MCQ Questions for Class 8 Maths Comparing Quantities Quiz 3

A shopkeeper buys

$x$ kg sugar for Rs.

$y$ and sells it at Rs.

$z$ per kg. Then expression for his profit can be represented by:

0%
Profit = $x - y + z$
0%
$y - zx$
0%
$x - zy$
0%
$zx - y$

Explanation

Amount he sells

$x$ kg of sugar = Rs.

$z$ per kg.

$\therefore S.P = Rs. zx$ and

$C.P = Rs. y$

$\therefore Profit = zx - y$

A shopkeeper offers 2.5% discount on cash purchases. What cash amount would Rohan pay for a cycle, the marked price of which is Rs 650?

0%
Rs 685.27
0%
Rs 633.75
0%
Rs 612.22
0%
Rs 589.33

Explanation

M.P=Rs. 650

Discount=2.5%

S.P

$=650-2.5\% of 650$

$\Rightarrow 650-\frac{2.5}{100}\times 650$

$\Rightarrow 650-16.25=Rs.633.75$

A man buys

$m$ articles at Rs.

$x$ each and another

$n$ articles for Rs.

$y$ . If he sells all the articles at Rs.

$z$ per article, frame an equation to find his profit

0%
$(mx + n) z - (mx + y)$
0%
$(m + n) zx - (mx + y)$
0%
$(m + n) z - (mx +n y)$
0%
$(mn + x) z - (mx + y)$

Explanation

Cost price for a article is Rs

$x$
Cost price of

$m$ articles is Rs

$mx$ .
Cost price of another articles is Rs

$y$
Cost price of

$n$ another articles is Rs

$ny$
Total cost price

$=$ Rs

$mx +ny$
Selling price of a article is Rs

$z$
Therefore Selling Price for

$(m+n)$ articles

$=$

$z(m+n)$
Profit

$=$ Selling price

$-$ Cost price
Profit

$= z(m+n) - (mx + ny)\\$

The marked price of a dining table is Rs. 23,600 and is available at a discount of 8%. Find its selling price.

0%
Rs. 21,612
0%
Rs. 21,710
0%
Rs 21,610
0%
Rs 21,712

Explanation

Marked Price of a dinning table is Rs

$23600$
Discount=

$8$ %
Selling Price=Marked Price-Discount

$=23600-\cfrac { 8 }{ 100 } \times 23600$

$=$ Rs

$21712$

The selling price of a pen is

$Rs.\ 13.20$ if it is sold at

$12\%$ discount.

Find the new selling price of the pen, if it is sold at

$5\%$ discount.

0%
$Rs.\ 12.11$
0%
$Rs.\ 14.25$
0%
$Rs.\ 15.33$
0%
$Rs.\ 16.26$

Explanation

Let the marked price of the pen be

$x.$

For the case when discount is

$12\%,$

$SP$ is

$Rs.\ 13.20$ . Then,

$\begin{aligned}{}13.20 &= x\left( {1 - \frac{{12}}{{100}}} \right)\\13.20& = x \times \frac{{88}}{{100}}\\x &= \frac{{13.20 \times 100}}{{88}}\\& = Rs.\ 15\end{aligned}$

For the case when the discount is

$5\%,$

$SP$ will be,

$\begin{aligned}{}SP& = 15\left( {1 - \frac{5}{{100}}} \right)\\ &= 15 \times \frac{{95}}{{100}}\\ &= Rs.\ 14.25\end{aligned}$

Hence, option

$B$ is correct.

A shopkeeper buys an article for Rs.

$450$ . He marks it at

$20\%$ above the cost price. Find the marked price of the article.

0%
Rs.426
0%
Rs.540
0%
Rs.632
0%
Rs.720

Explanation

Marked price will be

$= C.P. + 20$

$\%$ of

$C.P.$

$= \dfrac {120}{100} \times C.P.$

$= \dfrac {120}{100} \times 450$

$=$ Rs.

$540$

An articles marked for Rs.

$1,300$ and is sold for Rs.

$1,144$ ; find the discount percent.

0%
$9\%$
0%
$11\%$
0%
$12\%$
0%
$15\%$

Explanation

Discount

$\%$

$=\dfrac { Marked Price - Selling Price }{Marked Price } \times 100$

$= \dfrac {1,300 - 1,144}{1,300} \times 100$

$= \dfrac {156}{1,300} \times 100 = 12$

$\%$

The list price of an article is Rs. 800 and is available at a discount of 15 percent. Find the selling price of the article.

