi rh=2\times\dfrac{22}{7}\times 25\times 4$

Curved surface area of

$10$ pillars

$=2\times\dfrac{22}{7}\times 25\times 4\times 10$

Cost of painting

$=$ Rs.

$7$ per sq.m

$\therefore$ Total cost of painting

$10$ pillars

$=2\times\dfrac{22}{7}\times 25\times 4\times 10\times 7$

$=$ Rs.

$44,000$

To gain

$25\%$ after allowing a discount of

$10\% ,$ the shopkeeper must mark the price of the article which costs him

$Rs 360$ as :

0%
Rs. $500$
0%
Rs. $450$
0%
Rs. $460$
0%
Rs. $486$

Explanation

The correct answer is option (a).
Suppose, the marked price of the article

$=Rs. x$ .
Cost price of the article

$=Rs. 360$
As per question,

$x-x\times \dfrac{10}{100}-\dfrac{25\times 360}{100}=360$
or

$x-\dfrac{x}{10}-90=360$
or

$\dfrac{9x}{10}-90=360$
or

$\dfrac{9x}{10}=360+90$
So,

$x=Rs. 500$

The population of a particular area of a city is

$5000$ . It increases by

$10 \%$ in

$1^{st}$ year. It decreases by

$20 \%$ in the

$2^{nd}$ year because of some reason. In the

$3^{rd}$ year, the population increases by

$30 \%$ . What will be the population of area at the end of

$3$ years?

0%
$5120$
0%
$5300$
0%
$5720$
0%
$5620$

Explanation

Population of a city at the starting of first year

$=5000$

It increases by

$10\%$ in

$1^{st}$ year.

i.e., Population at the end of

$1^{st}$ year

$=$ Population at the starting of

$2^{nd}$ year

$=5000+10\%\space of\space5000\\=5000+\dfrac{10}{100}\times5000\\=5500$

It decreases by

$20\%$ in

$2^{nd}$ year.

i.e., Population at the end of

$2^{nd}$ year

$=$ Population at the starting of

$3^{rd}$ year

$=5500-20\%\space of\space5500\\=5500-\dfrac{20}{100}\times5500\\=5500-1100\\=4400$

It increases by

$30\%$ in

$3^{rd}$ year.

i.e., Population at the end of

$3^{rd}$ year

$=4400+30\%\space of\space4400\\=4400+\dfrac{30}{100}\times4400\\=4400+1320\\=5720$

So,

$\text{C}$ is the correct option.

The cost price of a car is

$Rs. \,4,00,000$ . If its price decreases by

$10 \%$ every year, then when will be the cost of car after

$3$ years?

0%
$Rs. \,3,00,000$
0%
$Rs. \,2,91,700$
0%
$Rs. \,2,91,600$
0%
$Rs. \,2,50,000$

Explanation

Cost price of car

$(P)=\mathrm{Rs.}\space4,00,000$

Rate of depreciation

$(R)=10\%$

Time

$(T)=3\space\text{years}$

So, Cost of car after

$3\space\text{years}=P(1-\frac{R}{100})^T$

$=4,00,000(1-\frac{10}{100})^3$

$=4,00,000(1-0.1)^3$

$=4,00,000(0.9)^3$

$=4,00,000\times0.729$

$=\mathrm{Rs.}\space2,91,600$

So,

$\text{C}$ is the correct option.

A shopkeeper purchases 60

$\mathrm { kg }$ of acommodity at the rate of Rs. 5 per kg and 150 kg of the same commodity at the rate of Rs.6 per kg. He mixes the two and sells the mixture at the rate of

$7$ Rs-per kg. What is the overall gain?

0%
Rs.360
0%
Rs.270
0%
Rs.180
0%
None of these

Explanation

The cost of $60Kg$ commodity is $5\times 60=300Rs.$

The cost of $150$ Kg commodity is $6\times 150=900Rs.$

The overall cost is $300+900=1200$

The total selling price is $210\times 7=1470$

The net profit is $1470-1200=270$

If a quarter kg of potato costs

$60$ paise, how many paise does

$200$ gm cost?

0%
$65$
0%
$70$
0%
$52$
0%
$48$

Explanation

Given,

Let the Required cost be

$x$ paise.