0%
Rs. 500
0%
Rs. 680
0%
Rs. 763
0%
None of these

Explanation

Discount

$= 15$ % of Marked Price

$= \dfrac {15}{100} \times 800$

$= Rs\ 120$

Selling price

$=$ Marked Price

$-$ Discount

$= Rs\ 800 - Rs\ 120$

$= Rs\ 680$

A shopkeeper buys an article for Rs.

$450$ . He marks it at

$20\%$ above the cost price. The percentage discount given by him, if he sells the article for Rs.

$496.80$ , is:

0%
$8\%$
0%
$12\%$
0%
$16\%$
0%
$20\%$

Explanation

According to the information given, Marked price will be

$= C.P. + 20$

$\%$ of

$C.P.$

$= \dfrac {120}{100} \times C.P.$

$= \dfrac {120}{100} \times 450$

$=$ Rs.

$540$

Discount

$\%$

$=\dfrac { Marked Price - Selling Price }{Marked Price } \times 100$

$= \dfrac {540 - 496.80}{540} \times 100$

$= \dfrac {43.2}{540} \times 100$

$=8$

$\%$

A wrist-watch is available at a discount of

$9\%$ . If the list-price of the watch is Rs.

$1,400$ ; find the discount given and the selling price of the watch.

0%
Rs. $112$ and Rs. $1,624$
0%
Rs. $126$ and Rs. $1,274$
0%
Rs. $102$ and Rs. $936$
0%
Rs. $40$ and Rs. $113$

Explanation

Given: Discount:

$9\%$

Discount given on the Marked Price

$= \dfrac {9}{100} \times 1,400$

$=Rs.126$

But discount

$\% =\dfrac { Marked\ \ Price - Selling\ \ Price }{Marked\ \ Price } \times 100$

$\Rightarrow \dfrac {1,400 - S.P}{1,400} \times 100 = 9$

$\Rightarrow 1,400 - S.P. = 126$

$\Rightarrow S.P. =Rs. 1274$

A shopkeeper buys an article for Rs.

$450$ . He marks it at

$20\%$ above the cost price. The selling price, if he sells the article at 10% discount, is:

0%
Rs. $263$
0%
Rs. $325$
0%
Rs. $400$
0%
Rs. $486$

Explanation

Marked price will be

$= C.P. + 20$ % of

$C.P. = \dfrac {120}{100} \times C.P. = \dfrac {120}{100} \times 450 =Rs 540$
And Discount

$= 10$ % of Marked Price

$= \dfrac {10}{100} \times 540 = Rs 54$
And Selling price

$=$ Marked Price

$-$ Discount

$= Rs 540 - Rs 54 = Rs 486$

The value of a machine depreciated by

$10 \%$ per year during the first two years and

$15 \%$ per year during the third year. Express the total depreciation of the machine, as per cent, during the three years.

0%
$43.21 \%$
0%
$31.15 \%$
0%
$23.14 \%$
0%
$18.34 \%$

Explanation

Lets Price of article is

$100$
Dep value after

$1$ year

$=100-\dfrac{100\times10}{100}$ =

$90$

Dep. value after

$2$ year

$=90- \cfrac{90\times 10}{100}= 81$
Dep. value after

$3$ years

$=81-\cfrac{81\times 15}{100}= 68.85$
Total Dep.

$=100-68.85$ =

$31.15 \%$

An article costs Rs.

$1,050$ to a manufacturer who lists its price at Rs.

$1,200$ . He sells it to a trader at a discount of

$5\%$ . The trader gets a further discount of

$5\%$ for cash payment. Calculate the profit percent that the manufacturer makes on the sale.

0%
$\displaystyle 3\frac{1}{7}\%$
0%
$\displaystyle 3\frac{1}{8}\%$
0%
$\displaystyle 2\frac{1}{7}\%$
0%
none of these

Explanation

An article costs Rs.

$1,050$ to a manufacturer who lists its price at Rs.

$1,200$
Manufacturer give

$5 \%$ discount on sell, so selling price

$=$

$1200-1200\left ( \dfrac{5}{100} \right )= 1140$
he gave other

$5 \%$ discount on cash sell.
So, selling price after cash sell

$=$

$1140-1140\left ( \dfrac{5}{100} \right )= 1083$
Profit

$=1083-1050=33$

$\%$ of profit

$=$

$\dfrac{33\times 100}{1050}$ =

$3\dfrac{1}{7}$

$\%$

A pair of articles was bought for : Rs.37.40 at a discount of 15%. What must be the marked price of each of the articles?

0%
Rs. $11$
0%
Rs. $22$
0%
Rs. $33$
0%
Rs. $44$

Explanation

S.P. of each article = Rs.

$\displaystyle\frac{37.40}{2}$
= Rs. 18.70.
Let M.P. be Rs. x.
Then, 85% of x = 18.70

$\Rightarrow\, x\, =\, \left ( \displaystyle \frac{18.70\, \times\, 100}{85} \right )\, =\, 22$

A shopkeeper marks the price of an article at Rs.

$800$ . Find the selling price, if he allows three successive discounts of

$10 \%$ ,

$5 \%$ and

$3 \%$ .

0%
Rs. $663.48$
0%
Rs. $623.48$
0%
Rs. $563.86$
0%
none of these

Explanation

M.P = $800$ Rs (given)
First Dis.= $10$ %
S.P. after first dis.= $800-(800\times\dfrac{10}{100})$ = $720$ Rs
Second Dis.= $5$ %
S.P. after second Dis.= $720-(720\times\dfrac{5}{100})$ = $684$ Rs
Third Dis.= $3$ %
S.P. after third Dis.= $684-(684\times\dfrac{3}{100})$ = $663.48$ Rs
S.P. is Rs $663.48$

A retailer marks his goods at a price that he would get a profit of

$40\%$ . He sold

$40\%$ of the goods at this price, half of the remainings at a discounts of

$20\%$ each. Find his loss percent or profit percent on the whole.

0%
$16.6\%$ profit
0%
$16.6\%$ loss
0%
$19.6\%$ profit
0%
$19.6\%$ loss

Explanation

Lets assume that retailer bought

$\mbox{ 100 goods @ Rs 100 each}$
He wants

$40$ % profit, then marked price

$=$

$100+ 40 = Rs 140$ each
He sold

$40\%$ goods on M.P

$=$

$40\times140 = Rs. 5600$
Half of remaining at

$20\%$ discount, then S.P

$=$

$\dfrac{140\times 80\times 30}{100}= Rs\ 3360$
Total price

$= 5600 + 3360 + 3000 = Rs. 11960$
Profit

$=11960-10000=Rs\ 1960$

$\%$ of profit

$=$

$\dfrac{1960\times 100}{10000}= 19.60$ %

Study the information given below and answer the question.

An article was purchased for Rs 5,Its price was marked up by 12%. It was sold at 5% discount on the marked price. What was the amount of discount given?

0%
Rs 319.6
0%
Rs 303.6
0%
Rs 306.3
0%
Rs 313.6

Explanation

$CP=Rs.5,600$

$MP= 5600+\dfrac{12} {100} 5600$

$MP=112\%\times 5600=Rs.6272$

Discount

$=5\%\times 6272=Rs.313.6$

A man sold an article at a loss of

$20 \%$ . If he had sold it for Rs.

$12$ more, then he would have gained

$10\%$ . The cost price of the article is

0%
Rs. $60$
0%
Rs. $40$
0%
Rs. $30$
0%
Rs. $22$

Explanation

Assume the cost of article is

$x$
the person sold at

$20\%$ loss

$Loss$

$\%$

$= \dfrac{C.P-S.P}{C.P}= \dfrac{x-S.P}{x}= \dfrac{20}{100}$

$\therefore$

$S.P$

$= 0.8$

$x$
If he had sold it for Rs.

$12$ more, then he would have gained

$10\%$ .

$Gain$

$\%$

$= \dfrac{S.P-C.P}{C.P}= \dfrac{(0.8x+12)-x}{x}= \dfrac{10}{100}$

$\therefore 12-0.2x=0.1x$

$\therefore 12=0.3x$

$\therefore x=40$

A man buys pencils at the rate of

$6$ for Rs.

$5$ and sells them at

$5$ for Rs.

$6$ . What is his profit

$\%$ ?

0%
$30$
0%
$35$
0%
$40$
0%
$44$

Explanation

C.P. of

$1$ pencil

$=$ Rs.

$\dfrac {5}{6}$
S.P. of 1 pencil

$=$ Rs.

$\dfrac {6}{5}$

$\therefore$ Profit

$=$ S.P.

$-$ C.P.

$=$ Rs.

$\left ( \dfrac {6}{5}-\dfrac {5}{6} \right )=\dfrac {36-25}{30}=$ Rs.