Therefore,

$250 : 200 :: 60 : x$

$\Rightarrow (250 \times x) = (200 \times 60)$

$\Rightarrow x= 48$

$120\%$ of

$45$

0%
$45$
0%
$54$
0%
$34$
0%
$43$

Explanation

Given,

$120\%$ of

$45$

$=\dfrac{120}{100} \times 45$

$=\dfrac{12}{2} \times 9$

$=6 \times 9$

$=54$

A shopkeeper sells an article at loss of

$12\dfrac{1}{2}\%$ . Had he sold it for Rs.

$51.80$ more than he would have earned profit of

$6\%$ . The cost price of the article is?

0%
Rs. $280$
0%
Rs. $300$
0%
Rs. $380$
0%
Rs. $400$

A merchant sold an item for

$\text{Rs. } 1200$ to earn a profit of

$50\%$ over its cost price. what could the cost price be?

0%
$\text{Rs } 55$
0%
$\text{Rs }607$
0%
$\text{Rs }800$
0%
$\text{Rs }1809$

Explanation

$\Rightarrow$ The selling price of an item

$=Rs.1200$

$\Rightarrow$ Profit

$=50\%$

Let the cost price be

$Rs.x$

$\Rightarrow$ Profit

$=x\times\dfrac{50}{100}=\dfrac{x}{2}$

$\Rightarrow$ Selling price of an item

$=x+\dfrac{x}{2}=\dfrac{3x}{2}$

$[\because$ selling price

$=$ cost price

$+$ profit

$]$

Now,

$\Rightarrow$

$\dfrac{3x}{2}=1200$

$\Rightarrow$

$3x=2400$

$\Rightarrow$

$x=800$

$\Rightarrow$ The required cost price is

$Rs.800$

By selling a chair for Rs.572, a man gains 30%. The cost price of the chair is

0%
Rs.34.
0%
Rs.400
0%
Rs.440
0%
None of these

The population of a country is

$10$ crore and it is the possibility that the population will become

$13.31$ crore in

$3$ years. What will be the annual rate per cent of this growth?

0%
$8 \%$
0%
$12.7 \%$
0%
$10 \%$
0%
$15 \%$

Find the

$S.P.$ of a T set shoes with marked price=

$Rs.17940$ and the discount offered on it is

$8%$ ?

0%
$Rs.16504.80$
0%
$Rs.16000.40$
0%
$Rs.20888.40$
0%
$Rs.10580.44$

A reduction of 20% in the price of onions enables a purchaser to obtain 8 kg more Rs 80.What is the reduced price per kg? What was the price per kg before reduction?

0%
Rs 1.50 Rs 2
0%
Rs 2, Rs 2.50
0%
Rs 3, Rs 2.50
0%
Rs1, Rs2.50

The present population of a city is 3,02,If the population increases by 10% every year, what was the population of the city two years ago?

0%
$2,80,000$
0%
$2,75,000$
0%
$2,48,000$
0%
$2,50,000$

Explanation

Let the population before two years ago be

$x$

Given the population increases by

$10\%$

So increase in population after one year is

$\dfrac{10}{100}\times x=0.1 x$

So population after one year is

$x+0.1 x=1.1 x$

Increase in population after another one year is

$\dfrac{10}{100} \times 1.1 x=0.11 x$

So population at present is

$1.1 x+0.11 x=1.21 x$

But given population at present is

$3,02,500$

$\implies 1.21 x=302500$

$\implies x=\dfrac{302500}{1.21}=2,50,000$

Population of city two years ago is

$2,50,000$

A man buys a TV at Rs. 18200. He spends Rs. 1800 on repairing of TV. If he want Rs. 3000 as profit. What is the selling price of TV?

0%
Rs. 20430
0%
Rs. 21200
0%
Rs. 23000
0%
Rs. 25200

On selling a wristwatch for Rs 1100 there is some loss. If the same wristwatch is sold for Rs 1600, the profit is equal to the loss. Find the cost price of the wristwatch.

0%
Rs. 1400
0%
Rs. 1350
0%
Rs.1300
0%
Rs.1450

An item sold at

$Rs. 435$ would incur a loss equal to

$Rs. 10$ less than the profit if it sold at

$Rs. 475$ . Find the cost price

0%
$Rs. 450$
0%
$Rs. 445$
0%
$Rs. 465$
0%
None of the above

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 10 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 10 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

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