$\dfrac {11}{30}$

$\therefore$ Profit

$\% =$

$\left (\dfrac {11/30}{5/6}\times 100 \right )$

$\%$

$=\left (\dfrac {11}{30}\times \dfrac {6}{5}\times 100 \right )$

$\%=44\%$

An article was purchased for

$\text{Rs }5,600$ . Its price was marked up by

$12\%.$ It was sold at a

$5\%$ discount on the marked price. The marked price of the article will be :

0%
$\text{Rs }6,207$
0%
$\text{Rs }6,242$
0%
$\text{Rs }6,292$
0%
$\text{Rs }6,272$

Explanation

Bought price is

$Rs.\ 5600$

Marked price is

$12\%$ more than purchased price.

Discount

$= 5 \%$

Hence,

Marked price

$=5600+\dfrac{12}{100}\times 5600=5600+672=Rs.\ 6272$

Which of the following comes under indirect tax?

0%
Wealth Tax
0%
House Tax
0%
Sales Tax
0%
All of these

By selling a transistor for

$Rs. \ 572$ , a shopkeeper earns a profit equivalent to

$30 \%$ of the cost price of the transistor. What is the cost price of the transistor?

0%
$Rs. 340$
0%
$Rs. 300$
0%
$Rs. 400$
0%
$Rs. 440$

Explanation

Let the C.P be Rs.

$100$

Profit

$=30\%$ of

$100$

$=\dfrac{30}{100}\times 100=$ Rs.

$30$

Then S.P

$=100+30=$ Rs.

$130$

if S.P is

$130$ , then C.P

$=$ Rs.

$100$

If S.P is

$572$ , then C.P

$=\dfrac{100}{130}\times 572=$ Rs.

$440$

An item costing Rs.

$840$ was sold by a shopkeeper at a gain of

$10 \%$ and it was again sold by the new buyer at a loss of

$5 \%$ .The final selling price of the item is:

0%
Rs. $877.80$
0%
Rs. $798$
0%
Rs. $924$
0%
Rs. $37.80$

Explanation

$C.P.$ $=$ Rs. $840$

$Gain$ $=10\%$

$S.P.$ $=\dfrac{100+\text {gain percentage}}{100}\times$ $C.P$

$S.P.$ $=\dfrac{100+10}{100}\times 840$

$\Rightarrow \dfrac{110}{100}\times 840=$ Rs. $924$

Selling price of the shopkeeper is the cost price of the new buyer.

Then $C.P.$ $=$ Rs. $924$

$Loss$ $=5\%$

$S.P.$ $=\dfrac{100-\text {loss percentage}}{100}\times$ $C.P.$

$S.P$ $=\dfrac{100-5}{100}\times 924$

$\Rightarrow \dfrac{95}{100}\times 924=$ Rs. $877.80$

Hence, final $S.P.$ =Rs. $877.80$

Find the compound interest by using simple interest approach for Rs 5000 for 3 years at 8% per annum compounded annnually.

0%
$1298.56$
0%
$1289.00$
0%
$1.200.89$
0%
None of these

A greedy businessman cheats both the seller and buyer by

$20\%$ . His real profit is:

0%
$43\%$
0%
$45\%$
0%
$44\%$
0%
$40\%$

Explanation

Let actual printed

$C.P. = Rs.125$
Price paid by the business man =

$80\% ~of~ 125$
Profit for him at the time of buying

$20\% ~of~ 125 = Rs. 25$
S.P. of the businessman =

$120\% ~of~ Rs.125$
Profit for him at the time of selling

$20\% ~of~ 125 = Rs.25$
Total profit

$=Rs.50$

$\therefore$ profit %

$= \dfrac{50}{125} \times 100 = 40\%$

The profit earned after selling an article for Rs.

$625$ is the same as loss incurred after selling the article for Rs.

$435$ . What is the cost price of the article?

0%
Rs $530$
0%
Rs $520$
0%
Rs $540$
0%
Rs $550$

Explanation

Let the

$C.P.$ =Rs

$x$

Then according to the question

$625-x=x-435$

$2x=625+435$

$2x=1060$

$x=530$

Hence

$C.P.$ of the article =Rs.

$530$

A trader gains

$15\%$ after selling an item at

$10\%$ discount on the printed price. The ratio of the cost price and the printed price is

0%
$18 : 23$
0%
$17 : 18$
0%
$17 : 23$
0%
$18 : 25$

Explanation

Let the printed price of item be Rs. $100$ .

After discount of $10\%$ SP $=$ Rs. $90$ profit earned $= 15\%$
C.P of item $= \dfrac{100}{115}\times 90 = \dfrac{1800}{23}$
Hence, CP : Printed Price $= \dfrac{1800}{23}:100 = 18:23$

A car worth Rs.

$\ 1,50,000$ was sold by

$X$ to

$Y$ at

$5 \%$ profit.

$Y$ sold the car back to

$X$ at

$20 \%$ loss. Therefore who gained in the entire transaction?

0%
$X$ gained Rs. $31500$
0%
$X$ lost Rs. $43500$
0%
$X$ gained Rs. $3150$
0%
$X$ lost Rs. $315000$

Explanation

The cost price of car for

$X=$ Rs.

$150000$

Then selling price to

$X$ at

$5\%$ profit

$=$ cost price of car to

$y$

$=$

$\dfrac{150000\times 105}{100}=$ Rs.

$157500$

But

$Y$ sell car to

$X$ at

$20\%$ loss

Then selling price of car to

$Y$

$=$ cost price of car

$x$ back

$=$

$\dfrac{157500\times 80}{100}=$ Rs.

$126000$

Then Profit to

$X$ in the entire transaction

$=157500-126000=$ Rs.

$31500$ .

John bought a car for a certain sum of money. He spent

$10 \%$ of the cost on repairs and sold the car for a profit of Rs.

$11000$ . How much did he spend on repairs, if he made a profit of

$20 \%$ ?

0%
Rs. $4000$
0%
Rs. $4400$
0%
Rs. $5000$
0%
Rs. $5500$

Explanation

Let C.P

$=$ Rs.

$x$ .

Then, cost on repairs

$= 10\%$ of

$x =$

$\dfrac {x}{10}$

$\therefore$ Total cost

$=$

$x+\dfrac {x}{10}=\dfrac {11x}{10}$
Now

$20\%$ of

$\dfrac {11x}{10}=11000$

$\Rightarrow \dfrac {20}{100}\times \dfrac {11x}{10}=11000\Rightarrow x=50,000$

$\therefore$ Expenditure on repairs

$=10\%$ of C.P.

$= 10$

$\%$ of Rs.

$50,000$

$=\dfrac{10}{100}\times 50,000=$ Rs.

$5000.$

A man wanted to sell on article with

$20 \%$ profit; but he actually sold at

$20 \%$ loss for Rs.

$480$ . At what price did he want to sell it to earn the profit.

0%
Rs. $720$
0%
Rs. $840$
0%
Rs. $600$
0%
Rs. $750$

Explanation

Let the C.P. of the article be Rs. $x$ .

Then, S.P. $=$ Rs. $\dfrac {x\times (100-20)}{100}$

$\Rightarrow 480=\dfrac {x\times 80}{100}$

$\Rightarrow x=\dfrac{480\times 100}{80}$
$\Rightarrow x=$ Rs. $600$
$\therefore$ S.P. at $20 \%$ profit $=$ Rs. $\dfrac {600\times (100+20)}{100}$
$=\dfrac {600\times 120}{ 100 }=$ Rs. $720$

A man sold a watch for Rs.

$600$ at a loss. Had he sold if for Rs.

$750$ , his gain would have been double the former loss. The cost price of the watch is.

0%
Rs. $800$
0%
Rs. $700$
0%
Rs. $670$
0%
Rs. $650$

Explanation

Let the cost price of watch is Rs.

$x$

Then loss

$=$ Rs.

$x-600$

If watch sold Rs.

$750$ , then profit

$=$ Rs.

$750-x$

Given gain has been double the loss

Then

$750-x=2(x-600)$

$\Rightarrow 750-x=2x-1200$

$\Rightarrow x=650$

Therefore, the cost price of the watch is Rs.

$650$ .

A man bought a second hand car for Rs.

$76000$ and a TV, for Rs.

$27500$ . He sold the car at a gain of

$15\%$ and the T.V. at a loss of

$12\%$ . Find the total amount gained or lost from the two transactions.

0%
lost Rs. $1800$
0%
gained Rs. $1800$
0%
gained Rs. $8100$
0%
lost Rs. $8100$

Explanation

Total

$C.P.$ of Car and TV

$76000 + 27500 = 103500$
Car he sold on

$15\%$ profit , so

$S.P.$ of Car

$= 76000 + 76000 \times \dfrac{15}{100} = 76000+11400 = 87400$
TV he sold on

$12\%$ loss,

$S.P.$ of TV

$= 27500 - 27500 \times \dfrac{12}{100} = 27500 - 3300 = 24200$
Total Salling price

$= 87400 + 24200 = 111600$

$Gain = SP - CP$

$= 111600 - 103500 = 8100$

Find the S.P. of a TV set whose marked price is Rs.

$17940$ and the discount offered on it is

$8\%$ ?

0%
Rs. $17596.80$
0%
Rs. $16504.80$
0%
Rs. $16426.80$
0%
Rs. $16213.80$

Explanation

Given, M.P. $=$ Rs. $17940$ , Discount $=8\%$

S.P. $=$ M.P. $-$ Discount

S.P $=17940-8\%$ of M.P.

$\Rightarrow 17940-\dfrac{8}{100}\times 17940$

$\Rightarrow 17940-1435.20=$ Rs. $16504.80$

Richa purchased an article at

$\displaystyle \frac{4}{5}$ of its list price and sold it for

$20 \%$ more than the list price. Richa's profit per cent was

0%
$50 \%$
0%
$40 \%$
0%
$30 \%$
0%
$25 \%$

Explanation

Let list price of article be Rs.

$100$

$\therefore$ Cost Price

$= \dfrac{4}{5} \times 100 =$ Rs.

$80$

$\therefore$ Selling Price

$= \dfrac{120}{100} \times 100 =$ Rs.

$120$

$\Rightarrow$ Profit

$= 120-80 =$ Rs.

$40$

$\therefore$ Profit

$\%$

$= \dfrac{Profit}{C.P.} \times 100$

$= \dfrac{40}{80}\times 100 = 50\%$

The ratio between the sale price and cost price of an article is

$7: 5$ . What is the ratio between the profit and the cost price of that article ?

0%
$2:7$
0%
$5:2$
0%
$7:2$
0%
$2:5$

Explanation

The ratio between the sale price and cost price of an article is

$7x: 5x.$

Then the profit becomes

$7x - 5x$ which is

$2x$ .

So, the ratio between profit and cost price is

$2x : 5x$ or

$2 : 5$ .

A trader purchased an old bicycle for Rs.

$480$ . He spent

$20 \%$ of the cost on its repair. If he wants to earn Rs.

$144$ as net profit on it, find profit

$\%$ .

0%
$50\%$
0%
$48\%$
0%
$96\%$
0%
$100\%$

Explanation

Cost price

$=$ Rs.

$480$
Repair cost

$= 20\%$ of Rs.

$480$

$=\dfrac{20}{100}\times 480=$ Rs.

$96$

$\therefore$ Total cost

$=$ C.P.

$+$ Repair cost

$\Rightarrow$ Rs.

$480 +$ Rs.

$96 =$ Rs.

$576$
Net profit

$=$ Rs.

$144$

$\therefore$ S.P. = Total cost + Net profit

$\Rightarrow$ Rs.

$576 +$ Rs.

$144 =$ Rs.

$720$

Profit

$=$ S.P.

$-$ C.P.

$=720-480=$ Rs.

$240$
Now profit

$\% =$

$=\dfrac {240}{480}\times$

$100 =50\%$

A shopkeeper marks his goods

$20$

$\%$ higher-than the cost price and allows a discount of

$5$

$\%$ . What is the percentage of his profit?

0%
$14$ $\%$
0%
$7$ $\%$
0%
$9$ $\%$
0%
$11$ $\%$

Explanation

Let the C.P. of the article $=$ Rs. $100$ .
Then, M.P. of the article $=$ Rs. $100 +$ Rs. $20 =$ Rs. $120$
Rate of Discount $= 5\%$
$\therefore$ Discount offered $= 5\%$ of M.P. $=\dfrac {5}{100}\times$ Rs. $120=$ Rs. $6$
$\therefore$ S.P. $=$ M.P. $-$ Discount $=$ Rs. $120 -$ Rs. $6 =$ Rs. $114$

$\text {Profit} =$ S.P. $-$ CP. $=$ Rs. $114 -$ Rs. $100 =$ Rs. $14$
Profit $\%=$ $\dfrac {14}{100}\times100$ = $14 \%$

A shopkeeper earns

$15$ % profit on a shirt even after allowing

$31$ % discount on the list price. If the list price is Rs.

$125$ , then what is the cost price of the shirt?

0%
Rs. $65$
0%
Rs. $70$
0%
Rs. $75$
0%
Rs. $80$

Explanation

Discount on the shirt

$=31\%$ of Rs.

$125$

$=$ Rs.

$\dfrac {31}{100}\times 125$

$=$ Rs.

$\dfrac {155}{4}$

Therefore, S.P. of the shirt

$=125-\dfrac {155}{4}$

$=$ Rs.

$\dfrac {345}{4}$

Therefore, C.P. of the shirt

$=\dfrac {345}{4}\times \dfrac {100}{115}$

$=$ Rs.

$75$

Thus, the cost price of the shirt is Rs.

$75$ .

Find the rate of discount when M.P.

$=$ Rs.

$975$ and S.P.

$=$ Rs.

$650$ .

0%
$33\dfrac {1}{3}\%$
0%
$33\dfrac {2}{3}\%$
0%
$33\dfrac {4}{3}\%$
0%
$33\dfrac {5}{3}\%$

Explanation

Discount

$=$ M.P.

$-$ S.P.

$=$ Rs.

$975 -$ Rs.

$650 =$ Rs.

$325$

$\therefore$ Discount

$\% =$

$\left ( \dfrac {\text{Discount }}{\text{M.P.}}\times 100 \right )\%$

$=\left ( \dfrac {325}{975}\times 100 \right )\%$

$=\dfrac {100}{3}$

$\%=$

$33\dfrac {1}{3}\%$

A shopkeeper allows a discount of

$10 \%$ on a watch whose marked price is Rs.

$3400$ and in the process makes a gain of Rs.

$220$ . What is the cost price of the watch?

0%
Rs. $2340$
0%
Rs. $2540$
0%
Rs. $2840$
0%
Rs. $2440$

Explanation

S.P. of the watch

$=\dfrac {3400\times (100-10)}{100}=$ Rs.

$3060$ .

Gain

$=$ Rs.

$220$

Therefore, C.P. of the watch

$=$ Rs.

$(3060-220)=2840$ .

Hence. option C is the correct answer.

The cost price of an article is

$64\%$ of the marked price. Calculate the gain per cent after allowing a discount of

$12\%$ .

0%
$52\%$
0%
$48\%$
0%
$50.5\%$
0%
$37.5\%$

Explanation

Let the marked price be Rs.

$100$ .

Then, C.P.

$=$ Rs.

$64$

and S.P. is

$=$ Rs.

$88$ .

Therefore, gain

$\%$

$=\dfrac {24}{64}\times 100=37.5\%$

The cost of a shirt after

$15 \%$ discount is Rs.

$\ 102$ . What is the cost of the shirt before discount?

0%
Rs. $\ 115$
0%
Rs. $\ 117$
0%
Rs. $\ 120$
0%
Rs. $\ 125$

Explanation

Let CP of the shirt be Rs.

$x$

Then after discount the price will be Rs.

$0.85x$

Equating

$0.85x = 102$ , we get

$x =$

$\dfrac{102}{0.85}$ = Rs.

$120$

Hence, the cost of the shirt before discount is Rs.

$120$ .

The marked price of a pen is Rs.

$60$ .After allowing a discount of

$10 \%$ , the merchant makes a profit of

$20 \%$ . What is the cost price of the pen?

0%
Rs. $40$
0%
Rs. $\ 45$
0%
Rs. $60$
0%
Rs. $80$

Explanation

Let the cost price of a pen Rs.

$100$

The marchant make profit

$20\%$ , then selling price

$=$ Rs.

$100+20=120$

Marked price Rs.

$60$ . Allowing discount

$10\%$ then selling price

$=$

$\dfrac{60\times 90}{100}=54$ Rs

So, cost price

$=$

$\dfrac{54\times 100}{120}=$ Rs.

$45$

The rate of discount when M.P.

$=$ Rs.

$4500$ and S.P.

$=$ Rs.

$4320$

0%
$6$ $\%$
0%
$10$ $\%$
0%
$4$ $\%$
0%
$8$ $\%$

Explanation

Given, M.P.

$=$ Rs.

$4500$ and S.P.

$=$ Rs.

$4320$

$\text{Rate of discount =} \dfrac{MP-SP}{MP}\times100$

$=\dfrac{4500-4320}{4500}\times100$

$=\dfrac{180}{4500}\times100$

$=4\%$
Hence, option C is correct.

Find the marked price of a pair of shoes which are sold at

$Rs\ 2176$ after allowing an off season discount of

$15 \%$ on them?

0%
$Rs\ 2500$
0%
$Rs \ 2568$
0%
$Rs \ 2560$
0%
$Rs \ 3000$

Explanation

Let the market cost of pair of shoes is Rs

$100$

Then selling price after discount

$15$ %=

$100-15=85$ Rs

But he sell it Rs

$2176$

Then market price=

$\dfrac{2176\times 100}{85}=$ Rs

$2560$

Find the amount actually paid for a mobile phone whose marked price is Rs.

$6600$ and discount offered on it is

$12$ %.

0%
Rs. $5000$
0%
Rs. $5880$
0%
Rs. $5800$
0%
Rs. $5808$

Explanation

Money discounted

$=12\%$ of

$6600$

$=6600\times\dfrac{12}{100}$

$=792$
Actual amount

$=6600-792=5808$
Option D is correct.

A owned an, article worth Rs.

$10, 000$ . He sold it to

$B$ at a profit of

$10\%$ based on the worth of the article.

$B$ sold the article back to

$A$ at a loss of

$10\%$ . How much did

$A$ make in these transactions?

0%
Rs. $1800$
0%
Rs. $1560$
0%
Rs. $1320$
0%
Rs. $1100$

Explanation

C.P of the article for

$A$

$=$ Rs.

$10,000$

Profit

$=10\%$

Selling price of the article by

$A$ to

$B$

$=$ Rs.

$\dfrac {110}{100}\times 10000=$ Rs.

$11000$

C.P of the article for

$B$

$=$ Rs.

$11000$

Loss

$=10\%$
Selling price of the article by

$B$ to

$A$

$=$ Rs.

$\dfrac {90}{100}\times 11000=$ Rs.

$9900$

$\therefore$ Profit earned by

$A$

$=$ Rs.

$(11000-9000)=$ Rs.

$1100$ .

A house wife paid Rs.

$\ 1260$ for a handbag after

$37 \%$ discount. The original price of the handbag was

0%
Rs. $\ 1500$
0%
Rs. $\ 1850$
0%
Rs. $\ 2000$
0%
Rs. $\ 1760$

Explanation

Let

$P$ be the original price.
Then according to question, we have

$1260=P-37\%$ of

$P$

$\Rightarrow 1260=\dfrac{63P}{100}$

$\Rightarrow P=1260\times\dfrac{100}{63}$

$\Rightarrow P=2000$
Thus, original price of the handbag is Rs.

$2000$ .

Ram mixes

$15$ kg of sugar purchased with the rate, off Rs.

$8.00$ per kg with

$25$ kg of sugar purchased at the rate of Rs.

$10.00$ per kg. At what rate per kg should Ram sell the mixture to get a profit of

$3$ per kg?

0%
Rs. $12.25$
0%
Rs. $15.75$
0%
Rs. $18.18$
0%
Rs. $19.75$

Explanation

C.P. of

$40$ kg of sugar

$=$ Rs.

$(15 \times 8 + 25\times 10) =$ Rs.

$120 +$ Rs.

$250 =$ Rs.

$370$

$\therefore$ C.P. of

$1$ kg of sugar

$=$ Rs.

$\dfrac {370}{40}=$ Rs.

$9.25$

$\therefore$ S.P. of

$1$ kg of sugar

$=$ Rs.

$9.25+$ Rs.

$3=$ Rs.

$12.25$

A shopkeeper sells an article at a loss of

$12\dfrac {1}{2}\%$ , Had he sold it for Rs.

$51.80$ more than he would have earned a profit of

$6\%$ . The cost price of the article is

0%
Rs. $280$
0%
Rs. $300$
0%
Rs. $380$
0%
Rs. $400$

Explanation

Let the C.P. of the article be Rs.

$x$

According to the question, we have
S.P. at

$6\%$ profit

$-$ S.P. at

$12\dfrac {1}{2}\%$ loss

$=$ Rs.

$51.80$

$\Rightarrow \dfrac {x\times (100+6)}{100}-\dfrac {x\times (100-12.5)}{100}=51.80$

$\Rightarrow \dfrac {106x}{100}-\dfrac {87.5x}{100}=51.80$

$\Rightarrow \dfrac {18.5x}{100}=51.80 \Rightarrow x=\dfrac {51.80\times 100}{18.5}=280$

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 3 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

CBSE Questions for Class 8 Maths Comparing Quantities Quiz 3 - MCQExams.com

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Practice Class 8 Maths Quiz Questions and Answers

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